如图已知ab是⊙o的直径点c在⊙o上过点c的直线与ab的延长线交于点pac=pc∠cob=2∠pcb．1求证pc是⊙o的切线 Sketch Coloring Page

如图已知ab是⊙o的直径点c在⊙o上过点c的直线与ab的延长线交于点pac=pc∠cob=2∠pcb．1求证pc是⊙o的切线 Template

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tomski如图已知ab是⊙o的直径点c在⊙o上过点c的直线与ab的延长线交于点pac=pc∠cob=2∠pcb．1求证pc是⊙o的切线 coloring

PPT 直线与圆的位置关系（2） PowerPoint Presentation Free Download ID6035436 sketch template

已知：AB是⊙O的直径，弦CD交AB于点E，且．（1）如图1，求证：CE=DE；（2）如图2，连接AC，点F为AC上的一点，连接BF，过点C作 sketch template

如图AB是⊙O的直径弦BC＝2 Cm∠ABC＝60°． 1求⊙O的直径 2若D是AB延长线上一点连结CD当BD长为多�时 sketch template

如图已知AB是⊙O的直径点C在⊙O上过点C的直线与AB的延长线交于点PAC=PC∠COB=2∠PCB．1求证PC是⊙O的切线 sketch template

如图已知AB为⊙O的直径AB=2AD和BE是圆O的两条切线AB为切点过 圆上一点C作⊙O的切线CF分别交ADBE于点MN sketch template

如图已知AB是⊙O的直径点C在⊙O上过点C的直线与AB的延长线交于点PAC=PC∠COB=2∠PCB．1求证PC是⊙O的切线 sketch template

如图已知AB是⊙O的直径CD是弦且CD⊥ABBC=6AC=8则sin∠ABD的值是ABCD——青夏教育精英家教�—— sketch template

已知如图OA是⊙O的半径以OA为直径的⊙C与⊙O的弦AB相交于点D．求证点D是AB的中点．题目和参考答案——青夏教育精英家教�—— sketch template

如图，AB是⊙O的直径，点C为的中点，CF为⊙O的弦，且CF⊥AB，垂足为E，连接BD交CF于点G，连接CD，AD，BF sketch template

如图已知AB是⊙O的直径弦CD与AB交于点EF为CD的延长线上一点连接AF且FA2=FD•FC．1求证FA为⊙O的切线2 sketch template

15．如图已知AB是⊙O的直径点C是⊙O上一点连结BCAC过点C作直线CD⊥AB于点D点E是AB上一点直线CE交⊙O于点F连结 sketch template

如图四边形ABCD内接于⊙OAB是⊙O的直径AC和BD相交于点E且1求证BC=CD2分别延长ABDC交于点P过点A作 sketch template

如图AB是⊙O的直径CP是弧AB上两点AB=13AC=5．若点P是弧AB的中点求PA的长若点P是弧BC的中点求PA的长 sketch template

如图 ABC是⊙O的内接三角形AB是⊙O的直径∠ABC=30度．将 ABC沿直线AB�右平移使点A与点O重合则BC与⊙O的位置关系是 sketch template

已知如图AB为⊙O的直径CD为⊙O上的两点且C为AD的中点若∠BAD=20°求∠ACO的度数．题目和参考答案——青夏教育精英家教�—— sketch template

如图已知AB是⊙O的直径点CD在⊙O上∠ABC=50°则∠D为 A30°B40°C50°D60° 题目和参考答案 sketch template

如图AB是⊙O的直径CD是⊙O上的两点若∠ABC=70°则∠BDC的度数为 A．50°B．40°C．30°D．20° 题目和参考 sketch template

用�量法证明直径所对的圆�角是直角百度教育 sketch template

如图AB是⊙O的直径点CD是半圆弧AB上的两个三等分点AB=aAC=b则AD= A12a BB12a BCa 12bD sketch template

如图AB是⊙O的直径∠ACD=45°∠ADC=30°．1∠ABD=45°．2求证AD=BD．3若AC=2求⊙O的半径 sketch template

如图C是⊙O直径AB上一点过C点作弦DE使CD＝CO若的度数为40º求的度数 D A C O E——青夏教育精英家教�—— sketch template

如图已知⊙O1与⊙O2相交于AB两点AB是⊙O2的直径过A点作⊙O1的切线交⊙O2于点E并与BO1的延长线交于点PPB分别与⊙O1 sketch template

如图⊙O与⊙P相交于BC两点BC是⊙P的直径且把⊙O分成度数的比为12的两条弧A是上的动点连结ABAC分别交⊙P于DE两点 sketch template

如图AB是⊙O的直径BC是⊙O的弦半径OD⊥BC垂足为E若BC=6DE=3 1图中有很多结论例如OA=OC=OD=OB等 sketch template

如图AB是半圆⊙O的直径 ABC的两边ACBC分别交半圆于DE且E为BC的中点已知∠BAC=50°则∠C= A 55 sketch template

如图已知AB是⊙O的直径C是圆上一点延长BC至D使CD=BC连接AD过C作CE⊥AD于EBE交⊙O于F．求证EF•EB=AE sketch template

如图已知AB为⊙O的直径点C为半圆上的三等分点在直径AB所在的直线上找一点P连接CP交⊙O于点Q使PQ=OQ则∠CPO=20°或 sketch template

如图AB是⊙O的直径CD是⊙O上的点∠CDB=30°过点C作⊙O的切线交AB的延长线于E则sin∠E的值为 A．12B．32C sketch template

如图已知⊙O1和⊙O2相交于ABACAD分别是两圆的直径1CBD三点在同一直线吗为什么2当⊙O1和⊙O2满足什么条件 sketch template

如图 已知ab为圆o的直径d是弧bc的中点答案及详细解析过程——青夏教育精英家教�—— sketch template

如图 已知ab为圆o的直径d是弧bc的中点答案及详细解析过程——青夏教育精英家教�—— sketch template

如图已知半圆O的直径AB将一个三角尺的直角顶点固定在圆心O上当三角尺绕着点O转动时三角尺的两条直角边与半圆圆�分别交于CD两点连结 sketch template

如图直线AB经过⊙O的圆心与⊙O相交于AB两点点C在⊙O上且∠AOC=30度．点E是直线AB上的一个动点直线EC交⊙O于D则使 sketch template

如图D是半径为R的⊙O上一点过点D作⊙O的切线交直径AB的延长线于点C下列四个条件�AD=CD�∠A=30°�∠ADC=120 sketch template

百度教育 sketch template

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