如图所示在rt abc中∠bac=90°ab=4ac=3adae分别是其角平分线和中线过点c作cg⊥ad于f交ab于g连接 Sketch Coloring Page

如图所示在rt abc中∠bac=90°ab=4ac=3adae分别是其角平分线和中线过点c作cg⊥ad于f交ab于g连接 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #5232 Avril by Teresa Temacha

anonymous

anonymous
sketch #5232 Avril by Teresa Temacha

sketch #3425 &#;Tonari no Kaibutsu-kun&#; by Betty Marie Melzer

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anonymous
sketch #3425 &#;Tonari no Kaibutsu-kun&#; by Betty Marie Melzer

sketch #2423

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anonymous
sketch #2423

sketch #5093 Pedro Henrique Jordan Coquet

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anonymous
sketch #5093 Pedro Henrique Jordan Coquet

sketch #2781

Smile Better
sketch #2781

sketch #4905 The Little Prince by Gaurav Patel

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anonymous
sketch #4905 The Little Prince by Gaurav Patel

sketch #4948 Snow White by George Lucaz

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sketch #4948 Snow White by George Lucaz

sketch #2573 homer simpson

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anonymous
sketch #2573 homer simpson

sketch #937

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anonymous
sketch #937

sketch #5134

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anonymous
sketch #5134

sketch #895

anonymous

anonymous
sketch #895

sketch #4589

anonymous

anonymous
sketch #4589

sketch #1328

anonymous

anonymous
sketch #1328

sketch #5139 Sick Sick Six Urs Stefan

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anonymous
sketch #5139 Sick Sick Six Urs Stefan

sketch #542 life

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anonymous
sketch #542 life

sketch #734 ytsfsfsdhgdhgf

Melissa Cogo
sketch #734 ytsfsfsdhgdhgf

sketch #5149 Daenerys Targaryen by Jorge Valero

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anonymous
sketch #5149 Daenerys Targaryen by Jorge Valero

sketch #4388 Homer and the Cherry

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anonymous
sketch #4388 Homer and the Cherry

sketch #2889

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anonymous
sketch #2889

sketch #4881

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anonymous
sketch #4881

sketch #3742 Homer by Koes Maung

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anonymous
sketch #3742 Homer by Koes Maung

sketch #3769 The Beatles by يآآسر محمد

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anonymous
sketch #3769 The Beatles by يآآسر محمد

sketch #2082 mash

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anonymous
sketch #2082 mash

sketch #1043 Deadoo..

Cherie N Patanao
sketch #1043 Deadoo..

sketch #3800

Fon Talesrunner
sketch #3800

sketch #3014 Fancy

James Forest
sketch #3014 Fancy "S "

sketch #3042 Tobi by Mirnes Sinanovic

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anonymous
sketch #3042 Tobi by Mirnes Sinanovic

sketch #3448 Treba mi bolji

anonymous

anonymous
sketch #3448 Treba mi bolji "mish " ;)

sketch #3662 Angel by Alexander Volodimirovich Danilchenko

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sketch #3662 Angel by Alexander Volodimirovich Danilchenko

sketch #2025

anonymous

anonymous
sketch #2025

tomski如图所示在rt abc中∠bac=90°ab=4ac=3adae分别是其角平分线和中线过点c作cg⊥ad于f交ab于g连接 coloring

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

题目如图Rt ABC中∠BAC=90°AB=3AC=6点DE分别是边BCAC上的动点则DA DE的最小值为．题目和参考 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图，在Rt ABC中，∠ABC=90°，AB=3，BC=4，在Rt MPN中，∠MPN=90°，点P在AC上，PM交AB于点E，PN交BC于 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图所示在Rt ABC中∠BAC=90°AB=4AC=3ADAE分别是其角平分线和中线过点C作CG⊥AD于F交AB于G连接 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠ACB=90°D是AB边上一点以BD为直径的⊙O与AC交于点E连接DE并延长与BC的延长线交于点FBD sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

如图在Rt ABC中∠BAC=90°AB=5AC=12P为边BC上一动点PE⊥AB于EPF⊥AC于FM为EF中点则AM的取值 sketch template

如图在Rt ABC中∠BAC=90°AB=3AC=4D为BC的中点则线段AD的长为 A．15B．2C．25D．3 题目和 sketch template

如图1所示已知 ABC中∠BAC=90°AB=ACAE是过点A的一条直线且B点和C点在AE的同侧BD⊥AE于D点CE⊥AE于E点 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图在Rt ABC中∠BAC=90°∠C=30°以边AC上一点O为圆心OA为半径作圆恰好经过边BC的中点D并与边AC相交于另一点 sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

已知如图在Rt ABC中∠C=90°以AC为直径作⊙O交AB于D过O作OE∥AB交BC于E．1求证ED是⊙O的切线．2 sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图所示在Rt ABC中AD平分∠BAC交BC于DCH⊥AB于H交AD于FDE⊥AB垂足为E求证四边形CFDE是菱形——青夏 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

21．如图所示在Rt ABC中∠BAC=90°AB=AC=2以AB为直径的圆交BC于D 求图形阴影部分的面积——青夏教育精英家教�—— sketch template

如图Rt ABC中∠BAC=90°以AB为直径作⊙O交BC于点DOE∥BC交AC于点E连接AD交OE于点F连接DE．1判断 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在Rt ABC中∠BAC=90°AB=3AC=4点P为BC边上一动点PE⊥AB于点EPF⊥AC于点F连结EF点M为EF的 sketch template

如图．在Rt ABC中．∠ACB=90°．∠ABC=30°AB=6．点D是BC边上一动点连接AD．将 ACD沿AD折叠．点C落在点C1处 sketch template

在Rt ABC中∠ACB=90°∠BAC=30°BC=6．I如图�将线段CA绕点C顺时针旋转30°所得到与AB交于点M则CM的 sketch template

如图所示在Rt ABC中AB=AC∠A=90°点D为BC上任一点DF⊥AB于FDE⊥AC于EM为BC的中点试判断 MEF是什么 sketch template

如图矩形ABCD中AB=6BC=8点E是BC边上一点连接AE把∠B沿AE折叠使点B落在点B′处当 CEB′为直角三角形时BE sketch template

如图Rt ABC中∠D=90°∠B=45°∠ACD=60°BC=10cm求AD的长．题目和参考答案——青夏教育精英家教�—— sketch template

如图所示在 ABC中D是BC边上一点∠1=∠2 ∠3=∠4∠BAC=63° 求∠DAC的度数——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

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