如图rt abc中∠c=90°o为ab上一点以o为圆心ob长为半径的圆交bc边于点d与ac边相切于点e．1求证be平分∠ Sketch Coloring Page

如图rt abc中∠c=90°o为ab上一点以o为圆心ob长为半径的圆交bc边于点d与ac边相切于点e．1求证be平分∠ Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #2884 Robot Shimun Yeyo Ahmed

anonymous

anonymous
sketch #2884 Robot Shimun Yeyo Ahmed

sketch #22

anonymous

anonymous
sketch #22

sketch #3765 Happy easter!

anonymous

anonymous
sketch #3765 Happy easter!

sketch #2309

anonymous

anonymous
sketch #2309

sketch #1034 what ever you want it to be

anonymous

anonymous
sketch #1034 what ever you want it to be

sketch #3118 Joker Hernan Da Costa Marquez

anonymous

anonymous
sketch #3118 Joker Hernan Da Costa Marquez

sketch #2359 imazighen amazigh flag

Amazigh N Amurwakuc
sketch #2359 imazighen amazigh flag

sketch #1504 donara

Donara Smbatyan
sketch #1504 donara

sketch #5261

anonymous

anonymous
sketch #5261

sketch #5368

anonymous

anonymous
sketch #5368

sketch #2476 Asuna from SAO by sketchmaster

sketchmaster
sketch #2476 Asuna from SAO by sketchmaster

sketch #2393

anonymous

anonymous
sketch #2393

sketch #4939 Zelda by Jeanie Wagenknecht

anonymous

anonymous
sketch #4939 Zelda by Jeanie Wagenknecht

sketch #3455 Enya by Georai Shahar

anonymous

anonymous
sketch #3455 Enya by Georai Shahar

sketch #5287

anonymous

anonymous
sketch #5287

sketch #2017 HEYOO

anonymous

anonymous
sketch #2017 HEYOO

sketch #3513

anonymous

anonymous
sketch #3513

sketch #137

Chris Shrimp Lonsdale
sketch #137

sketch #5217

anonymous

anonymous
sketch #5217

sketch #76

Rachel Roe
sketch #76

sketch #2874 Mario by Ahmed Hosny

anonymous

anonymous
sketch #2874 Mario by Ahmed Hosny

sketch #4945

anonymous

anonymous
sketch #4945

sketch #15

Tom Kelly
sketch #15

sketch #3505 Django

anonymous

anonymous
sketch #3505 Django

sketch #2431 face :D

anonymous

anonymous
sketch #2431 face :D

sketch #4522 Adventure Time by KiNg Buamir

anonymous

anonymous
sketch #4522 Adventure Time by KiNg Buamir

sketch #1095

anonymous

anonymous
sketch #1095

sketch #3157 umpa lumpa

anonymous

anonymous
sketch #3157 umpa lumpa

sketch #4152

Nujie C Nobita
sketch #4152

sketch #5343

anonymous

anonymous
sketch #5343

tomski如图rt abc中∠c=90°o为ab上一点以o为圆心ob长为半径的圆交bc边于点d与ac边相切于点e．1求证be平分∠ coloring

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图Rt ABC中∠C=90°O为AB上一点以O为圆心OB长为半径的圆交BC边于点D与AC边相切于点E．1求证BE平分∠ sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

如图在Rt ABC中∠ACB=90°CD是AB边上的中线DE⊥AB于点D交AC于点E．求证∠AED=∠DCB．题目和参考答案 sketch template

15．如图在 ABC中∠C=90°AB=10经过点C且与边AB相切的动圆与CACB分别交于点DE则线段DE长度的最小值是 sketch template

如图已知Rt ABC中∠ACB=90°BC=6AB=10以BC为直径的⊙O交AB于DACDO的延长线交于E点M为线段AC上一点 sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径．题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图，在Rt ABC中，∠ACB=90°，CB=4，CA=6， C半径为2，P为圆上一动点，连结AP，BP，则AP 12BP的最小值为（）A sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图Rt ABC中∠ABC＝90°以AB为直径的⊙O交AC于点DE是BC的中点连接DEOE．1判断DE与⊙O的位置关系并说明 sketch template

如图在等腰Rt ABC中∠BAC=90°AB=ACBC=2$sqrt{2}$点D是AC边上一动点连接BD以AD为直径的圆交BD sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图Rt ABC中∠BAC=90°以AB为直径作⊙O交BC于点DOE∥BC交AC于点E连接AD交OE于点F连接DE．1判断 sketch template

如图在Rt ABC中∠ACB=90°∠BAC=30°∠ACB的平分线与∠ABC的外角平分线交于E点连接AE则∠CEB是 A sketch template

如图 Rt ABC绕O点旋转90°得Rt BDE其中∠ACB=∠E= 90°AC=3DE=5 则OC的长为 A． B． C sketch template

如图在Rt ABC中∠ACB=90°AC=2．点DE分别在边BCAB上ED⊥BC以AE为半径的⊙A交DE的延长线于点F．1当 sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

10．如图在 ABC中AC=BC ∠C=90°BD为∠ABC的平分线若A点到直线BD的距离为a求BE的长——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°AC=6㎝BC=8㎝P为BC的中点．动点Q从点P出�沿射线PC方�以2㎝/s的速度运动以P为 sketch template

如图AB是⊙O的直径CD是⊙O上的两点若∠ABC=70°则∠BDC的度数为 A．50°B．40°C．30°D．20° 题目和参考 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图�在Rt ABC中已知∠A=90°AB=ACGF分别是ABAC上的两点且GF∥BCAF=2BG=4 1求梯形 sketch template

在Rt ABC中∠ACB=90°∠BAC=30°BC=6．I如图�将线段CA绕点C顺时针旋转30°所得到与AB交于点M则CM的 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

如图在Rt ABC中∠C=90°AC=8BC=6点DE分别在边ABAC上将 ADE沿直线DE翻折点A的对应点在边AB上联结 sketch template

如图AB是⊙O的直径C D E都是⊙O上的点则∠1 ∠2 = ——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠C=90°DE⊥ABAC=BE=15BC=20则四边形ACED的面积为 75 96——青夏教育精英家教�—— sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径．题目和参考答案——青夏教育精英家教�—— sketch template

如图线段AB经过圆心O交⊙O于点AC∠A=∠B=30º边BD交⊙O于点D试说明BD是⊙O的切线——青夏教育精英家教�—— sketch template

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