15．如图rt abc中∠c=90°∠abc=30°ab=6．点d在ab边上点e是bc边上一点不与点bc重合且da=de则 Sketch Coloring Page

15．如图rt abc中∠c=90°∠abc=30°ab=6．点d在ab边上点e是bc边上一点不与点bc重合且da=de则 Template

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sketch #3818 เดียวจะวาดใหม่ยังไม่เสร็จๆ

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tomski15．如图rt abc中∠c=90°∠abc=30°ab=6．点d在ab边上点e是bc边上一点不与点bc重合且da=de则 coloring

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

5．如图在Rt ABC中∠C=90°∠A=30°BD是∠ABC的平分线若BD=10则CD=——青夏教育精英家教�—— sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

题目已知如图在Rt ABC中∠ACB=90°D是边AB的中点CE=CBCD=5求1BC的长．2tanE的值 sketch template

15．如图在 ABC中∠C=90°AB=10经过点C且与边AB相切的动圆与CACB分别交于点DE则线段DE长度的最小值是 sketch template

题目如图在 Rt ABC 中∠ACB＝90°．1用直尺和圆规作∠A的平分线交 BC 于点 P保留作图的痕迹不写作法2当 sketch template

如图在Rt ABC中∠B=90°BC=6∠C=30°点D从点C出�沿CA方�以每秒2个单位长的速度�点A匀速运动同时点E从点A出� sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

题目如图Rt ABC中∠BAC=90°AB=3AC=6点DE分别是边BCAC上的动点则DA DE的最小值为．题目和参考 sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

题目如图Rt ABC中∠C=90°AC=3BC=4若以A为旋转中心将其按顺时针方�旋转60°到 ABC位置则B点经过的 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图Rt ABC中∠C=90°AC=12BC=5分别以ABACBC为边在AB的同侧作正方形ABDEACFGBCIH四块阴影 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图所示在Rt ABC中∠BAC=90°AB=4AC=3ADAE分别是其角平分线和中线过点C作CG⊥AD于F交AB于G连接 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

题目如图 在Rt ABC中∠ACB＝90°AC＝6BC＝8将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图6在Rt ABC中 ∠C＝90°BD是∠ABC的平分线交AC于D若CD＝4AB＝8则 ABD的面积是 sketch template

百度教育 sketch template

如图在Rt ABC中∠C=90°AC=6∠A的平分线交BC于点DDE⊥AB于点E且BE=4求DE的长．题目和参考答案——青夏 sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

如图Rt ABC中∠D=90°∠B=45°∠ACD=60°BC=10cm求AD的长．题目和参考答案——青夏教育精英家教�—— sketch template

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