题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Sketch Coloring Page

题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Template

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sketch #3429 Another try of Miku xD

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sketch #1435 donara

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tomski题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 coloring

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图1Rt ABC中∠C=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

题目如图点ABC在一条直线上 ABD BCE均为等边三角形连接AE和CDAE分别交CDBD于点MPCD交BE于点Q sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图在 ABC中AB=AC∠A=36°请你设计三种不同的方法将 ABC分割成三个等腰三角形不要求写出画法不要求证明但是要标出所 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图在三角形ABC中BDDC=12E为AD的中点若三角形ABC的面积为120平方厘米则阴影部分的面积是多�平方厘米 题目和参考 sketch template

题目如图AD为 ABC的中线BE为三角形ABD中线． 1在 BED中作BD边上的高EF2若 ABC的面积为40BD=5求 sketch template

如图在直角三角形ABC中∠BAC=90°将 ABC沿直线BC�右平移得到 DEF连结ADAE则下列结论中不成立的是 A．AD∥ sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

如图， ABC和 DEF是两个全等的等腰直角三角形，∠ BAC=∠ EDF=90°， DEF的顶点E与 ABC的斜边BC的中点重合，将 DEF sketch template

已知在三角形abc中知识要点北京爱智康 sketch template

三角形重心的性质及其证明 知乎 sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

如图所示在三角形ABC中D为BC的中点AD和BE相交F点已知三角形ABC的面积为42平方厘米求三角形BDF的面积． 题目和参考答案 sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

题目如图在等腰直角三角形ABC中∠ABC=90°D为AC边上的中点过D点作DE⊥DF交AB于点E交BC于点F若AE=8FC sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

百度教育 sketch template

20． 如图，三角形ABC中，BD平分∠ABC，AD垂直于BD，三角形BCD的面积为45，三角形ADC的面积为20，则三角形ABD的面积等于 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数． 题目和参考答案——青夏 sketch template

百度教育 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

百度教育 sketch template

如图，在 ABC中，AB=4，AC=3，BC=5，DE是BC的垂直平分线，DE分别交BC、AB于点D、E．1求证： ABC为直角三角形． 2求 sketch template

百度教育 sketch template

百度教育 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

百度教育 sketch template

如图，在 ABC中，∠ABC=90°，AB=BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2之间的距离为2，l2，l3 sketch template

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