如图在斜三棱柱abc A1b1c1中侧面abb1a1⊥底面abc侧棱aa1与底面abc成60°的角aa1=2．底面abc是边长为2的正 Sketch Coloring Page

如图在斜三棱柱abc A1b1c1中侧面abb1a1⊥底面abc侧棱aa1与底面abc成60°的角aa1=2．底面abc是边长为2的正 Template

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tomski如图在斜三棱柱abc a1b1c1中侧面abb1a1⊥底面abc侧棱aa1与底面abc成60°的角aa1=2．底面abc是边长为2的正 coloring

已知斜三棱柱ABC A1B1C1的侧面A1ACC1与底面ABC垂直∠ABC＝90°BC＝2AC＝2且AA1⊥A1CAA1＝A1C sketch template

斜三棱柱ABC A1B1C1中底面是边长为a的正三角形侧棱长为bAA1与底面相邻两边ABAC都成450求棱柱的侧面积——青夏教育 sketch template

4．如图在斜三棱柱ABC A1B1C1中侧面AA1B1B⊥底面ABC侧棱AA1与底面ABC成60°的角AA1=2底面ABC是边长为2 sketch template

如图在斜三棱柱ABC A1B1C1中侧面ABB1A1⊥底面ABC侧棱AA1与底面ABC成60°的角AA1=2．底面ABC是边长为2的正 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

斜三棱柱ABC A1B1C1的底面是边长为2的正三角形侧棱长为2侧棱AA1和底面相邻两边ABAC都成45°角求全面积和体积题目和 sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

如图在三棱柱ABC A1B1C1中 ABC为等边三角形侧棱AA1⊥平面ABCAB=2AA1=23DE分别为AA1BC1的中点 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

如图斜三棱柱中面是菱形侧面 求证1 2求点到平面的距离——青夏教育精英家教�—— sketch template

斜三棱柱ABC A1B1C1的底面是边长为2的正三角形顶点A1在底面的射影O是 ABC的中心异面直线AB与CC1所成的角为45° 1 sketch template

在体积为15的斜三棱柱ABC A1B1C1中S是C1C上的一点S ABC的体积为3则三棱锥S A1B1C1的体积为 A．1 B sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

如图正三棱柱ABC A1B1C1的九条棱均相等D是BC上一点AD⊥C1D 1求证截面ABC1⊥侧面BCC1B1 2求 sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

如图在三棱柱ABC A1B1C1中B1B⊥平面A1B1C1AC=CB=CC1=2∠ACB=90°DE分别是A1B1CC1的中点 sketch template

【题文�如图，在直三棱柱ABC－A1B1C1中，，AC＝3，BC＝4，AA1＝4，点D是AB的中点，（1）求证：AC⊥BC1；（2）求证 sketch template

已知斜三棱柱ABC A1B1C1的底面为正三角形侧面A1ACC1为菱形∠A1AC=60°且平面A1ACC1⊥平面ABCM是C1C的中点 sketch template

如图，已知正三棱柱ABC A 1B 1C 1的所有棱长都为2，D为CC 1中点，E为BC的中点（1）求证：BD⊥ 平面AB 1E；（2）求三 sketch template

如图已知正三棱柱ABC A1B1C1的各条棱长均为2M是BC的中点．Ⅰ求证A1C∥平面AB1MⅡ求证在棱CC1上找一点N使得 sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

如图，在直三棱柱ABC—A1B1C1中，∠ACB＝90°，∠BAC＝30°，BC＝1，AA1＝，M是棱CC1的中点． 1 求证：A1B⊥ sketch template

百度教育 sketch template

2019年高考数学二轮复习对点练：专题五立体几何专题对点练16 Word版含答案 Word文档在线阅读与下载无忧文档 sketch template

如图所示在直三棱柱ABC A1B1C1中AB＝1AC＝AA1＝∠ABC＝60° 1证明AB⊥A1C 2求二面角A A1C sketch template

如图在正三棱柱ABC 中AB=1点D在棱上BD=1若AD与平面BC所成的角为a则sina= ——青夏教育精英家教�—— sketch template

9．在斜三棱柱ABC A1B1C1中A0B0分别为侧棱AA1BB1上的点且知BB0B0B1=32过A0B0C1的截面将三 sketch template

如图在直三棱锥ABC A1B1C1中AC=BC=AA1∠ACB=90°EF分别是ABBC的中点G是AA1上的点若一个三棱锥的三 sketch template

百度教育 sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

斜三棱柱ABC A1B1C1中底面是边长为a的正三角形侧棱长为bAA1与底面相邻两边ABAC都成450求棱柱的侧面积——青夏教育 sketch template

如图斜三棱柱中面是菱形侧面 求证1 2求点到平面的距离——青夏教育精英家教�—— sketch template

17．来源 在斜三棱柱中侧面平面 I求证 II若是棱上的两个三等分点求证平面——青夏教育精英家教�—— sketch template

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