如图在正方形abcd中点ef分别在cdbc上且bf=ce连接beaf相交于点g则下列结论不正确的是 A.be=afb.∠ Template




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tomski如图在正方形abcd中点ef分别在cdbc上且bf=ce连接beaf相交于点g则下列结论不正确的是 a.be=afb.∠ coloring