已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 Sketch Coloring Page

已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 Template

Background image: Hide Show

View Larger Image Image Credit: zhihu.com

please wait, the page is loading...

More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #1440 donara

Donara Smbatyan
sketch #1440 donara

sketch #2359 imazighen amazigh flag

Amazigh N Amurwakuc
sketch #2359 imazighen amazigh flag

sketch #3344 Homer by Samuel Roberto

anonymous

anonymous
sketch #3344 Homer by Samuel Roberto

sketch #5150 Regina from Dino Crisis by Hsien-Ying Hsieh

anonymous

anonymous
sketch #5150 Regina from Dino Crisis by Hsien-Ying Hsieh

sketch #1652

anonymous

anonymous
sketch #1652

sketch #5095 Lion by Frederic Knauer

anonymous

anonymous
sketch #5095 Lion by Frederic Knauer

sketch #5262

anonymous

anonymous
sketch #5262

sketch #1455 donara

Donara Smbatyan
sketch #1455 donara

sketch #2308

anonymous

anonymous
sketch #2308

sketch #5351

anonymous

anonymous
sketch #5351

sketch #2144

anonymous

anonymous
sketch #2144

sketch #5069 Mad Hatter by Ahmed Mostafa

anonymous

anonymous
sketch #5069 Mad Hatter by Ahmed Mostafa

sketch #4868 Pokemons! by Ammed Hjb

anonymous

anonymous
sketch #4868 Pokemons! by Ammed Hjb

sketch #3258

anonymous

anonymous
sketch #3258

sketch #4386 Freddie Mercury by Павел Павлов

anonymous

anonymous
sketch #4386 Freddie Mercury by Павел Павлов

sketch #3695

Mahmed Alhaj
sketch #3695

sketch #4899

anonymous

anonymous
sketch #4899

sketch #2434 Metallica

sketchmaster
sketch #2434 Metallica

sketch #1923 12

anonymous

anonymous
sketch #1923 12

sketch #1504 donara

Donara Smbatyan
sketch #1504 donara

sketch #3639

anonymous

anonymous
sketch #3639

sketch #2644 Purple bun

Rachel Roe
sketch #2644 Purple bun

sketch #4479

Hank Henry Armstrong
sketch #4479

sketch #5211

anonymous

anonymous
sketch #5211

sketch #3489 Panda by Scott Terry

anonymous

anonymous
sketch #3489 Panda by Scott Terry

sketch #3052

anonymous

anonymous
sketch #3052

sketch #5212 Katy Perry by Shahid Khokhar

anonymous

anonymous
sketch #5212 Katy Perry by Shahid Khokhar

sketch #4742

anonymous

anonymous
sketch #4742

sketch #3362 The Boss by David Torre

anonymous

anonymous
sketch #3362 The Boss by David Torre

sketch #3499 Alien Laura Gutierrez Hinojosa

anonymous

anonymous
sketch #3499 Alien Laura Gutierrez Hinojosa

tomski已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数知乎 coloring

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知在三角形abc中知识要点北京爱智康 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

三角形中线的定理？ 知乎 sketch template

【中考提升�初中数学平面几何压轴题6大模型及解题方法 知乎 sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

百度教育 sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

已知 ABC中AB=AC∠BAC=α DBC为等边三角形．1如图1∠ABD= 2如图2若∠BCE=150°∠ABE=60 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

在三角形ABC中点O是AC边上一个动点过点O作MN∥BC设MN交∠BCA的平分线于点E交 ABC的外角∠ACD平分线于点E．1求证 sketch template

如图所示已知三角形ABC中∠BAC为钝角． 1画出点C到AB的垂线段 2过A点画BC的垂线 3点B到AC的距离是多� sketch template

百度教育 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

已知在等边三角形ABC中DE分别为ABAC上的点且BD=AEEB与CD相交于点OEF⊥CD于点F．求证OE=2OF．题目和参考 sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

如图已知等边三角形ABC在BC的延长线上取一点E以CE为边作等边三角形DCE连接AEBD．点M是BD的中点点N是AE的中点．1在图 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

26．如图已知 ABC中DE分别是ACAB上的点BD与CE相交于点O给出下列三个条件 �∠EBO=∠DCO �∠BEO=∠CDO sketch template

如图在三角形纸片ABC中AB=6BC=8AC=4．沿虚线剪下的涂色部分的三角形与 ABC相似的是ABCD 题目和参考答案——青 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

19．已知如图7等腰三角形ABC中AB=AC=4若以AB为直径的⊙O与BC相交于点DDE∥ABDE与AC相交于点E则DE sketch template

百度教育 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

如图在 ABC中已知点DE分别在ABAC上BE与CD相交于点O依据下列各个选项中所列举的条件不能说明AB=AC的是 A．BE sketch template

连结三角形两边中点的线段叫做三角形的中位线如图�，在 ABC 中，D，E分别是AB，AC的中点，DE 就是 的一条中位线 �们可 sketch template

如图已知在 ABC中AB=ACD为BC边的中点过点D作DE⊥ABDF⊥AC垂足分别为EF．1求证 BED≌ CFD2 sketch template

百度教育 sketch template

free web stats