题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Sketch Coloring Page

题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Template

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tomski题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 coloring

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形ABC中∠ACB=90°∠B=50°将此三角形绕点C沿顺时针方�旋转后得到三角形A′B′C若点B′恰好落在线段AB上 sketch template

如图所示在三角形ABC中D为BC的中点AD和BE相交F点已知三角形ABC的面积为42平方厘米求三角形BDF的面积． 题目和参考答案 sketch template

如图在三角形ABC中D为 BC的中点 AF=2BFCE=3AE连接CF交 DE于 P点求EPDP的值． 题目和参考答案——青夏教育 sketch template

百度教育 sketch template

如图在三角形ABC中点DF在边BC上点E在边AB上点G在边AC上∠CDG=∠B∠1 ∠FEA=180°．证明AD∥EF． 题目 sketch template

百度教育 sketch template

如图在钝角三角形ABC中M为AB边的中点MDEC都垂直于BC边．若三角形BDE的面积是3平方厘米则三角形ABC的面积是多� 题目和 sketch template

如图等边三角形ABC中AB=5延长BC至点P使CP=3将 ABC绕点B顺时针旋转a角得到 DBE连接DPEP则当 DPE为 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为百度教育 sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

如图所示三角形DEF平移得到三角形ABC已知∠B=45°∠C=65°AB=2cm则∠DFE=65度DE=2cm． 题目和参考答案 sketch template

百度教育 sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

百度教育 sketch template

百度教育 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

百度教育 sketch template

如图所示在三角形ABC中∠ABC=45°CD⊥AB与点DBE平分∠ABC 且BE⊥AC于点E与CD相交于点FH是BC边的中点 sketch template

在等边三角形ABC中点E在AB上点D在CB的延长线上且ED=EC．试探索以下问题1当点E为AB的中点时如图1确定线段AE与DB sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

百度教育 sketch template

5．如图在Rt ABC中CD是斜边AB上的高则图中的相似三角形共有 3对 D4对提示考�Rt ABC与Rt ACD sketch template

如图在三角形ABC中D为 BC的中点 AF=2BFCE=3AE连接CF交 DE于 P点求EPDP的值． 题目和参考答案——青夏教育 sketch template

百度教育 sketch template

如图所示三角形ABC中点XYZ分别在线段AZBXCY上且YZ=2ZCZX=3XAXY=4YB三角形XYZ的面积等于24求 sketch template

在三角形ABC中∠A=∠B ∠C这是 三角形． 题目和参考答案——青夏教育精英家教�—— sketch template

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