如图，rt Abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 Ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Sketch Coloring Page

如图，rt Abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 Ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Template

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anonymous

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anonymous

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sketch #4867 Johnny Depp Ronin Ronin

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sketch #1669

anonymous

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tomski如图，rt abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 ade沿de折叠，点a恰好落在bc上的点f处，若点f为 coloring

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

已知如图在Rt ABC中∠C=90°以AC为直径作⊙O交AB于D过O作OE∥AB交BC于E．1求证ED是⊙O的切线．2 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图6在Rt ABC中 ∠C＝90°BD是∠ABC的平分线交AC于D若CD＝4AB＝8则 ABD的面积是 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

题目在Rt ABC中∠C=90°BC=3AC=4点P在以C为圆心5为半径的圆上连结PAPB．若PB=4则PA的长为 sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠A =90°AC =6cmAB=8cm把AB边翻折使AB边落在BC边上点A落在点E处折痕为BD则sin sketch template

如图Rt ABC中∠ABC＝90°以AB为直径的⊙O交AC于点DE是BC的中点连接DEOE．1判断DE与⊙O的位置关系并说明 sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径．题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠C=90°AC=6∠A的平分线交BC于点DDE⊥AB于点E且BE=4求DE的长．题目和参考答案——青夏 sketch template

如图Rt ABC中∠BAC=90°以AB为直径作⊙O交BC于点DOE∥BC交AC于点E连接AD交OE于点F连接DE．1判断 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图在Rt ABC中∠BAC=90°∠C=30°以边AC上一点O为圆心OA为半径作圆恰好经过边BC的中点D并与边AC相交于另一点 sketch template

如图在Rt ABC中∠C=90°以斜边AB为边�外作正方形ABDE且正方形对角线交于点O连接OC已知AC=5OC=62求另一 sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

如图在Rt ABC中∠C=90°DE⊥ABAC=BE=15BC=20则四边形ACED的面积为 75 96——青夏教育精英家教�—— sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

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