如图在 abc中分别以abac为边�外作等腰直角三角形abe等腰直角三角形acd其中∠bae=∠cad=90°bd与ce相交于点o Sketch Coloring Page

如图在 abc中分别以abac为边�外作等腰直角三角形abe等腰直角三角形acd其中∠bae=∠cad=90°bd与ce相交于点o Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #798

Laura Agapi Asnicar
sketch #798

sketch #5159 Frank Briones Silvia Haynes

anonymous

anonymous
sketch #5159 Frank Briones Silvia Haynes

sketch #3804

Laura Agapi Asnicar
sketch #3804

sketch #1145

anonymous

anonymous
sketch #1145

sketch #3999 Deadmau by Speeð Üp Säm

anonymous

anonymous
sketch #3999 Deadmau by Speeð Üp Säm

sketch #4522 Adventure Time by KiNg Buamir

anonymous

anonymous
sketch #4522 Adventure Time by KiNg Buamir

sketch #3042 Tobi by Mirnes Sinanovic

anonymous

anonymous
sketch #3042 Tobi by Mirnes Sinanovic

sketch #4698

anonymous

anonymous
sketch #4698

sketch #3613

anonymous

anonymous
sketch #3613

sketch #4161

Hank Henry Armstrong
sketch #4161

sketch #1448 donara

Donara Smbatyan
sketch #1448 donara

sketch #5438

anonymous

anonymous
sketch #5438

sketch #2549

anonymous

anonymous
sketch #2549

sketch #3381 DBZ by Adidtzu Ady

anonymous

anonymous
sketch #3381 DBZ by Adidtzu Ady

sketch #4653 Kero by Indike Liyanage

anonymous

anonymous
sketch #4653 Kero by Indike Liyanage

sketch #1643

anonymous

anonymous
sketch #1643

sketch #2582

anonymous

anonymous
sketch #2582

sketch #3360

anonymous

anonymous
sketch #3360

sketch #2765 Kratos by Nassim Nouri

Nassim Nouri
sketch #2765 Kratos by Nassim Nouri

sketch #2087 zay lin

Zay Lin
sketch #2087 zay lin

sketch #12 my bear

Tom Kelly
sketch #12 my bear

sketch #1114 fire flame camping bonfire

anonymous

anonymous
sketch #1114 fire flame camping bonfire

sketch #5290 Kyuubi Jorge Valero

anonymous

anonymous
sketch #5290 Kyuubi Jorge Valero

sketch #4190

anonymous

anonymous
sketch #4190

sketch #3367 Ichigo by Szymon Broszczak

anonymous

anonymous
sketch #3367 Ichigo by Szymon Broszczak

sketch #3483 Ginger

Sarah Nila
sketch #3483 Ginger

sketch #215 my mickey mouse

Tom Kelly
sketch #215 my mickey mouse

sketch #5268 Harley Quinn by 조바다

anonymous

anonymous
sketch #5268 Harley Quinn by 조바다

sketch #4661 Woodpecker by Hsien-Ying Hsieh

anonymous

anonymous
sketch #4661 Woodpecker by Hsien-Ying Hsieh

sketch #5258 Adventure Time by Kheith Ryan Lubiano

anonymous

anonymous
sketch #5258 Adventure Time by Kheith Ryan Lubiano

tomski如图在 abc中分别以abac为边�外作等腰直角三角形abe等腰直角三角形acd其中∠bae=∠cad=90°bd与ce相交于点o coloring

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图在等腰 ABC中AB=AC以AB为直径的圆O交BC于点D过点C作CF∥AB与⊙O的切线BE交于点E连接DE．1求证BD sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图在 ABC中EF分别是ABAC的中点则 ——青夏教育精英家教�—— sketch template

如图在 ABC中AB=AC∠ABC=72°按如下步骤作图�以点B为圆心以任意长为半径作弧分别交ABBC于点EF�分别以点E sketch template

题目如图在 ABC中AB=AC以AB为直径作⊙O交BC于点D过点D作⊙O的切线DE交AC于点E交AB延长线于点F．1求证 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图 ABC中AB=ACAB的垂直平分线交AC于点D．若∠A=40°则∠DBC= 若AC BC=10cm则 DBC的�长为 Cm sketch template

如图在 ABC中AB=ACBC=6点EF是中线AD上两点AD=4则图中阴影面积是6．题目和参考答案——青夏教育精英家教�—— sketch template

如图在锐角 ABC中以ABAC为边分别�形外作等边 ABD ACE连BE和CD交于O点BE交AC于M点CD交AB于N点以下结论 sketch template

如图在 ABC中∠A=60° ABC的内切圆I分别切边ABAC于点DE直线DE分别与直线BICI相交于点FG证明FG sketch template

如图在 ABC中∠ABC=90°D是边AC上的一点连接BD使∠A=2∠1E是BC上的一点以BE为直径的⊙O经过点D 1求证 sketch template

如图，在 ABC中，AB=4，AC=3，BC=5，DE是BC的垂直平分线，DE分别交BC、AB于点D、E．1求证： ABC为直角三角形． 2求 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图1在 ABC中AB=AC以AB为直径的⊙O分别交ACBC于点DE．点F在AC的延长线上且∠CAB=2∠CBF．1求证BF sketch template

如图在 ABC中AB=AC∠BAC=54°以AB为直径的 ⊙O分别交ACBC于点DE过点B作⊙O的切线交AC的延长线于点F sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

如图在 ABC中AB=AC=8BC=5AB的垂直平分线交AC于D则 BCD的�长为 A 13 B 15 C 18 D sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图，以 ABC的边AB、AC为边�外作正方形ABDE和正方形ACFG，AH⊥BC，垂足为点H，交EG于点M．求证：EM=MG．百度教育 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图在 ABC中AB=7AC=6BC=8线段BC所在的直线以每秒2个单位的速度沿BA方�运动并始终保持原位置平行x秒时该直线在 sketch template

如图在 ABC中AB的垂直平分线EF交BC于点E交AB于点FD为线段CE的中点BE=AC1求证AD⊥BC2若∠BAC sketch template

如图在 ABC中BD平分∠ABC交AC于点DDE∥BC交AB于点EEF⊥BD于点F．求证∠BEF=∠DEF．题目和参考答案——青夏 sketch template

如图以 ABC的ABAC为一边�外作正方形ABGF和ACDE两个正方形对角线交点分别是MNP是BC中点求证PM＝PN．题目和 sketch template

如图在 ABC中已知点DE分别在ABAC上BE与CD相交于点O依据下列各个选项中所列举的条件不能说明AB=AC的是 A．BE sketch template

$如图 ABC中点D在AB上AD=$frac{1}{3}$AB．点E在BC上BE=$frac{1}{4}$BC．点F在AC上CF sketch template$

如图在 ABC中AB=AC以AC为直径的⊙O交AB于点D交BC于点E．若BD=2BE=3则AC的长为9．题目和参考答案——青夏 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图所示在 ABC中AB=AC∠A=36°BDCE分别为∠ABC与∠ACB的角平分线且相交于点F则图中的等腰三角形有 A．6个 B sketch template

百度教育 sketch template

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