如图 abc中ab=ac．∠a=36°ab的中垂线de交ac于d交ab于e下述结论ad=bd=bc3 Bdc的�长等于ab Sketch Coloring Page

如图 abc中ab=ac．∠a=36°ab的中垂线de交ac于d交ab于e下述结论ad=bd=bc3 Bdc的�长等于ab Template

Background image: Hide Show

View Larger Image Image Credit: 1010jiajiao.com

please wait, the page is loading...

More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

anonymous

anonymous
sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

sketch #1899 blue

anonymous

anonymous
sketch #1899 blue

sketch #5202 The Woman by Céline Chalois

anonymous

anonymous
sketch #5202 The Woman by Céline Chalois

sketch #3753

anonymous

anonymous
sketch #3753

sketch #4972

anonymous

anonymous
sketch #4972

sketch #5179 Audrey Hepburn by 陳一夫

anonymous

anonymous
sketch #5179 Audrey Hepburn by 陳一夫

sketch #4885

anonymous

anonymous
sketch #4885

sketch #2874 Mario by Ahmed Hosny

anonymous

anonymous
sketch #2874 Mario by Ahmed Hosny

sketch #811

Laura Agapi Asnicar
sketch #811

sketch #5044

anonymous

anonymous
sketch #5044

sketch #4921

anonymous

anonymous
sketch #4921

sketch #3667

anonymous

anonymous
sketch #3667

sketch #3032 Batman by Aaron Bahary

anonymous

anonymous
sketch #3032 Batman by Aaron Bahary

sketch #3680 Infected Mushroom by Rohit Rahul

anonymous

anonymous
sketch #3680 Infected Mushroom by Rohit Rahul

sketch #4915 Marshall Lee Gopal Gopi

anonymous

anonymous
sketch #4915 Marshall Lee Gopal Gopi

sketch #3191

anonymous

anonymous
sketch #3191

sketch #5349

anonymous

anonymous
sketch #5349

sketch #3250 Lonely cat Lars Tunebo

anonymous

anonymous
sketch #3250 Lonely cat Lars Tunebo

sketch #2446 Joker by sketchmaster

sketchmaster
sketch #2446 Joker by sketchmaster

sketch #2852 Teddy Zorka Edding Giustinianovic

Zorka Edding Giustinianovic
sketch #2852 Teddy Zorka Edding Giustinianovic

sketch #1953 愛鼠繪

anonymous

anonymous
sketch #1953 愛鼠繪

sketch #734 ytsfsfsdhgdhgf

Melissa Cogo
sketch #734 ytsfsfsdhgdhgf

sketch #4454 Lisa by Muhammad Raiyaan

anonymous

anonymous
sketch #4454 Lisa by Muhammad Raiyaan

sketch #5200 Kristen Stewart by Rhemzkian Esturco

anonymous

anonymous
sketch #5200 Kristen Stewart by Rhemzkian Esturco

sketch #127

Johnny B. Goode
sketch #127

sketch #3736 Why so serious? by Taï Marsan

anonymous

anonymous
sketch #3736 Why so serious? by Taï Marsan

sketch #787

Laura Agapi Asnicar
sketch #787

sketch #1043 Deadoo..

Cherie N Patanao
sketch #1043 Deadoo..

sketch #4979 Luffy

anonymous

anonymous
sketch #4979 Luffy

sketch #3155 Iron Man

anonymous

anonymous
sketch #3155 Iron Man

tomski如图 abc中ab=ac．∠a=36°ab的中垂线de交ac于d交ab于e下述结论ad=bd=bc3 bdc的�长等于ab coloring

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图在 ABC中AB=AC∠A=36°AB的垂直平分线交AC于点E垂足为点D连接BE则∠EBC的度数为 A．18°B．36 sketch template

5．如图AB=AC∠A=36°BD平分∠ABC图中除BC外与BC 相等的线段分别是．——青夏教育精英家教�—— sketch template

如图在 ABC中AB=AC∠A=36°BD平分∠ABC则∠1= 度图中有个等腰三角形．题目和参考答案——青夏教育精英家教�—— sketch template

17．如图 ABC中AB=AC∠A=36°BDCE分别为角平分线且交点为F则图中的等腰三角形 A．6个 B．7个 C．8个 D sketch template

7．如图 ABC中AB=AC∠A=36°两条角平分线BDCE相交于点F图中的等腰三角形共有 A．6个 B．7个 C．8个 D．9个 sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

5．如图AB=AC∠A=36°BD平分∠ABC图中除BC外与BC 相等的线段分别是．——青夏教育精英家教�—— sketch template

如图在 ABC中AB＝AC∠A＝36°BDCE分别是∠ABC与∠ACB的角平分线且相交于点F则图中的等腰三角形共有 A6 sketch template

如图，在Rt ABC中，∠ABC=90°，AB=3，BC=4，在Rt MPN中，∠MPN=90°，点P在AC上，PM交AB于点E，PN交BC于 sketch template

如图 ABC中AB=ACAE⊥BCE为垂足F为AB上一点．以BF为直径的圆与AE相切于M点交BC于G点．1求证BM平分∠ABC sketch template

如图在 ABC中AB=ACAE是角平分线BM平分∠ABC交AE于点M经过BM两点的⊙O交BC于点G交AB于点FFB恰为⊙O的 sketch template

如图甲在 ABC中∠ACB为锐角．点D为射线BC上一动点连接AD以AD为一边且在AD的右侧作正方形ADEF．解答下列问题 1 sketch template

如图，在 ABC中，AB=AC，⊙O是 ABC的外接圆，BO的延长线交边AC于点D（1）求证：∠BAC=2∠ABD；（2）当 BCD是等腰 sketch template

如图，在 ABC中，AB=AC，⊙O是 ABC的外接圆，BO的延长线交边AC于点D（1）求证：∠BAC=2∠ABD；（2）当 BCD是等腰 sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图已知 ABC中AB=AC=24厘米∠ABC=∠ACBBC=16厘米点D为AB的中点．如果点P在线段BC上以4厘米/秒的速度由B点 sketch template

如图所示在 ABC中AB=AC∠A=36°BDCE分别为∠ABC与∠ACB的角平分线且相交于点F则图中的等腰三角形有 A．6个 B sketch template

如图 ABC中∠BAC=90°AB=ACD是斜边BC的中点EF分别是ABAC边上的点且DE⊥DF若BE=12CF=5求 sketch template

如图已知 ABC中AB=ACM是BC的中点DE分别是ABAC边上的点且BD=CE1求证MD=ME．2若D为AB的 sketch template

如图在Rt ABC中∠ABC=90°BA=BC点D是AB的中点连接CD过点B作BG⊥CD分别交CDCA于点EF与过点A且 sketch template

如图在 ABC中AB=20cmAC=12cm点P从点B出�以每秒3cm的速度�点A运动点Q从点A同时出�以每秒2cm的速度�点C运动 sketch template

如图在 ABC中点D是AB边上的一点1请用尺规作图法在 ABC内求作∠ADE使∠ADE=∠BDE交AC于E不要求写作法 sketch template

如图，在菱形ABCD中，AB=AC=10，对角线AC、BD相交于点O，点M在线段AC上，且AM=3，点P为线段BD上的一个动点，则MP sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

3．如图在 ABC中∠ABC和∠ACB的角平分线相交于点O过点O 作EF∥BC交AB于E交AC于F若AB=18AC=16求 sketch template

题目如图等腰Rt ABC中∠ABC＝90°AB＝BC点AB分别在坐标轴上．1如图1若点C的横坐标为5直接写出点B的坐标 sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

14．如图在 ABC中∠B=90°两直角边AB=5BC=12三角形内有一点P到各边的距离相等求点P到各边的距离——青夏教育精英家教�—— sketch template

如图在 ABC中AB=AC∠BAC=90°直角∠EPF的顶点P是BC的中点两边PEPF分别交ABAC于点EF连接EF交AP于 sketch template

3．如图在 ABC中∠ABC和∠ACB的角平分线相交于点O过点O 作EF∥BC交AB于E交AC于F若AB=18AC=16求 sketch template

如图1所示已知 ABC中∠BAC=90°AB=ACAE是过点A的一条直线且B点和C点在AE的同侧BD⊥AE于D点CE⊥AE于E点 sketch template

如图在 ABC中∠ABC=90°以AB的中点O为圆心OA为半径的圆交AC于点DE是BC的中点连接DEOE．1判断DE与⊙O的 sketch template

free web stats