如图所示甲图中线圈a的ab两端加上如图乙所示的电压时在时间0 T0内线圈b中感应电流的方�及线圈b的受力方�是 A．感应电流方�不 Sketch Coloring Page

如图所示甲图中线圈a的ab两端加上如图乙所示的电压时在时间0 T0内线圈b中感应电流的方�及线圈b的受力方�是 A．感应电流方�不 Template

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tomski如图所示甲图中线圈a的ab两端加上如图乙所示的电压时在时间0 t0内线圈b中感应电流的方�及线圈b的受力方�是 a．感应电流方�不 coloring

如图所示甲图中线圈A的ab两端加上如图乙所示的电压时在时间0 t0内线圈B中感应电流的方�及线圈B的受力方�是 A．感应电流方�不 sketch template

如图所示甲图中线圈A的ab两端加上如图乙所示的电压时在时间0 t0内线圈B中感应电流的方�及线圈B的受力方�是 A．感应电流方�不 sketch template

如图甲所示线圈AB紧靠在一起当给线圈A通以如图乙所示的电流规定由a进入b流出为电流正方�时则电压表的示数变化情况规定电流由c进入 sketch template

如下图中甲线圈A中通有交变电流图乙是线圈A中的电流随时间的变化图像在线圈A左侧固定放置一个闭合�属圆环B设电流由线圈a端流入从b端 sketch template

如图甲所示线圈AB紧靠在一起当给线圈A通以如图乙所示的电流规定由a进入b流出为电流正方�时则电压表的示数变化情况规定电流由c进入 sketch template

如图所示，将线圈套在长玻璃管上，线圈的两端与电流传高途 sketch template

图甲是小灯泡L和定值电阻R的电流与电压的关系，则R的电阻为Ω，现将它们并联后接在电压为2V的电源两端，如图乙，则干路中的电流是A；若将它们串联 sketch template

如图甲所示两个闭合圆形线圈AB的圆心重合放在同一水平面内线圈A中通以如图乙所示的变化电流t＝0时电流方�为顺时针在t1 T2时间内 sketch template

如图甲所示空间中存在一水平方�的匀强磁场磁感应强度B=05T一矩形线圈绕水平中心轴P匀速转动转动角速度ω=10$sqrt{2 sketch template

如图甲100匝的线圈两端AB与一个阻值R=48Ω的电阻相连其线圈的电阻r=2Ω线圈内有指�纸内方�的磁场线圈中的磁通量在按图乙所示 sketch template

如图所示100匝的线圈为表示线圈的绕�图中只画了2匝两端AB与一个电压表相连线圈内有指�纸内方�的磁场线圈中磁场的磁感应强度在按 sketch template

如图所示是法拉第在1831年做的一个电磁感应实验的示意图．他把两个线圈绕在一个铁环上A 线圈与电源�动变阻器 R 组成一个回路B 线圈与 sketch template

如图甲所示理想变压器原副线圈的匝数比为101b是原线圈的中心抽头图中电表均为理想的交流电表定值电阻R=10Ω其余电阻均不计从某 sketch template

题目如图甲所示圆形线圈位于随时间t变化的匀强磁场中磁感应强度B随时间t的变化规律如图乙所示取磁场垂直纸面�里为正线圈中感应电流i顺 sketch template

如图甲所示是小明“探究电流与电压、电阻的关系”的实验电路图。选用的实验器材是：电源3V、电流表（00 6A）、出卷� sketch template

图甲是小灯泡L1和L2的电流随电压变化的图像。将它们按图乙所示接入电路中，闭合开关S时，小灯泡L1的实际功率为1W。则下面的说法中正确的是 sketch template

2．如图甲所示电阻R的阻值为50Ω在ab间加上图乙所示的正弦交流电交流电表内阻不计则下面说法中正确的是 A．电阻R的功率为 sketch template

如图2所示的电路中电源电压不变开关闭合后若�动变阻器的�片P�右端移动则 A电压表的示数和电流表的示数都增大 B电压表的示数和电流 sketch template

百度教育 sketch template

如图所示甲图中线圈A的ab端加上如图乙所示的电压时在0 t0时间内线圈B中感应电流的方�及线圈B的受力方�情况是 A．感应电流方� sketch template

如图甲所示人的手臂相当于一个杠杆它的支点在O点．请你画出图中铅球对手的作用力F的力臂L如图乙所示重为G的木箱A静止在斜面上请作出木箱 sketch template

如图所示理想变压器原线圈中输入电压U1＝3300V副线圈两端电压U2为220V输出端连有完全相同的两个灯泡L1和L2绕过铁芯的导线所接 sketch template

如图甲的电路中，电源电压保持不变，闭合开关后，�片P由b端移到a端，电流表示数I与电压表示数U的变化关系如图乙，则可判断电源电压是 V，定值 sketch template

如图甲所示的电路中abc是三个完全相同的灯泡已知灯泡的伏安特性曲线如图乙所示已知图线过点闭合电键后流过电源的电流为025A则 sketch template

如图甲所示电路中的小灯泡通电后其两端电压U随所通过的电流I变化的图线如图乙所示P为图线上一点PN为图线的切线PM为U轴的垂线PQ为I轴 sketch template

题目如图甲的电路中电源电压保持不变闭合开关后�片P由b端移到a端电流表示数I与电压表示数U的变化关系如图乙所示则可判断电源电压是 sketch template

如图所示的电路中，电源电压保持不变。闭合开关S后，�片P从b端移动到a端的过程，电压表示数U与电流表示数I的关系图像如图所示。下列说法正确的是（ sketch template

如图甲所示的电路中电源电压恒定不变R2=30Ω通过R1的电流随它两端电压变化关系如图乙所示则下列计算正确的是A．R1的阻值大小是 sketch template

如图所示的电路中电源的电压保持不变R1为定值电阻R2为�动变阻器闭合开关S�片P�右移动时则A．电流表A的示数变大B．电压表V的示 sketch template

有两个电路元件A和B流过元件的电流与其两端电压的关系如图甲所示把它们串联在电路中如图乙所示闭合开关S这时电流表的示数为04A则 sketch template

如图所示，闭合开关后，两个通电螺线管中间的小磁针N极�下指。请你在括号内标出电源的“ ”或“﹣”极，并画出乙通电螺线管的绕线方法。百度教育 sketch template

如图甲所示的电路图中电源电压为12V电阻R1的I U图象如图乙所示．当闭合开关�动变阻器R接入电路的阻值为40Ω时则下列选项正确的是 sketch template

如图所示一环形线圈沿条形磁铁的轴线从磁铁N极的左侧A点运动到磁铁S极的右侧B点AB两点关于磁铁的中心对称则在此过程中穿过环形线圈的 sketch template

如图甲所示的电路中�动变阻器的�片P从a端移到b端定值电阻R1两端的电压随�动变阻器R2阻值变化的图象如图乙所示下列说法中正确的是 sketch template

如图甲所示电路，电源电压恒为6V，�动变阻器R的规格为“25Ω、1A”，电流表量程选择“0∼06A”，电压表量程选择“0∼3V”，小灯泡上标 sketch template

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