题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Sketch Coloring Page

题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Template

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tomski题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 coloring

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

如图1Rt ABC中∠C=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数． 题目和参考答案——青夏 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图在 ABC中DE∥BC且AD=3DB=2．写出图中的相似三角形并指出其相似比． 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形ABC中BDDC=12E为AD的中点若三角形ABC的面积为120平方厘米则阴影部分的面积是多�平方厘米 题目和参考 sketch template

如图在三角形ABC中D为 BC的中点 AF=2BFCE=3AE连接CF交 DE于 P点求EPDP的值． 题目和参考答案——青夏教育 sketch template

如图在直角三角形ABC中∠BAC=90°将 ABC沿直线BC�右平移得到 DEF连结ADAE则下列结论中不成立的是 A．AD∥ sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

如图已知在 ABC中AD是BC边上的中线E是AD上一点且BE=AC延长BE交AC于点F。求证AF=EF。百度教育 sketch template

百度教育 sketch template

如图中三角形ABC的面积是平行四边形DBCE面积的 A．一半 B．2倍 C．相等 题目和参考答案——青夏教育精英家教�—— sketch template

如图，在等边三角形ABC中，点D，E分别是边BC，CA上的点，且BD=CE，连结AD，BE交于点P．（1）求证： ABE≌ CAD；（2）连接 sketch template

如图在三角形纸片ABC中AC＝BC．把 ABC沿着AC翻折点B落在点D处连接BD如果∠BAD＝80°则∠CBD的度数为 °． 题目 sketch template

如图在三角形ABC中点DF在边BC上点E在边AB上点G在边AC上∠CDG=∠B∠1 ∠FEA=180°．证明AD∥EF． 题目 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为百度教育 sketch template

如图，在三角形ABC中已知∠ A = 90° ∠ C 60° 。把三角形ABC绕点B按顺时针方�旋转一定的角度后，得到三角形A B sketch template

如图三角形ABC中E为AC之中点．BD=2DCAD与BE交于F则三角形BDF的面积四边形DCEF的面积=8787． 题目和参考答案 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

百度教育 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

如图在正三角形ABC中DEF分别为各边的中点GHIJ分别为AFADBEDE的中点．将 ABC沿DEEFDF折成三棱锥 sketch template

如图在三角形ABC中BC=8厘米AD=6厘米EF分别为AB和AC的中点．那么三角形EBF的面积是66平方厘米．——青夏教育精英家教�—— sketch template

百度教育 sketch template

题目如图在等腰直角三角形ABC中∠ABC=90°D为AC边上的中点过D点作DE⊥DF交AB于点E交BC于点F若AE=8FC sketch template

百度教育 sketch template

如图 ABC是等边三角形分别延长CAABBC到A′B′C′使AA′=BB′=CC′=AC若 ABC的面积为1则 A′B′C sketch template

如图等边三角形ABC中DE分别为ABBC边上的两个动点且总使BD=CEAE与CD交于点FAG⊥CD于点G则以下结论∠AFG sketch template

百度教育 sketch template

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