已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 Sketch Coloring Page

已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 Template

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tomski已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 coloring

已知在三角形abc中知识要点北京爱智康 sketch template

【中考提升�初中数学平面几何压轴题6大模型及解题方法 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知 ABC中AB=AC∠BAC=α DBC为等边三角形．1如图1∠ABD= 2如图2若∠BCE=150°∠ABE=60 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

已知 ABC中AB=AC∠BAC=α DBC为等边三角形．1如图1∠ABD= 2如图2若∠BCE=150°∠ABE=60 sketch template

百度教育 sketch template

已知在等边三角形ABC中DE分别为ABAC上的点且BD=AEEB与CD相交于点OEF⊥CD于点F．求证OE=2OF．题目和参考 sketch template

如图在 ABC中AB=AC=8cm∠A=30°求 ABC的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图在 ABC中AB＞AC＞BCP为三角形内任意一点连接AP并延长交BC于D．求证1AB AC＞AD BC2AB AC sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

已知如图在等边三角形ABC中MN分别是ABAC的中点D是MN上任意一点CDBD的延长线分别与ABAC交于FE若1CE sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图在三角形ABC中BC=8厘米AD=6厘米EF分别为AB和AC的中点．那么三角形EBF的面积是66平方厘米．——青夏教育精英家教�—— sketch template

在等腰三角形ABC中AB=ACBECD分别是底角的平分线DE∥BC图中等腰三角形的个数有 A3个 B4个 C5个 D6 sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

已知 ABC中∠BAC=30°AB=AC=4．将 ABC沿AC翻折点B落在B′点连接并延长A B′与线段BC的延长线相交于点D求 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

如图已知 ABC中AB=ACM是BC的中点DE分别是ABAC边上的点且BD=CE1求证MD=ME．2若D为AB的 sketch template

如图在三角形ABC中BDDC=12E为AD的中点若三角形ABC的面积为120平方厘米则阴影部分的面积是多�平方厘米题目和参考 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

图，三角形ABC中，EF分别在AB，AC上，DE垂直于DF，D是边上BC的中点，则BE CF答案及详细解析过程——青夏教育精英家教�—— sketch template

在 ABC中AB=AC点P为 ABC所在平面内一点过点P分别作PE∥AC交AB于点EPF∥AB交BC于点D交AC于点F．若点P在BC sketch template

在Rt ABC中∠ACB等于90°∠ABC等于30°AC=1将 ABC绕点A逆时针旋转至 AB′C′使得点AC′恰好落在斜边AB上 sketch template

如图所示在 ABC中AB=AC∠BAD=α且AE=AD则∠EDC= A12αB13αC14αD23α 题目和参考答案 sketch template

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