4．如图半圆的直径ab=4o为圆心c是半圆上不同于ab的任意一点若p为半 径oc上的动点则·的最小值是 a．2 B．0 Sketch Coloring Page

4．如图半圆的直径ab=4o为圆心c是半圆上不同于ab的任意一点若p为半 径oc上的动点则·的最小值是 a．2 B．0 Template

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tomski4．如图半圆的直径ab=4o为圆心c是半圆上不同于ab的任意一点若p为半 径oc上的动点则·的最小值是 a．2 coloring

如图半圆O的直径AB=4与半圆内切的⊙O1与AB切于C设AC=x⊙O1的半径为y则y与x的关系式为 ．题目和参考答案——青夏教育 sketch template

4．如图半圆的直径AB=4O为圆心C是半圆上不同于AB的任意一点若P为半 径OC上的动点则·的最小值是 A．2 B．0 sketch template

4．如图半圆的直径AB=4O为圆心C是半圆上不同于AB的任意一点若P为半 径OC上的动点则·的最小值是 A．2 B．0 sketch template

如图，AB是半圆O的直径，C是半圆O上一点（不与点A、B重合），D是AC的中点，DE⊥ AB于点E，过点C作半圆O的切线，交ED的延长线于 sketch template

如图1，点O是以AB为直径的半圆的圆心，AD与BC均为该半圆的切线，C，D均为直径AB上方的动点，连接CD，且始终满足CD=AD BC sketch template

题目如图已知AB为半圆O的直径P为半圆上的一个动点以OPOB为一组邻边作POBQ连接OQAP设OQAP的中点分别为MN sketch template

如图1，AB是半圆O的直径，C是半圆O上一点，点O′与点O关于直线AC对称，射线AO′交半圆O于点D，弦AC交O′O于点E、交OD于点F．（1 sketch template

已知如图AB是半圆O上的直径E是的中点半径OE交弦BC于点D过点C作⊙O的切线交OE的延长线于点F．BC=8DE=2．Ⅰ求⊙O sketch template

$如图AB是半圆的直径点C是弧AB的中点点E是弧BC的中点连结AEBC交于点F则$frac{EF}{AF}$的值为$frac sketch template$

如图AB为半圆O的直径C为半圆上一点且为半圆的设扇形AOC COB弓形BC的面积分别为则下列结论正确的是 A＜＜ B sketch template

如图，在以点O为圆心的两个同心圆中，大圆的弦AB交小圆于点C、D 已知AB=4，CD=2，圆心O到直线AB的距离为1，则大圆的半径为 ，小圆 sketch template

如图已知AB是⊙O的直径CD是半圆上两点．AB=26AC=101若点D是$widehat{AB}$的中点求AD的长2若点D sketch template

如图，AB是半圆O的直径，点C在半圆上，AB=5，AC=4，D是BC上的一个动点，连接AD．过点C作CE⊥ AD于E，连接BE，则BE的 sketch template

如图AB是半圆O的直径AB=4厘米四边形OPQR是边长为1厘米的正方形则图中阴影部分的面积为214平方厘米．题目和参考答案——青夏 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

如图1， AB 为半圆O的直径，C为 BA 延长线上一点， CD 切半圆于点D， BE⊥CD ，交延长线于点E，交半圆于点F，已知BC sketch template

如图点CD是以AB为直径的半圆O上的三等分点AB=12厘米则图中由弦ACAD和CD围成的阴影部分图形的面积为多�平方厘米题目和 sketch template

如图AB是半圆O的直径点C是⊙O上一点连接ACBC过点O作OD∥AC交BC于点D在OD的延长线上取一点E连接EB使∠OEB=∠ sketch template

如图AB是半圆⊙O的直径 ABC的两边ACBC分别交半圆于DE且E为BC的中点已知∠BAC=50°则∠C= A 55 sketch template

如图半圆O的直径AB=7两弦ABCD相交于点E弦CD=且BD=5则DE等于 A B C D——青夏教育精英家教�—— sketch template

如图AB是半圆O的直径将半圆沿弦BC折叠折叠后的圆弧与AB交于点D再将弧BD沿AB对折后交弦BC于E若E恰好是BC的中点则BC sketch template

已知 ABC是等边三角形以BC为直径的半圆O与边AB相交于点DDE⊥AC垂足为点E．1判断DE与⊙O的位置关系并证明你的结论2 sketch template

如图AB是⊙O的直径点DE是半圆的三等分点AEBD的延长线交于点C若CE=2则图中阴影部分的面积是 A43π 3B sketch template

如图1AB是⊙O的直径直线l交⊙O于CD两点AE⊥直线l垂足为E 1求证AC·AD=AB·AE 2若将直线l�上平移 sketch template

如图以OB为直径的半圆与半圆O交于点PAOCB在同一条直线上作 AD⊥ AB与BP的延长线交于点D若半圆O的半径为2∠D的余弦 sketch template

如图由直径分别为4厘米6厘米和10厘米的三个半圆所组成的图形则图中阴影部分的面积为314 平方厘米．题目和参考答案——青夏教育精英家教�—— sketch template

7．如图已知C是以AB为直径的半圆O上一点CH⊥AB于点H直线AC与过B点的切线相交于点DE为CH中点连接AE并延长交BD于点F sketch template

如图在 ABC中BC=4以点A为圆心2为半径的⊙A与BC相切于点D交AB于E交AC于F点P是⊙A上一点且∠EPF=40°则图 sketch template

如图AB是半圆O的直径点C是⊙O上一点连接ACBC过点O作OD∥AC交BC于点D在OD的延长线上取一点E连接EB使∠OEB=∠ sketch template

如图AB为半圆O的直径弦ADBC相交于点P若CD=3AB=4求tan∠BPD的值——青夏教育精英家教�—— sketch template

如图AB是半圆O的直径点C是⊙O上一点连接ACBC过点O作OD∥AC交BC于点D在OD的延长线上取一点E连接EB使∠OEB=∠ sketch template

如图以⊿ABC的一边AB为直径的半圆与其它两边ACBC的交点分别为DE且 1试判断⊿ABC的形状并说明理由 2已知半圆的 sketch template

百度教育 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

如图AB是半圆的直径O是圆心C是半圆外一点CACB分别交半圆于点DE若 CDE的面积与四边形ABED的面积相等则∠C等于 A sketch template

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