7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Sketch Coloring Page

7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Template

Background image: Hide Show

View Larger Image Image Credit: 1010jiajiao.com

please wait, the page is loading...

More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #2144

anonymous

anonymous
sketch #2144

sketch #5062

anonymous

anonymous
sketch #5062

sketch #1122 norooz

anonymous

anonymous
sketch #1122 norooz

sketch #125

Chris Shrimp Lonsdale
sketch #125

sketch #2560

anonymous

anonymous
sketch #2560

sketch #2950 Miss Fortune from League of Legends by Araceli GM

anonymous

anonymous
sketch #2950 Miss Fortune from League of Legends by Araceli GM

sketch #4901 Adventure Time by Louisette Alain

anonymous

anonymous
sketch #4901 Adventure Time by Louisette Alain

sketch #3274

anonymous

anonymous
sketch #3274

sketch #5192

anonymous

anonymous
sketch #5192

sketch #5096

anonymous

anonymous
sketch #5096

sketch #132

anonymous

anonymous
sketch #132

sketch #2899 Snoopy by Rhemzkian Esturco

anonymous

anonymous
sketch #2899 Snoopy by Rhemzkian Esturco

sketch #5224

anonymous

anonymous
sketch #5224

sketch #5225 The Friendship by Annabelle Bourget

anonymous

anonymous
sketch #5225 The Friendship by Annabelle Bourget

sketch #3444 PSY by Melodee Ripepi

anonymous

anonymous
sketch #3444 PSY by Melodee Ripepi

sketch #5051

anonymous

anonymous
sketch #5051

sketch #3296

anonymous

anonymous
sketch #3296

sketch #1249

Laura Agapi Asnicar
sketch #1249

sketch #3643

anonymous

anonymous
sketch #3643

sketch #302

Chrystal Smith
sketch #302

sketch #3950

anonymous

anonymous
sketch #3950

sketch #5027

anonymous

anonymous
sketch #5027

sketch #2813 Stan from South Park by Amer Amimer

Amer Amimer
sketch #2813 Stan from South Park by Amer Amimer

sketch #2460 Zayn Malik of One Direction by sketchmaster

sketchmaster
sketch #2460 Zayn Malik of One Direction by sketchmaster

sketch #2888 Jimi Hendrix by Meen Suksoi

anonymous

anonymous
sketch #2888 Jimi Hendrix by Meen Suksoi

sketch #649

anonymous

anonymous
sketch #649

sketch #4903 Naruto & Kurama by Fatér Szilvia

anonymous

anonymous
sketch #4903 Naruto & Kurama by Fatér Szilvia

sketch #3157 umpa lumpa

anonymous

anonymous
sketch #3157 umpa lumpa

sketch #2070

anonymous

anonymous
sketch #2070

sketch #245 Fishy

Lucy Barnard
sketch #245 Fishy

tomski7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— coloring

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

如图在正方形ABCD中点EF分别是ADBC中点连接EF将矩形CDEF绕着点C逆时针旋转一定角度得到矩形CD′E′F′点E′恰好落 sketch template

【问题情境�（1）如图1，正方形ABCD中，E、F分别是边AB和对角线AC上的点，∠EDF=45°．易证 DBE∽ DCF（不需写出证明过程 sketch template

小明遇到一个问题如图1正方形ABCD中EFGH分别是ABBCCD和DA边上靠�ABCD的n等分点连接AFBGCH sketch template

如图在 ABC中点DEF分别在边ABACBC上且DE∥BCEF∥AB若AD＝2BD则的值为 A B C D sketch template

题目如图AB=4cmAC=BD=3cm．∠CAB=∠DBA=60°点P在线段AB上以1cm/s的速度由点A�点B运动同时点Q在线 sketch template

【方法引领�如图1，点E、F分别是正方形ABCD的BC、CD边上的动点，连接AE、AF和EF，∠EAF=45°．若BE=2，DF=3，求EF的 sketch template

题目如图已知正方形ABCD的边长为6EF分别是ABBC边上的点且∠EDF=45°将 DAE绕点D逆时针旋转90°得到 DCM sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

20．如图点DEF分别在ABBCAC上且DE∥ACEF∥AB下面写出了说明“∠A ∠B ∠C＝180° 的过程请填空因为 sketch template

$如图在 ABC中DE分别是ABBC上的点且DE∥AC若$frac{{S} { BDE}}{{S} DEC}}$=$frac sketch template$

如图菱形ABCD中对角线ACBD相交于点O点E是AB的中点已知AC＝8cmBD＝6cm求OE的长——青夏教育精英家教�—— sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图已知长方体ABCD A1B1C1D1中AB=BC=2AA1=1点EF分别是A1B1B1C1的中点点O是AB与BD的交点．1 sketch template

（1）如图�，在四边形ABCD中，AB=AD，∠B=∠ADC=90°．E、F分别是BC、CD上的点，且EF=BE FD，探究图中∠BAE、∠ sketch template

如图1，D、E、F分别是 ABC各边上的点，四边形ADEF是平行四边形，有三个选项：�D是AB的中点，�E是BC的中点，�F是AC的中点． sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

如图 ABC中点DEF分别在边BCABCA上且DE∥CADF∥BA则�如果∠BAC=90°那么四边形AEDF是矩形�如果 sketch template

题目如图在 ABC中E是BC上的一点EC=2BE点D是AC的中点设 ABC ADF BEF的面积分别为S S sketch template

如图在 ABC中点DEF分别在BCABAC上且DE∥ACDF∥AB．1如果∠BAC=90°那么四边形AEDF是 形2 sketch template

如图 ABC是等腰三角形∠C=90°D是AB的中点点EF分别在ACBC边上运动且保持AE=CF连接DEDFEF．在此运动 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图点DE分别在 ABC的边上ABAC上且若DE=3BC=6AB=8则AE的长为——青夏教育精英家教�—— sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图在平行四边形ABCD中AB=6BC=4∠B=60°点E是边AB上的一点点F是边CD上一点将平行四边形ABCD沿EF折叠得到 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

如图点DE分别在ACAB上． 1 已知BD=CECD=BE求证AB=AC 2 分别将“BD=CE 记为�“CD=BE sketch template

如图点DEFB在同一直线上AB∥CDAE∥CF且AE=CF若BD=10BF=2则EF= ——青夏教育精英家教�—— sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

20．如图点DEF分别在ABBCAC上且DE∥ACEF∥AB下面写出了说明“∠A ∠B ∠C＝180° 的过程请填空因为 sketch template

free web stats