如图�在rt abc中∠c=90°．将 abc绕点c逆时针旋转得到 A′b′c旋转角为α且0°＜α＜180°．在旋转过程中点b′可以 Sketch Coloring Page

如图�在rt abc中∠c=90°．将 abc绕点c逆时针旋转得到 A′b′c旋转角为α且0°＜α＜180°．在旋转过程中点b′可以 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #3749 Girl Ari Rainbow

anonymous

anonymous
sketch #3749 Girl Ari Rainbow

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anonymous

anonymous
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anonymous

anonymous
sketch #5182 Inuyasha by Sepp Herberger

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sketchmaster
sketch #2635 Zoidberg by sketchmaster

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anonymous

anonymous
sketch #3226 Goth Face

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anonymous

anonymous
sketch #2283 Head in a shoe

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anonymous

anonymous
sketch #5114 Doraemon by Carrieann Benthem

sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

anonymous

anonymous
sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

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anonymous

anonymous
sketch #4546 Misaki Mei by Wanis Khelifa

sketch #1447 donara

Donara Smbatyan
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anonymous

anonymous
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sketch #5202 The Woman by Céline Chalois

anonymous

anonymous
sketch #5202 The Woman by Céline Chalois

sketch #3562 Angry by Leon Soria Ricardo

anonymous

anonymous
sketch #3562 Angry by Leon Soria Ricardo

sketch #804

Laura Agapi Asnicar
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sketch #4298

anonymous

anonymous
sketch #4298

sketch #4688

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sketch #4688

sketch #4695

anonymous

anonymous
sketch #4695

sketch #4942 Woman by Abbie Hayman

anonymous

anonymous
sketch #4942 Woman by Abbie Hayman

sketch #859 meyvalar

anonymous

anonymous
sketch #859 meyvalar

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anonymous

anonymous
sketch #5161

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anonymous

anonymous
sketch #1328

sketch #2765 Kratos by Nassim Nouri

Nassim Nouri
sketch #2765 Kratos by Nassim Nouri

sketch #4965

anonymous

anonymous
sketch #4965

sketch #5170

anonymous

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sketch #5170

sketch #5340 Amazing Dragon

anonymous

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sketch #5340 Amazing Dragon

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sketch #2446 Joker by sketchmaster

sketchmaster
sketch #2446 Joker by sketchmaster

tomski如图�在rt abc中∠c=90°．将 abc绕点c逆时针旋转得到 coloring

如图Rt ABC中∠C=90°O为AB上一点以O为圆心OB长为半径的圆交BC边于点D与AC边相切于点E．1求证BE平分∠ sketch template

如图在Rt ABC中∠C=90°点O在AB上经过点A的⊙O与BC相切于点D与ACAB分别相交于点EF连接AD与EF相交于点G sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

已知如图在Rt ABC中∠C=90°以AC为直径作⊙O交AB于D过O作OE∥AB交BC于E．1求证ED是⊙O的切线．2 sketch template

在Rt ABC中∠C=90°AB的垂直平分线交BC边于D∠B=2∠DAC则∠B的度数为 A．18°B．54°C．36°D．72 sketch template

如图在Rt ABC中∠C=90°．1根据要求用尺规作图过点C作斜边AB边上的高CD垂足为D不写作法只保留作图痕迹2证明 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图，在Rt ABC中，∠ACB=90°，AC=3，BC=1，将 ABC绕点A逆时针方�旋转90°，得到 AB′C′．连接BB′，交AC于点D sketch template

已知如图在Rt ACB中∠C=90°AC=4cmBC=3cm．点P由B出�沿BA方��点A匀速运动点Q由A出�沿AC方��点C匀速 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图6在Rt ABC中 ∠C＝90°BD是∠ABC的平分线交AC于D若CD＝4AB＝8则 ABD的面积是 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图在Rt ABC中∠C=90°AC=6∠A的平分线交BC于点DDE⊥AB于点E且BE=4求DE的长．题目和参考答案——青夏 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图在Rt ABC中∠B=90°BC=6∠C=30°点D从点C出�沿CA方�以每秒2个单位长的速度�点A匀速运动同时点E从点A出� sketch template

如图在Rt ABC中∠A =90°AC =6cmAB=8cm把AB边翻折使AB边落在BC边上点A落在点E处折痕为BD则sin sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图 Rt ABC绕O点旋转90°得Rt BDE其中∠ACB=∠E= 90°AC=3DE=5 则OC的长为 A． B． C sketch template

如图在Rt ABC中∠ACB=90°∠A=60°AC=1将 ABC绕点C顺时针旋转得 A1B1C1且点A1落在边AB边上取BB1 sketch template

如图�在Rt ABC中∠C=90°．将 ABC绕点C逆时针旋转得到 A′B′C旋转角为α且0°＜α＜180°．在旋转过程中点B′可以 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

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