如图所示在等边 abc中点de分别在边bcab上且bd=aead与ce交于点f则∠dfc的度数为 A．60°b．45°c Sketch Coloring Page

如图所示在等边 abc中点de分别在边bcab上且bd=aead与ce交于点f则∠dfc的度数为 A．60°b．45°c Template

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sketch #5124 Tony Tony Chopper by 陳一夫

anonymous

anonymous
sketch #5124 Tony Tony Chopper by 陳一夫

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anonymous

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anonymous

anonymous
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sketch #1122 norooz

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sketch #5268 Harley Quinn by 조바다

anonymous

anonymous
sketch #5268 Harley Quinn by 조바다

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anonymous

anonymous
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sketch #5277 League of Legends champions by Sylvie Rieux

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anonymous
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Fabio Sala
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sketch #2678 Portrait by Jocelyn Alejandra Rantul

Jocelyn Alejandra Rantul
sketch #2678 Portrait by Jocelyn Alejandra Rantul

sketch #2668 Butterfly by Loai Issa

Loai Issa
sketch #2668 Butterfly by Loai Issa

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anonymous
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sketch #5061

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sketch #2318

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Tom Kelly
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sketch #4990

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sketch #4454 Lisa by Muhammad Raiyaan

anonymous

anonymous
sketch #4454 Lisa by Muhammad Raiyaan

sketch #5086 Lion by Z Ionut Ady

anonymous

anonymous
sketch #5086 Lion by Z Ionut Ady

sketch #4903 Naruto & Kurama by Fatér Szilvia

anonymous

anonymous
sketch #4903 Naruto & Kurama by Fatér Szilvia

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Hank Henry Armstrong
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sketch #4087 Stewie by Leon Soria Ricardo

anonymous

anonymous
sketch #4087 Stewie by Leon Soria Ricardo

sketch #5219 Zayn Malik by Amila Madhushanaka

anonymous

anonymous
sketch #5219 Zayn Malik by Amila Madhushanaka

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Emin AltınKöprü
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tomski如图所示在等边 abc中点de分别在边bcab上且bd=aead与ce交于点f则∠dfc的度数为 a．60°b．45°c coloring

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

1如图1所示在等边 ABC中点D是AB边上的动点以CD为一边�上作等边 EDC连接AE求证AE∥BC中等边 ABC的形状改 sketch template

1如图1所示在等边 ABC中点D是AB边上的动点以CD为一边�上作等边 EDC连接AE求证AE∥BC中等边 ABC的形状改 sketch template

题目如图在等边三角形ABC中AD⊥BC垂足为D且AD＝6E是AC边上的中点M是AD边上的动点则EM CM的最小值是题目 sketch template

如图等边 ABC在平面直角坐标系中的位置如图所示其中顶点A则顶点C的坐标为 A123B023C123 1D sketch template

已知如图在等边 ABC中点D为AC上任意一点且∠EDF=60°．求证 CDE∽ AFD．题目和参考答案——青夏教育精英家教�—— sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

题目如图点ABC在一条直线上 ABD BCE均为等边三角形连接AE和CDAE分别交CDBD于点MPCD交BE于点Q sketch template

题目如图在等边 ABC中DE分别是BCAC上的动点且BD=CE连接AD与BE相交于点F连接CF下列结论� ABD≌ BCE sketch template

如图1在等边 ABC的边AC的延长线上取一点E以CE为边作等边 CDE使它与 ABC位于直线AE的同侧．1同学们对图1进行了热烈的 sketch template

题目如图1 ABC为等边三角形点EF分别在BC和AB上且CE=BFAE与CF相交于点H1求证 ACE≌ CBF2求 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为 百度教育 sketch template

（1）问题�现如图1， ABC和 BDE均为等边三角形，点A，D，E在同一直线上，连接CD．填空：�∠CDB的度数为 ；�线段AE，CD sketch template

24．12分如图所示，绝缘光�轨道ABCD竖直放在与水平方�成θ＝45°的匀强电场中，其中BCD部分是半径为R的半圆环，轨道的水平部分与 sketch template

如图在等边 ABC中点DE分别在BCAB上AD与CE交于F且BD=AE．则∠DFC=6060度．题目和参考答案——青夏教育精英家教�—— sketch template

如图在等边 ABC 中DEF分别为ABBCCA上一点且AD=BE=CF若每三个三角形两两全等为一组则图中全等的三角形组数为 sketch template

在 ABC和 DEC中，AC=BC，DC=EC，∠ACB=∠ECD=90°（1）如图1，当点A、C、D在同一条直线上时，求证：AF⊥BD sketch template

如图所示，在 ABC中，∠B=60°，AB=AC，点D、E分别在BC、AB上，且BD=AE，AD与CE交于点F．（1）求证： ABC是等边三角 sketch template

如图，在 ABC中，点D，E分别是边AC，AB的中点，BD与CE交于点O，连接DE．下列结论：� ；� ；� ；� ．其中正确的个数有（ sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图所示，在a、b两点固定着两个带等量异种电荷的点电荷，c、d两点将a、b两点的连线三等分，e、f是a、b两点连线的中垂线上的两点，且e、f到 sketch template

如图所示有一束平行于等边三棱镜截面ABC的单色光从空气射�E点并偏折到F点．已知入射方�与边AB的夹角为θ=300EF分别为边BC的 sketch template

已知：如图所示在 ABC中AD是 ABC的角平分线E、F分别是ABAC上的点并且有∠EDF ∠EAF=180∘，DG⊥AB于点G sketch template

如图等边三角形ABC中DE分别为ABBC边上的两动点且总使AD=BEAE与CD交于点FAG⊥CD于点G则FGAF= A sketch template

如图在 ABC中点D是AB边上的一点1请用尺规作图法在 ABC内求作∠ADE使∠ADE=∠BDE交AC于E不要求写作法 sketch template

如图，已知点A、B、C在同一直线上， ABD和 BCE都是等边三角形．则在下列结论中：�AP=DQ，�EP=EC，�PQ=PB，�∠AOB=∠ sketch template

如图所示，边长为2的等边三角形中，D点在边上运动（不与B、C重合），点E在边的延长线上，点F在边的延长线上，． 点D在边上从B至C的运动过程 sketch template

如图所示在等腰Rt ABC中AC=BC以斜边AB为一边作等边 ABD使点CD在AB的同侧再以CD为一边作等边 ECD使点CE在 sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图等边 ABC中点D在AB上点E在BC上AD=BE．AE和CD相交于点P求证∠CPE=60°．题目和参考答案——青夏教育精英家教�—— sketch template

如图等边三角形ABC中点DEF分别为边ABACBC的中点M为直线BC动点 DMN为等边三角形1如图1当点M在点B左侧时 sketch template

如图在等边 ABC中点DE分别在边BCAC上且AE=CDBE与AD相交于点PBQ⊥AD于点Q．1求证BE=AD2求证 sketch template

探究1如图1在ABC与ADE中AB=ACAD=AE∠BAC=∠DAE=90°连结BDCE．请写出图1中所有全等的三角形 sketch template

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