如图，在直角三角形abc中，∠acb=90°，ca＝4．点p是半圆弧ac的中点，连接bp，线段bp把图形apcb分成两部分，则这两部分面积之差 Sketch Coloring Page

如图，在直角三角形abc中，∠acb=90°，ca＝4．点p是半圆弧ac的中点，连接bp，线段bp把图形apcb分成两部分，则这两部分面积之差 Template

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tomski如图，在直角三角形abc中，∠acb=90°，ca＝4．点p是半圆弧ac的中点，连接bp，线段bp把图形apcb分成两部分，则这两部分面积之差 coloring

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图， ABC和 DEF是两个全等的等腰直角三角形，∠ BAC=∠ EDF=90°， DEF的顶点E与 ABC的斜边BC的中点重合，将 DEF sketch template

如图在 ABC中AB=AC∠A=36°请你设计三种不同的方法将 ABC分割成三个等腰三角形不要求写出画法不要求证明但是要标出所 sketch template

如图在直角三角形ABC中∠ACB=90°CD是AB边上的高AB=13cmBC=12cmAC=5cm求CD的长 3作出 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

如图，在直角三角形ABC中，∠ACB=90°，∠CBA=30°，请你设计三种不同的分法，把 ABC分割成两个三角形，且 ZOL问答 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

如图在直角三角形ABC中放置边长分别34x的三个正方形则x的值为．题目和参考答案——青夏教育精英家教�—— sketch template

如图ABC是等腰直角三角形它的内部有两个小正方形求阴影部分的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图直角 ABC的直角顶点为C且AC=5BC=12AB=13将此三角形绕点A顺时针旋转90°到直角 AB′C′的位置在旋转过程中 sketch template

如图以直角三角形ABC的三边长分别为6cm 8cm10cm分别以它的三边为直径�上做三个半圆 则图中的阴影部分面积为 ——青夏教育 sketch template

如图，在直角三角形ABC中，∠ACB=90°，∠CBA=30°，请你设计三种不同的分法，把 ABC分割成两个三角形，且 ZOL问答 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如图，在正三角形ABC中，AB=6，D、E分别为AC、BC上的动点，知乎 sketch template

如图在平面直角坐标系中把 ABC沿y轴对折后得到 A1B1C1再将 A1B1C1�下平移4个单位长度得到 A2B2C2则 AB1C2的 sketch template

14．如图在 ABC中∠B=90°两直角边AB=5BC=12三角形内有一点P到各边的距离相等求点P到各边的距离——青夏教育精英家教�—— sketch template

如图在直角三角形ABC中AB与BC的长度分别为8厘米10厘米以BC为直径画半圆D是半圆的中点阴影部分的面积是多�平方厘米题目和 sketch template

如图在三角形ABC中BDDC=12E为AD的中点若三角形ABC的面积为120平方厘米则阴影部分的面积是多�平方厘米题目和参考 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示 1 如图�分别以直角三角形ABC三边为 sketch template

如图在直角三角形ABC中∠BAC=90°将 ABC沿直线BC�右平移得到 DEF连结ADAE则下列结论中不成立的是 A．AD∥ sketch template

如图将两块全等的直角三角形纸片 ABC和 DEF叠放在一起其中∠ACB=∠E=90°BC=DE=6AC=FE=8如图将 DEF绕点 sketch template

百度教育 sketch template

如图，在平面直角坐标系xOy中，三角形ABC三个顶点的坐标分别是A（ 3，2），B（ 1， 1），C（0，3）．将三角形ABC平移，使点A与点 sketch template

如图所示在直角三角形abc区域含边界内存在垂直于纸面�外的匀强磁场磁感应强度大小为B∠a=60°∠b=90°边长ac=L一个 sketch template

21如图，已知等腰直角三角形ABC，点P是斜边BC上一点不与B，C重合，PE是 ABP的外接圆⊙O的直径．1求证： APE是等腰直角 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

1．在直角 ABC中∠C=90°． 1如果以此直角三角形三边为边分别作三个正三角形那么面积S1S2S3之间有什么关系 2 sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

如图在三角形ABC中BC=8厘米AD=6厘米EF分别为AB和AC的中点．那么三角形EBF的面积是66平方厘米．——青夏教育精英家教�—— sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为．——青夏教育精英家教�—— sketch template

如图直角三角形ABC的两条直角边AB和BC分别长4厘米和3厘米现在以斜边AC为轴旋转一�．求所形成的立体图形的体积．题目和参考答案——青 sketch template

在等腰直角三角形ABC中过直角顶点C在 内部任意作一条射线CM与线段AB交于点M则 AM sketch template

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