如图 Abe是边长为21的正三角形．已知四边形bcde的�长是 Abe�长的两倍．则五边形abcde的�长是a137b147c157d Sketch Coloring Page

如图 Abe是边长为21的正三角形．已知四边形bcde的�长是 Abe�长的两倍．则五边形abcde的�长是a137b147c157d Template

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tomski如图 abe是边长为21的正三角形．已知四边形bcde的�长是 abe�长的两倍．则五边形abcde的�长是a137b147c157d coloring

如图 ABE是边长为21的正三角形．已知四边形BCDE的�长是 ABE�长的两倍．则五边形ABCDE的�长是A137B147C157D sketch template

三角形中线的定理？知乎 sketch template

三角形边长关系 三角形求边长计算公式随意贴 sketch template

浅谈完全四边形性质知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数知乎 sketch template

�们把边长和面积都是整数的三角形叫作整数三角形例如边长分别为345的直角三角形其面积为6是一个整数三角形． 1你能再举几个例子 sketch template

【初中数学�特殊角度的直角三角形（30度、45度）知乎 sketch template

正五边形的尺规做法推导知乎 sketch template

如图在直角三角形ABC中放置边长分别34x的三个正方形则x的值为 ．题目和参考答案——青夏教育精英家教�—— sketch template

数学课上同学们探究�现如图1顶角为36°的等腰三角形具有一种特性即经过它某一顶点的一条直线可把它分成两个小等腰三角形 并且对其进行了 sketch template

如图所示三角形abc是边长为1的正三角形 三角形bdc是顶角为120度的等腰三角形 以d为顶点做一个60是度的角m 百度知道 sketch template

如图已知正三角形ABC的边长为1EFG分别是ABBCCA上的点且AE=BF=CG设 EFG的面积为yAE的长为x则y关于x sketch template

如图直角三角形ABC的三边分别为3cm4cm5cm将这个直角三角形以一条直角边所在的直线为轴旋转一�求所形成的立体图形的体积——青夏 sketch template

设 ABC的内角ABC所对的边分别为abc且2bcosC=2a C．1求角B的大小2若b=1求a C的最大值．题目和 sketch template

定义三边长和面积都是整数的三角形称为“整数三角形 ．数学学习小组的同学从32根等长的火柴棒中取出若干根首尾依次相接组成三角形进行探究活动 sketch template

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

百度教育 sketch template

如图在 ABC中AB=AC∠A=36°请你设计三种不同的方法将 ABC分割成三个等腰三角形不要求写出画法不要求证明但是要标出所 sketch template

如图在三棱锥S ABC中底面ABC是边长为4的正三角形侧面SAC⊥底面ABCSA=SC=23MN分别为ABSB的中点．Ⅰ求证 sketch template

正五边形的尺规做法推导知乎 sketch template

如图已知正方形ABCD以CD为边�外作等边三角形CDEBE与AC相交于点F求证EF=CF BF 百度教育 sketch template

如图矩形ABCDE为BC边上一点将 ABE沿AE对折使点B的对应点F落在边DC上若∠DAF=20°则∠FBE的度数是 A．20 sketch template

如图等边三角形ABC的边长为6A、B、A1三点在一条直线上且 ABC≌ A1BC1若D为线段BC1上一动点则AD CD的最小值是 sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

如图四边形ABCD是菱形且∠ABC=60° ABE是等边三角形M为对角线BD上任意一点将BM绕点B逆时针旋转60°得到BN连接EN sketch template

如图，平面四边形 ，将沿折起到的位置，此时二面角的大小为 连接 则三棱锥外接球的表面积为；三棱锥的体积为 sketch template

如图一个直角三角形的三边长均为正整数已知它的一条直角边的长恰是3那么另一条直角边的长是 ．题目和参考答案——青夏教育精英家教�—— sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

用三个全等的直角三角形 AEF BDF和 CDE拼成如图所示的大的正三角形已知大的正三角形的边长是3则下列叙述中正确的是 ．�∠A=60 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图在四棱锥P ABCD中底面ABCD为等腰梯形AB∥CDAD=BC=2对角线AC⊥BD于O∠DAO=60°且PO⊥平面ABCD sketch template

如图在斜三棱柱ABC A1B1C1中侧面ABB1A1⊥底面ABC侧棱AA1与底面ABC成60°的角AA1=2．底面ABC是边长为2的正 sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图，在平行六面体ABCD A 1B 1C 1D 1中，底面是边长为2的正方形，若∠ 1AB=∠ 1AD=60^° ，且A 1A sketch template

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