14= 15如图四棱柱abcd―a1b1c1d1的底面abcd为正方形侧棱与底面边长均为2a——青夏教育精英家教�—— Sketch Coloring Page

14= 15如图四棱柱abcd―a1b1c1d1的底面abcd为正方形侧棱与底面边长均为2a——青夏教育精英家教�—— Template

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tomski14= 15如图四棱柱abcd―a1b1c1d1的底面abcd为正方形侧棱与底面边长均为2a——青夏教育精英家教�—— coloring

14= 15如图四棱柱ABCD―A1B1C1D1的底面ABCD为正方形侧棱与底面边长均为2a——青夏教育精英家教�—— sketch template

PPT 空间几何体的体积 PowerPoint Presentation Free Download ID6407495 sketch template

如图在正四棱柱ABCD A1B1C1D1中已知AA1=2AB且点P为DD1的中点．1求证直线BD1∥平面PAC2求证平面 sketch template

如图四棱柱ABCD A1B1C1D1的底面ABCD为正方形侧棱与底面边长均为2a且∠A1AD=∠A1AB=60°则侧棱AA1和截面 sketch template

如图在四棱柱ABCD A1B1C1D1中底面ABCD和侧面BCC1B1都是矩形E是CD的中点D1E⊥CDAB=2BC=2．Ⅰ求证 sketch template

斜四棱柱的三视图千图� sketch template

如图是一个四棱柱被一个平面所截的几何体，底面是正方形，M是的中点， sketch template

如图1由正四棱锥P ABCD和正四棱柱ABCD A1B1C1D1所组成的几何体的三视图如图2．1求证PC⊥平面A1BD2求点P到 sketch template

正四棱柱图片定义千图� sketch template

14．如图在直四棱柱ABCD A1B1C1D1中已知DC＝DD1＝2AD＝2ABAD⊥DCAB∥DCE为DC的中点． 1求证 sketch template

如图在四棱柱ABCD A1B1C1D1中底面ABCD和侧面BCC1B1都是矩形E是CD的中点D1E⊥CDAB=2BC=2．Ⅰ求证 sketch template

PPT 空间几何体的体积 PowerPoint Presentation Free Download ID6407495 sketch template

如图已知直四棱柱ABCD A1B1C1D1的底面边长和侧棱长均为1且满足∠BAD=60°O1为A1C1的中点．1求证BD⊥A1C sketch template

如图 在直四棱柱ABCD A1B1C1D1中AB＝AD＝2 DC＝2AA1＝AD⊥DCAC⊥BD 垂足为E I求证BD⊥ sketch template

题目如图四个几何体分别是三棱柱四棱柱五棱柱和六棱柱三棱柱有5个面9条棱6个顶点观察图形填写下面的空．1四棱柱有个面 sketch template

如图在直四棱柱ABCD A1B1C1D1中底面ABCD为等腰梯形AB∥CDAB=4BC=CD=2AA1=2EE1F分别是棱 sketch template

如图 在直四棱柱ABCD A1B1C1D1中AB＝AD＝2 DC＝2AA1＝AD⊥DCAC⊥BD 垂足为E I求证BD⊥ sketch template

如图所示在直四棱柱ABCD A1B1C1D1中DB=BCDB⊥AC点M是棱BB1上一点． 1求证B1D1∥面A1BD 2 sketch template

在直四棱柱ABCD A1B1C1D1中已知AB∥CDAB=AD=1D1D=CD=2AB⊥AD．I求证BC⊥面D1DBII求 sketch template

本题满分12分如图在正四棱台中上底面边长为1下底面边长为3侧棱长为21求此正四棱台的侧面积2求此正四棱台的体积百度教育 sketch template

如图直四棱柱ABCD A1B1C1D1的高为3底面是边长为4且∠DAB=60°的菱形AC∩BD=OA1C1∩B1D1=O1E是O1A sketch template

直四棱柱的图片千图� sketch template

观察图三棱柱有5个面6个顶点9条棱四棱柱有6个面8个顶点12条棱五棱柱有7个面10个顶点15条棱 由此可推测n 2棱柱有 sketch template

如图所示在直四棱柱ABCD A1B1C1D1中DB=BCDB⊥AC点M是棱BB1上一点． 1求证B1D1∥面A1BD 2 sketch template

如图在正四棱台ABCD A1B1C1D1中A1B1=aAB=2a$A{A 1}=sqrt{2}a$EF分别是ADAB的中点 sketch template

在四棱台ABCD A1B1C1D1中上下底面均为正方形则DD1与BB1所在直线是 A．相交直线 B．平行直线 C 不垂直的异面 sketch template

15．如图正方体ABCD A1B1C1D1的棱长为1点M在AB上且AM=AB点P在平面ABCD上且动点P到直线A1D1的距离的平方与 sketch template

正四棱柱图片定义千图� sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

如图，在四棱柱中，底面和侧面均为正方形 高途 sketch template

如图在长方体ABCD A1B1C1D1中已知AB=4AD=3AA1=2E是线段AB上的点且EB=1则二面角C DE C1的正切值 sketch template

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长 为 ——青夏教育 sketch template

如图四棱锥P ABCD中PD⊥平面ABCD底面ABCD是正方形PD=AB=2E为PC中点．1求证DE⊥平面PCB2求点C sketch template

20．（12分）如图，四棱锥P ABCD的底面为正方形，PD⊥底面ABCD．设平面PAD与平面PBC的交线为l．（1）证明：l⊥平面PDC sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

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