已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Sketch Coloring Page

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Template

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tomski已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 coloring

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

四棱锥图片直观图三棱锥和四棱锥图片四棱锥图片素描图片大山谷图库 sketch template

四棱锥三视图图片千图� sketch template

四棱锥图片三视图 千图� sketch template

一个四棱锥的底面为正方形其直观图与三视图如图所示则二面角P DC A的正弦值为 ABCD——青夏教育精英家教�—— sketch template

7．一个四棱锥的底面为正方形其三视图如图所示则这个四棱锥的体积是 A． B． C． D．——青夏教育精英家教�—— sketch template

四棱锥三视图图片五棱锥三视图图片一个正四棱锥的三视图第2页大山谷图库 sketch template

四棱锥俯视图正四棱锥的俯视图正视图侧视图俯视图 大山谷图库 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

湖南省新田一中高中数学 1 棱柱、棱锥、棱台的结构特征课时作业 Word文档在线阅读与下载免费文档 sketch template

一个三棱锥的三视图如图所示则该三棱锥的体积是 A4 B C D8——青夏教育精英家教�—— sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

如图1由正四棱锥P ABCD和正四棱柱ABCD A1B1C1D1所组成的几何体的三视图如图2．1求证PC⊥平面A1BD2求点P到 sketch template

已知如图三棱锥P ABC中AP=ACPB=2将此三棱锥沿三条侧棱剪开其展开图是一个直角梯形P1P2P3A． 1求证侧棱PB sketch template

四棱锥的侧视图四棱锥的三视图正视图侧视图俯视图第7页大山谷图库 sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

一个四棱锥的三视图如图所示其中主视图是腰长为1的等腰直角三角形则这个几何体的体积是 A．12B．1C．32D．2——青夏教育精英家教�—— sketch template

四棱柱三视图图片正三棱锥三视图四棱柱图片大山谷图库 sketch template

一个四棱锥的三视图如图所示其中主视图是腰长为1的等腰直角三角形则这个几何体的体积是 A．12B．1C．32D．2——青夏教育精英家教�—— sketch template

高考数学一轮复习题组层级快练49含解析 Word文档在线阅读与下载文档� sketch template

四棱锥的俯视图四棱锥的三视图四棱锥的侧视图第2页大山谷图库 sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

【与名师对话�高考数学总复习 8 1 空间几何体的结构特征及三视图和直观图配套课时作业理新人教A版 Word文档在线阅读与下载无忧文档 sketch template

12．如图所示在四棱锥P ABCD中底面ABCD是矩形PA＝AB＝2BC＝a又侧棱PA⊥底面ABCD 1当a为何值时BD⊥ sketch template

由四棱柱ABCD A1B1C1D1截去三棱锥C1 B1CD1后得到的几何体如图所示四边形ABCD为正方形O为AC与BD 的交点E为AD的 sketch template

四棱锥展开图 千图� sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

四棱锥截面图 千图� sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

$如图所示四棱锥P ABCD中PA⊥平面ABCDPB与底面所成的角为$frac{π}{4}$底面ABCD为直角梯形∠ABC=∠BAD sketch template$

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