15．如图2正四面体abcd的棱长为1h是顶点d的底面 Abc上的射影m在dh上且使得∠abc=90°则dm的长 为 ——青夏教育 Sketch Coloring Page

15．如图2正四面体abcd的棱长为1h是顶点d的底面 Abc上的射影m在dh上且使得∠abc=90°则dm的长 为 ——青夏教育 Template

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tomski15．如图2正四面体abcd的棱长为1h是顶点d的底面 abc上的射影m在dh上且使得∠abc=90°则dm的长 为 coloring

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长 为 ——青夏教育 sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

如图，正四面体的长为1，， 则． sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长 为 ——青夏教育 sketch template

别盲目刷题，一道题琢磨透“一鱼多吃”，胜过刷题千万遍知乎 sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

正四面体ABCD棱长为2，E、F分别为BC、AD中点，则EF的长为 百度教育 sketch template

高中数学：几何体表面积与体积的教学设计知乎 sketch template

任意四面体的外接球半径公式知乎 sketch template

每日一题2392补形 Math173 sketch template

已知正四面体ABCD的棱长为1求1该四面体的内切球的表面积2与该四面体各条棱均相切的球的体积3该四面体的外接球上AB两点间 sketch template

如图已知正四面体A BCD的棱长为1EF分别为棱ABCD的中点 1建立适当的空间直角坐标系写出顶点ABCD的坐标 2 sketch template

一个正四面体的各条棱长都是a那么这个正四面体的高百度经验 sketch template

棱长为2的正四面体的四个顶点都在同一个球面上若过该球球心的一个截面如图则图中三角形的面积是 ．题目和参考答案——青夏教育精英家教�—— sketch template

已知菱形的边长为2，将沿折起，使得点至点的位置，得到四面体当二面角的大小为120°时，四面体的体积为；当四面体的体积为1时，以为球心，的长 sketch template

如图四面体ABCD的每条棱长都等于2点EF分别为棱ABAD的中点则AB BC= BC EF= EF与AC所成的角为 sketch template

如图在四面体ABCD中AB=CD=4AD=BD=5AC=BC=6点EFGH分别在棱ADBDBCAC上若直线ABCD都 sketch template

14= 15如图四棱柱ABCD―A1B1C1D1的底面ABCD为正方形侧棱与底面边长均为2a——青夏教育精英家教�—— sketch template

7．如图正四面体的棱长均为且平面于A点BCD均在平面外且在平面同一侧则点B到平面的距离是 A． B． C． D．——青夏教育精英 sketch template

由四个全等的等边三角形的封面几何体称为正四面体如图正四面体ABCD中EF分别是棱BCAD的中点CF与DE是一对异面直线在图形中 sketch template

已知正四面体ABCD及其内切球O经过该四面体的棱AD及底面ABC上的高DH作截面交BC于点E则截面图形正确的是 B sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

正四面体一个顶点处的立体角是多大？知乎 sketch template

如图，已知正四面体的棱长为，，分别为棱，的中点．若高途 sketch template

在正四面体的6条棱中随机抽取2条那么其2条棱互相垂直的概率为〔〕 A B C D 百度教育 sketch template

正四面体一个顶点处的立体角是多大？知乎 sketch template

如图，在平行六面体ABCD A 1B 1C 1D 1中，底面是边长为2的正方形，若∠ 1AB=∠ 1AD=60^° ，且A 1A sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

正四面体 360百� sketch template

如图，正方形ABCD的边长为2，E为边AD上一动点，连接BE、CE，以CE为边�右侧作正方形CEFG1若BE=sqrt{5}，则正方形 sketch template

如图五面体EF ABCD中ABCD是以点H为中心的正方形EF∥ABEH丄平面 ABCDAB=2EF=EH=1．1证明EH∥ sketch template

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