（1）如图1，在四边形abcd中，ab=cd，e、f分别是bc、ad的中点，连接ef并延长，分别与ba、cd的延长线交于点m、n，证明：∠ Sketch Coloring Page

（1）如图1，在四边形abcd中，ab=cd，e、f分别是bc、ad的中点，连接ef并延长，分别与ba、cd的延长线交于点m、n，证明：∠ Template

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يآآسر محمد
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tomski（1）如图1，在四边形abcd中，ab=cd，e、f分别是bc、ad的中点，连接ef并延长，分别与ba、cd的延长线交于点m、n，证明：∠ coloring

（1）如图1，在四边形ABCD中，AB=CD，E、F分别是BC、AD的中点，连接EF并延长，分别与BA、CD的延长线交于点M、N，证明：∠ sketch template

【自主探究�（1）如图1，在四边形ABCD中，AB=AD，∠BAD=90°，点E、F分别在边BC、CD上，且∠EAF=45°，若∠B=∠ADF sketch template

题目1如图1在四边形ABCD中AB=AD∠BAD=120°∠B=∠ADC=90°．EF分别是BCCD上的点．且∠EAF sketch template

$1如图1在四边形ABCD中AB=AD∠B=∠D=90°EF分别是边BCCD上的点且∠EAF=$frac{1}{2}$∠ sketch template$

如图1在四边形ABCD中AB=CDEF分别是BCAD的中点连接EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图1，在四边形ABCD中，AB=AD，∠BAD=120°，∠B=∠ADC=90°，EF分别是BC，CD上的点，且∠EAF=60°，探究图中 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图在四边形ABCD中AB=CDEF分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN证明∠BME=∠ sketch template

百度教育 sketch template

如图在四边形ABCD中延长AD至E已知AC平分∠DAB∠DAB=70°∠1=35°．1求证AB∥CD2求∠2度数．题目 sketch template

如图，在四边形ABCD中，AD∥BC，E为CD的中点，连结AE，BE，延长AE交BC的延长线于点F。 sketch template

如图已知四边形ABCD中AB∥CDAB=6cmBC=23cmBD=3 3cm将这个平行四边形折过去使点B和点D重合求折痕 sketch template

1如图在四边形ABCD中AB=AD∠B=∠D=90°E、F分别是边BC、CD上的点且∠EAF=∠BAD求证EF=BE FD sketch template

百度教育 sketch template

如图在平行四边形ABCD中AD=2ABCE平分∠BCD延长CEBA交于点F连接ACDF．1如图1求证四边形ACDF是平行 sketch template

百度教育 sketch template

1操作�现如图1在矩形ABCD中E是BC的中点将 ABE沿AE折叠后得到 AFE点F在矩形ABCD内部延长AF交CD于点G sketch template

13．如图四边形ABCD中对角线BDADBDBCAD=BC=则当= 时四边形ABCD是平行四边形．——青夏教育精英家教�—— sketch template

例1如图所示空间四边形ABCD中EFG分别在ABBCCD上且满足AE∶EB=CF∶FB=2∶1 CG∶GD=3∶1过EF sketch template

如图在四边形ABCD中AB=AD∠BAD=∠BCD=90°连接AC若AC=6则四边形ABCD的面积为解析如图作AM⊥BC sketch template

题目如图在平行四边形ABCD中AB=6BC=4∠B=60°点E是边AB上的一点点F是边CD上一点将平行四边形ABCD沿EF sketch template

如图在四边形ABCD中对角线ACBD相交于点O∠ADB=∠CBDAD=BC．1求证四边形ABCD是平行四边形2若AC sketch template

题目如图在四边形ABCD中∠B＝60°∠D＝30°AB＝BC．1求∠A ∠C的度数2连接BD探究ADBDCD三者 sketch template

如图在四边形ABCD 中∠ABC＝90°AB＝6BC＝8CD＝10AD＝10 1求四边形ABCD的面积2求 BD的长 sketch template

如图已知在四边形ABCD中∠BAD=∠BCD=90°BC=CDE是AD延长线上一点若DE=AB=3cmCE=42cm．1试证明 sketch template

如图在正方形ABCD中EC=2BE三角形 BOC的面积是3平方米求阴影部分的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图在四边形ABCD中∠A=135°∠B=∠D=90°BC=2 AD=2则四边形ABCD的面积是A4 B4 C4D6——青 sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

百度教育 sketch template

如图，在中，对角线AC，BD相交于点O， sketch template

百度教育 sketch template

如图所示在四边形ABCD中AC平分∠BAD∠ADC ∠ABC=180°．1求证CD=CB2若BC=10AB=21AD=9 sketch template

如图1在正方形ABCD中P为对角线BD上的一点点E在AD的延长线上且PA=PEPE交CD于F连接CE．1求证 PCE是等腰 sketch template

如图，在四边形ABCD中，AB=AD，∠ BAD=∠ BCD=90^° ，连接AC，若AC=8，则四边形ABCD的面积为。百度教育 sketch template

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