题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Sketch Coloring Page

题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 Template

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tomski题目：如图，在三角形abc中，点d是ab的中点，∠dac=2∠dca，∠dcb=30度，求∠b的度数知乎 coloring

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

利用三角形中位线求线段长度 知乎 sketch template

如图在三角形ABC中BE=EF=FCED=2DA求阴影部分的面积是三角形ABC面积的几分之几 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数． 题目和参考答案——青夏 sketch template

这道解三角形的题目有什么简便方法？ 知乎 sketch template

百度教育 sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

百度教育 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

如图1Rt ABC中∠C=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 sketch template

已知在三角形abc中知识要点北京爱智康 sketch template

题目如图 ABC是等边三角形AB=点D是边BC上一点点H是线段AD上一点连接BHCH．当∠BHD=60°∠AHC=90°时 sketch template

百度教育 sketch template

如图在三角形ABC中D点为AB的中点E点为BC的中点F点为BE的中点已知三角形DCF面积为63平方厘米则三角形ABC面积为多�平方 sketch template

三角形重心的性质及其证明 知乎 sketch template

如图在 ABC中AB=AC∠A=36°请你设计三种不同的方法将 ABC分割成三个等腰三角形不要求写出画法不要求证明但是要标出所 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为百度教育 sketch template

如图在三角形ABC中点DF在边BC上点E在边AB上点G在边AC上∠CDG=∠B∠1 ∠FEA=180°．证明AD∥EF． 题目 sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

已知如图在等边三角形ABC中MN分别是ABAC的中点D是MN上任意一点CDBD的延长线分别与ABAC交于FE若1CE sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

百度教育 sketch template

7分如图在 ABC中∠BAC=60°AE是 ABC中与∠BAC相邻的外角的平分线且AE∥BC则 ABC是等边三角形吗为什么百度教育 sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

百度教育 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

如图在正三角形ABC中DEF分别为各边的中点GHIJ分别为AFADBEDE的中点．将 ABC沿DEEFDF折成三棱锥 sketch template

如图在 ABC中DE∥BC且AD=3DB=2．写出图中的相似三角形并指出其相似比． 题目和参考答案——青夏教育精英家教�—— sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

百度教育 sketch template

如图在 ABC中点DE分别在边ACAB上BD与CE交于点O给出下列四个条件�∠EBO=∠DCO�BE=CD�OB=OC sketch template

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