如图在等边 abc中d为ac的中点e是ab上一点且则图中和 Ade相似的三角形有a．1个 B．2个 C．3个d．4个——青夏教育精英 Sketch Coloring Page

如图在等边 abc中d为ac的中点e是ab上一点且则图中和 Ade相似的三角形有a．1个 B．2个 C．3个d．4个——青夏教育精英 Template

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sketch #5079 SketchToy Pencil by Sarah Prieto

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sketch #5079 SketchToy Pencil by Sarah Prieto

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sketch #5237 Gotye by Jhonatan Soares

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sketch #288 RK

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sketch #4269 dragón

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sketch #3626 Skream by Wellen Lima

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sketch #3036 Wiz Khalifa by Malyi Link

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sketch #3036 Wiz Khalifa by Malyi Link

sketch #3268 Werewolf by Mert Arda Yiğit

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sketch #3268 Werewolf by Mert Arda Yiğit

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sketch #2744 Burce Lee by Karim Tayyeby

Karim Tayyeby
sketch #2744 Burce Lee by Karim Tayyeby

tomski如图在等边 abc中d为ac的中点e是ab上一点且则图中和 ade相似的三角形有a．1个 coloring

题目如图在边长为2的等边 ABC中D为BC的中点E是AC边上一点则BE DE的最小值为 ．题目和参考答案——青夏教育精英家教�—— sketch template

如图在边长为6cm的等边 ABC中D是AC的中点E为BC延长线上一点若∠DEC=30°则BE的长为 Cm．A．8B．9C．10D sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

在 ABC中，D为AB上的中点，E为线段AC上的点，且DE = 1/2BC，什么时候有两条DE？知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图在等边 ABC中D为AC的中点E是AB上一点且则图中和 ADE相似的三角形有A．1个 B．2个 C．3个D．4个——青夏教育精英 sketch template

题目已知如图 ABC和 CDE均为等边三角形BCD三点在同一条直线上连接线段BEAD交于点F连接CF1求证∠FBC sketch template

如图在等边 ABC中D为AC的中点E是AB上一点且则图中和 ADE相似的三角形有A．1个 B．2个 C．3个D．4个——青夏教育精英 sketch template

如图在边长为2的等边 ABC中AD⊥BC于点D且AD=$sqrt{3}$E为AC中点P为AD上一点则 PEC�长的最小值是 sketch template

如图，在 ABC中，点D是AC的中点，点E是BC的三等分点，连接AE和B 华图公务�题库 sketch template

如图所示，边长为2的等边三角形中，D点在边上运动（不与B、C重合），点E在边的延长线上，点F在边的延长线上，．点D在边上从B至C的运动过程 sketch template

如图1在 ABC中AC=BC∠ACB=90°点D为AB边中点以点D为顶点作∠PDQ=90°DPDQ分别交直线ACBC于EF sketch template

如图已知在等边三角形ABC中DE是ABAC上的点且AD=CE．求证CD=BE．题目和参考答案——青夏教育精英家教�—— sketch template

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

如图等边三角形ABC的边长为6A、B、A1三点在一条直线上且 ABC≌ A1BC1若D为线段BC1上一动点则AD CD的最小值是 sketch template

如图在等边 ABC中点DE分别为ABAC边的中点点F为BC边上一点CF=1连接DF以DF为边作等边 DFG连接AG且∠ sketch template

如图在正方形ABCD中EC=2BE三角形 BOC的面积是3平方米求阴影部分的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图，AB为⊙O的直径，C、D为⊙O上的两点，且AC平分∠BAD，过点C作直线EF⊥AD，交AD的延长线于点E． sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图D为等边 ABC边AC的中点E是BC延长线上一点且CEBC则 DBE是一个 三角形只填出一个你认为正确的结论——青夏教育 sketch template

如图，在菱形ABCD中，AB=AC=10，对角线AC、BD相交于点O，点M在线段AC上，且AM=3，点P为线段BD上的一个动点，则MP sketch template

百度教育 sketch template

如图在等边 ABC中D为AC的中点E是AB上一点且则图中和 ADE相似的三角形有A．1个 B．2个 C．3个D．4个——青夏教育精英 sketch template

如图等边 ABC中AB=5点DE分别在BCAC边上将 EDC沿直线DE翻折后点C落在点C′处且点C′在 ABC的外部则图中 sketch template

如图，在等边 ABC中，D为BC边上一点，E为AC边上一点，且∠ADE=60°，BD=3，CE=2，则 ABC的边长为（） A 9 B sketch template

如图在平面直角坐标系中把 ABC沿y轴对折后得到 A1B1C1再将 A1B1C1�下平移4个单位长度得到 A2B2C2则 AB1C2的 sketch template

如图在 ABC中AB的垂直平分线EF交BC于点E交AB于点FD为线段CE的中点BE=AC1求证AD⊥BC2若∠BAC sketch template

如图所示在等腰Rt ABC中AC=BC以斜边AB为一边作等边 ABD使点CD在AB的同侧再以CD为一边作等边 ECD使点CE在 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数题目和参考答案——青夏教育精英家教�—— sketch template

题目如图在 ABC中边ABAC的垂直平分线分别交BC于DE．1若BC=10求 ADE的�长 2 设直线DMEN交于点 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在等边 ABC中P是BC上一点D是AC上的一点∠APD=60°BP=1CD=则 ABC的边长是A 3 B 4 C 5 sketch template

如图，在以点O为圆心的两个同心圆中，大圆的弦AB交小圆于点C、D 已知AB=4，CD=2，圆心O到直线AB的距离为1，则大圆的半径为 ，小圆 sketch template

如图等边三角形ABC中DE分别为ABBC边上的两动点且总使AD=BEAE与CD交于点FAG⊥CD于点G则FGAF= A sketch template

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