在rt abc中∠c=90°ab=12bdae是中线且bd和ae相交于g点则cg=4．题目和参考答案——青夏教育精英家教�—— Sketch Coloring Page

在rt abc中∠c=90°ab=12bdae是中线且bd和ae相交于g点则cg=4．题目和参考答案——青夏教育精英家教�—— Template

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anonymous

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sketch #1255 something

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sketch #5094 Squirrel by Mehdi Público

anonymous

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sketch #5094 Squirrel by Mehdi Público

sketch #2895 Hulk by Dmitry Cherepanin

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anonymous
sketch #2895 Hulk by Dmitry Cherepanin

sketch #5314

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sketch #2889

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sketch #5093 Pedro Henrique Jordan Coquet

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sketch #5093 Pedro Henrique Jordan Coquet

sketch #5279

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sketch #5054 Angelina Jolie by Hailey So Pretty

anonymous

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sketch #5054 Angelina Jolie by Hailey So Pretty

sketch #2477 hhhh

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sketch #2477 hhhh

sketch #4351

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sketch #5207 Gorilla by Jean-Benoit Renaud

anonymous

anonymous
sketch #5207 Gorilla by Jean-Benoit Renaud

sketch #1964 愛鼠繪

愛君
sketch #1964 愛鼠繪

sketch #2351

anonymous

anonymous
sketch #2351

sketch #1079

anonymous

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sketch #4370 Breaking Bad

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sketch #4370 Breaking Bad

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sketch #5063 Super Meat Boy by Alexander Volodimirovich Danilchenko

anonymous

anonymous
sketch #5063 Super Meat Boy by Alexander Volodimirovich Danilchenko

sketch #5369 Wolverine by ShopRasta Roots

anonymous

anonymous
sketch #5369 Wolverine by ShopRasta Roots

sketch #2884 Robot Shimun Yeyo Ahmed

anonymous

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sketch #2884 Robot Shimun Yeyo Ahmed

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Laura Agapi Asnicar
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sketch #1385 fingerschpitsengeful

anonymous

anonymous
sketch #1385 fingerschpitsengeful

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Laura Agapi Asnicar
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sketch #2643 Spring chick

Rachel Roe
sketch #2643 Spring chick

sketch #2899 Snoopy by Rhemzkian Esturco

anonymous

anonymous
sketch #2899 Snoopy by Rhemzkian Esturco

sketch #5064

anonymous

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tomski在rt abc中∠c=90°ab=12bdae是中线且bd和ae相交于g点则cg=4．题目和参考答案——青夏教育精英家教�—— coloring

16．在Rt ABC中∠C=90°三角形的面积为则斜边长是 SinA=——青夏教育精英家教�—— sketch template

已知在 ABC中∠BAC=90°AB=ACAE是过点A的一条直线且BD⊥AE于DCE⊥AE于E．1当直线AE处于如图�的位置时 sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

在Rt ABC中∠ACB=90°AC=BCD为直线AC上一点直线AE⊥直线BD垂足为E直线AE和直线BC交于点H过点C作AB的 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

在Rt ABC中∠C=90°AB的垂直平分线交BC边于D∠B=2∠DAC则∠B的度数为 A．18°B．54°C．36°D．72 sketch template

如图1在Rt ABC中∠ACB=90°∠B=60°D为AB的中点∠EDF=90°DE交AC于点GDF经过点C．1求∠ADE的 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠C=90°AB=10cmAC=6cm动点P从点B出�沿射线BC以2cm/s的速度移动设运动的时间为t秒．1 sketch template

在Rt ABC中∠C=90°AB=12BDAE是中线且BD和AE相交于G点则CG=4． 题目和参考答案——青夏教育精英家教�—— sketch template

在Rt ABC中∠C=90°∠BAC的角平分线AD交BC于点DCD=2则点D到AB的距离是 A1B2C3D4 题目和参考 sketch template

如图在 ABC中∠C=90°DE是AB的中垂线分别交ABBC于点DE若∠B=30°BC=10则CE= ． 题目和参考答案 sketch template

在Rt ABC中∠C=90°BC=3AB=5则sinA= ． 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示在Rt ABC中∠BAC=90°AB=4AC=3ADAE分别是其角平分线和中线过点C作CG⊥AD于F交AB于G连接 sketch template

在Rt ABC中∠C=90°∠BAC的角平分线AD交BC于点DCD=2则点D到AB的距离是A3B4C2D1——青夏教育精英家教�—— sketch template

在Rt ABC中∠ACB等于90°∠ABC等于30°AC=1将 ABC绕点A逆时针旋转至 AB′C′使得点AC′恰好落在斜边AB上 sketch template

如图在Rt ABC中∠C=90°∠BAC的角平分线AD交BC于点D若AC=5BC=12．求点D到AB的距离． 题目和参考答案——青夏 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

Rt ABC中∠C=90°它的内切圆O分别与ABBCCA相切于DEF且BD=6AD=4则是⊙O的半径是A6B4C3D sketch template

如图1所示在Rt ABC中∠C=90°点D是线段CA延长线上一点且AD=AB．点F是线段AB上一点连接DF以DF为斜边作等腰Rt sketch template

如图1所示在Rt ABC中∠C=90°点D是线段CA延长线上一点且AD=AB．点F是线段AB上一点连接DF以DF为斜边作等腰Rt sketch template

题目如图 ABC中∠ACB＝90°∠A＝30°AC＝6点P在边AB上运动点P关于直线ACBC对称的点分别为P1P2．则在点 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图在Rt ABC中∠ACB=90°AC=BC∠ABC=45°点D为BC的中点CE⊥AD于点E其延长线交AB于点F连接DF sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

已知如图在 ABC中∠C=90°∠B=30°AC=6点D在边BC上AD平分∠CABE为AC上的一个动点EF⊥AB垂足为F sketch template

如图在Rt ABC中∠C=90°AC=8BC=6点DE分别在边ABAC上将 ADE沿直线DE翻折点A的对应点在边AB上联结 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图在Rt ABC中∠ACB=90°AB的垂直平分线DE交AC于E交BC的延长线于F若∠F=30°DE=1则BE的长是 ． 题目 sketch template

已知Rt ABC中∠C=90°若a B=14cmc=10cm则Rt ABC的面积是 A24cm2B36cm2C48cm2D sketch template

如图在 ABC中∠C=90°AB的垂直平分线DE分别交BCAB于点DEAD平分∠BAC．1写出图中相等的线段并说明相等的 sketch template

在Rt ABC中∠C=90°AB=3BC=1则tanA= ——青夏教育精英家教�—— sketch template

如图Rt ABC中∠ACB=90°．1分别以ABAC为边�外作等边三角形ABD和等边三角形ACE连接CE交AB于点F若∠BAC sketch template

已知如图在Rt ABC中∠C=90°点O在AB上以O为圆心OA长为半径的圆与ACAB分别交于点DE且∠CBD=∠A．1 sketch template

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