题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Sketch Coloring Page

题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Template

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tomski题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 coloring

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

已知在三角形abc中知识要点北京爱智康 sketch template

百度教育 sketch template

这道解三角形的题目有什么简便方法？ 知乎 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数． 题目和参考答案——青夏 sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

如图在 ABC中AB=AC∠A=36°请你设计三种不同的方法将 ABC分割成三个等腰三角形不要求写出画法不要求证明但是要标出所 sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

百度教育 sketch template

如图．已知点BCD在同一条直线上． ABC和 CDE都是等边三角形BE交AC于FAD交CE于H1求证 BCE≌ ACD2 sketch template

14．如图在 ABC中∠B=90°两直角边AB=5BC=12三角形内有一点P到各边的距离相等求点P到各边的距离——青夏教育精英家教�—— sketch template

如图在三角形ABC中∠ACB=90°∠B=50°将此三角形绕点C沿顺时针方�旋转后得到三角形A′B′C若点B′恰好落在线段AB上 sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

百度教育 sketch template

如图，在 ABC中，AB=4，AC=3，BC=5，DE是BC的垂直平分线，DE分别交BC、AB于点D、E．1求证： ABC为直角三角形． 2求 sketch template

百度教育 sketch template

题目如图点ABC在一条直线上 ABD BCE均为等边三角形连接AE和CDAE分别交CDBD于点MPCD交BE于点Q sketch template

如图在 ABC中点DE分别在边ACAB上BD与CE交于点O给出下列四个条件�∠EBO=∠DCO�BE=CD�OB=OC sketch template

如图等边三角形ABC内接于圆D为上一点则图中 等于60°的角有 A3个 B4个 C5个 D6个——青夏教育精英家教�—— sketch template

如图在三角形ABC中D为 BC的中点 AF=2BFCE=3AE连接CF交 DE于 P点求EPDP的值． 题目和参考答案——青夏教育 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

如图中三角形ABC的面积是平行四边形DBCE面积的 A．一半 B．2倍 C．相等 题目和参考答案——青夏教育精英家教�—— sketch template

百度教育 sketch template

题目如图在平面直角坐标系中点的坐标为以线段为边在第四象限内作等边三角形点为正半轴上一动点 连接以线段为边在第四象限内作等边三角 sketch template

如图等边三角形ABC中AB=5延长BC至点P使CP=3将 ABC绕点B顺时针旋转a角得到 DBE连接DPEP则当 DPE为 sketch template

如图在 ABC中DE∥BC且AD=3DB=2．写出图中的相似三角形并指出其相似比． 题目和参考答案——青夏教育精英家教�—— sketch template

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