已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 Sketch Coloring Page

已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 Template

Background image: Hide Show

View Larger Image Image Credit: zhihu.com

please wait, the page is loading...

More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #1440 donara

Donara Smbatyan
sketch #1440 donara

sketch #1973

Daniel Lachman
sketch #1973

sketch #5161

anonymous

anonymous
sketch #5161

sketch #4566 Edward Scissorhands by Angel Ördoñez

anonymous

anonymous
sketch #4566 Edward Scissorhands by Angel Ördoñez

sketch #5198 Sakura Claudio Pose Jester Genso

anonymous

anonymous
sketch #5198 Sakura Claudio Pose Jester Genso

sketch #5204

anonymous

anonymous
sketch #5204

sketch #5346

anonymous

anonymous
sketch #5346

sketch #2150 batman

anonymous

anonymous
sketch #2150 batman

sketch #1079

anonymous

anonymous
sketch #1079

sketch #2582

anonymous

anonymous
sketch #2582

sketch #3505 Django

anonymous

anonymous
sketch #3505 Django

sketch #474 waa

anonymous

anonymous
sketch #474 waa

sketch #3273

anonymous

anonymous
sketch #3273

sketch #5440

anonymous

anonymous
sketch #5440

sketch #4012 Owl sketch

anonymous

anonymous
sketch #4012 Owl sketch

sketch #4532

anonymous

anonymous
sketch #4532

sketch #1668 SUNSET

anonymous

anonymous
sketch #1668 SUNSET

sketch #5119

anonymous

anonymous
sketch #5119

sketch #90 JF Style!

Jaroslav Florian
sketch #90 JF Style!

sketch #4549

anonymous

anonymous
sketch #4549

sketch #5062

anonymous

anonymous
sketch #5062

sketch #1446

anonymous

anonymous
sketch #1446

sketch #2904 Pinky and the Brain by Tim Poole

anonymous

anonymous
sketch #2904 Pinky and the Brain by Tim Poole

sketch #68512

anonymous

anonymous
sketch #68512

sketch #5315

anonymous

anonymous
sketch #5315

sketch #5084 Harry Potter by Enrique L. Manly

anonymous

anonymous
sketch #5084 Harry Potter by Enrique L. Manly

sketch #937

anonymous

anonymous
sketch #937

sketch #970 Depression

anonymous

anonymous
sketch #970 Depression

sketch #4287 eye

anonymous

anonymous
sketch #4287 eye

sketch #334 DON 'T!

anonymous

anonymous
sketch #334 DON 'T!

tomski已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 coloring

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

【中考提升�初中数学平面几何压轴题6大模型及解题方法 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

三角形中线的定理？ 知乎 sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

已知如图 ABC中∠BAC=90ºAB=ACD为AC的中点AE⊥BD交BC于E试说明∠ADB=∠CDE提示做CG⊥AC sketch template

如图已知 ABC中AB=ACM是BC的中点DE分别是ABAC边上的点且BD=CE1求证MD=ME．2若D为AB的 sketch template

已知如图在 ABC中AB=AC延长BC到D使BD=2BC连接AD过C作CE⊥BD交AD于点E连接BE交AC于点O．1求证 sketch template

记 ABC的内角ABC的对边分别为abc已知 =ac点D在边AC 上BDsin∠ABC=asinC1证明BD = B sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

已知 ABC中AB=AC∠BAC=90° ABD为等边三角形E是BD中点AECD相交于O点．1求∠DCB的度数2求证 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

三角形“四心”有关性质及证明（内心篇） 知乎 sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

定理等腰三角形的两个底角相等．请写已知求证并证明．已知 ABC中AB=AC求证∠B=∠C．证明题目和参考答案——青夏教育精英 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

百度教育 sketch template

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

已知如图在等边三角形ABC中MN分别是ABAC的中点D是MN上任意一点CDBD的延长线分别与ABAC交于FE若1CE sketch template

已知等边三角形ABC中延长AC到F使得ED=DF求证BE=CF——青夏教育精英家教�—— sketch template

20．已知三角形ABC A C 现将∆ABC平移使点A到位置A’处则点BC对应的坐标分别为 B’C’ ——青夏教育精英家教�—— sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

题目1问题如图1在Rt ABC中∠BAC＝90°AB＝ACD为BC边上一点不与点BC重合将线段AD绕点A逆时针旋转90 sketch template

百度教育 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

19．已知如图7等腰三角形ABC中AB=AC=4若以AB为直径的⊙O与BC相交于点DDE∥ABDE与AC相交于点E则DE sketch template

在Rt ABC中∠ACB等于90°∠ABC等于30°AC=1将 ABC绕点A逆时针旋转至 AB′C′使得点AC′恰好落在斜边AB上 sketch template

free web stats