已知三角形abc中ab≠ac求证∠b≠∠c要用反证法证明此�题第一步应假设——青夏教育精英家教�—— Sketch Coloring Page

已知三角形abc中ab≠ac求证∠b≠∠c要用反证法证明此�题第一步应假设——青夏教育精英家教�—— Template

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Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #4310 robot

anonymous

anonymous
sketch #4310 robot

sketch #949 jbj

anonymous

anonymous
sketch #949 jbj

sketch #5222 Magic Art Tin Sheek

anonymous

anonymous
sketch #5222 Magic Art Tin Sheek

sketch #2976 A girl watches the moon

Laura Agapi Asnicar
sketch #2976 A girl watches the moon

sketch #2922

anonymous

anonymous
sketch #2922

sketch #3620 Dude by Arasheel Eomseii

anonymous

anonymous
sketch #3620 Dude by Arasheel Eomseii

sketch #389

anonymous

anonymous
sketch #389

sketch #3701 amazing Skull

anonymous

anonymous
sketch #3701 amazing Skull

sketch #5074

anonymous

anonymous
sketch #5074

sketch #1118 easy zombie

anonymous

anonymous
sketch #1118 easy zombie

sketch #5341 Rafael Nadal by Alina Danielle

anonymous

anonymous
sketch #5341 Rafael Nadal by Alina Danielle

sketch #293 jdjdjdjdj

Helyryn
sketch #293 jdjdjdjdj

sketch #3575 Stitch by Laura Gutierrez Hinojosa

anonymous

anonymous
sketch #3575 Stitch by Laura Gutierrez Hinojosa

sketch #3232

anonymous

anonymous
sketch #3232

sketch #5434

anonymous

anonymous
sketch #5434

sketch #5437 Mikasa from Attack on Titan by Manimarmuthu Muthu

anonymous

anonymous
sketch #5437 Mikasa from Attack on Titan by Manimarmuthu Muthu

sketch #2892 Joker by Frank Aguiar Au

anonymous

anonymous
sketch #2892 Joker by Frank Aguiar Au

sketch #4436 Bob Marley by Luiza Irma

anonymous

anonymous
sketch #4436 Bob Marley by Luiza Irma

sketch #4511 Yao Ming by Betty Marie Melzer

anonymous

anonymous
sketch #4511 Yao Ming by Betty Marie Melzer

sketch #5162 Alien by KiNg Buamir

anonymous

anonymous
sketch #5162 Alien by KiNg Buamir

sketch #2788 Yuno Gasai from Mirai Nikki by Cristina Love

Cristina Love
sketch #2788 Yuno Gasai from Mirai Nikki by Cristina Love

sketch #5312

anonymous

anonymous
sketch #5312

sketch #3505 Django

anonymous

anonymous
sketch #3505 Django

sketch #5159 Frank Briones Silvia Haynes

anonymous

anonymous
sketch #5159 Frank Briones Silvia Haynes

sketch #1446

anonymous

anonymous
sketch #1446

sketch #4176 Eye by Jawad Kallou

anonymous

anonymous
sketch #4176 Eye by Jawad Kallou

sketch #2018

Charlie Vo
sketch #2018

sketch #5264

anonymous

anonymous
sketch #5264

sketch #1170

anonymous

anonymous
sketch #1170

sketch #5323 Cem Adrian by Glynis June Williams

anonymous

anonymous
sketch #5323 Cem Adrian by Glynis June Williams

tomski已知三角形abc中ab≠ac求证∠b≠∠c要用反证法证明此�题第一步应假设——青夏教育精英家教�—— coloring

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

【中考提升�初中数学平面几何压轴题6大模型及解题方法知乎 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

三角形“四心”有关性质及证明（内心篇）知乎 sketch template

轻松学好初中几何：各个击破初中几何问题之《等腰三角形》知乎 sketch template

定理证明 30°所对直角边等于斜边的一半知乎 sketch template

如图 ABD与 AEC都是等边三角形AB≠AC下列结论中�BE=DC�∠BOD=60°� BOD∽ COE．正确的序号是�� sketch template

定理等腰三角形的两个底角相等．请写已知求证并证明．已知 ABC中AB=AC求证∠B=∠C．证明 题目和参考答案——青夏教育精英 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

21如图，已知等腰直角三角形ABC，点P是斜边BC上一点不与B，C重合，PE是 ABP的外接圆⊙O的直径．1求证： APE是等腰直角 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

在三角形ABC中点O是AC边上一个动点过点O作MN∥BC设MN交∠BCA的平分线于点E交 ABC的外角∠ACD平分线于点E．1求证 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

已知在等边三角形ABC中DE分别为ABAC上的点且BD=AEEB与CD相交于点OEF⊥CD于点F．求证OE=2OF．题目和参考 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如下图所示， ABC中，AC=BC，∠ACB=30°，∠ADB=45°，那么边长AB是河南华图教育 sketch template

已知 ABC中AB=AC∠BAC=90° ABD为等边三角形E是BD中点AECD相交于O点．1求∠DCB的度数2求证 sketch template

如图在不等边 ABC中AB＞ACAC≠BC过AC上一点D作一条直线使截得的三角形与原三角形相似这样的直线可作 A2条 B3条 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

如图．已知点BCD在同一条直线上． ABC和 CDE都是等边三角形BE交AC于FAD交CE于H1求证 BCE≌ ACD2 sketch template

百度教育 sketch template

1证法回顾证明三角形中位线定理．已知如图1DE是 ABC的中位线．求证 ．证明添加辅助线如图1在 ABC中延长DE sketch template

已知等边三角形ABC中延长AC到F使得ED=DF求证BE=CF——青夏教育精英家教�—— sketch template

如图所示在三角形ABC中∠ABC=45°CD⊥AB与点DBE平分∠ABC 且BE⊥AC于点E与CD相交于点FH是BC边的中点 sketch template

1．如图⊙O是等腰三角形ABC的外接圆AB=AC延长BC至点D使CD＝AC连接AD交⊙O与点E连接BECE与AC交于点F 1 sketch template

如图已知 ABC中AB=BC=AC∠ABC=∠BCA=∠CAB=60°MN分别在 ABC的BCAC边上且BM=CNAMBN交 sketch template

已知 ABC中∠C=90°∠A=60°AC=2cm若以C为圆心的圆与AB相切则这个圆的半径是 ——青夏教育精英家教�—— sketch template

如图在等腰三角形ABC中AB=ACD是AB边上一点以CD为底边�上作等腰 DCE使 EDC∽ ABC连接AE．1判断 ACE sketch template

如图AO平分∠BACAB=AC图中有对三角形全等——青夏教育精英家教�—— sketch template

已知在 ABC中AB=AC=8∠BAC=30°将 ABC绕点A旋转使点B落在原 ABC的点C处此时点C落在点D处延长线段AD交原 sketch template

如图已知在 ABC中AB=ACD为BC边的中点过点D作DE⊥ABDF⊥AC垂足分别为EF．1求证 BED≌ CFD2 sketch template

已知 ABC中∠ACB＝90°AC＝9cmAB＝40cm则斜边上的中线CD的长是 A 20cm B 40cm C 20 sketch template

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