如图已知 abc和 dce均是等边三角形点bce在同一条直线上ae与bd交于点o与cd交于点gac与bd交于点f连接oc．求证 Sketch Coloring Page

如图已知 abc和 dce均是等边三角形点bce在同一条直线上ae与bd交于点o与cd交于点gac与bd交于点f连接oc．求证 Template

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tomski如图已知 abc和 dce均是等边三角形点bce在同一条直线上ae与bd交于点o与cd交于点gac与bd交于点f连接oc．求证 coloring

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

如图已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点O与CD交于点GAC与BD交于点F连接OC．求证 sketch template

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

如图已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点O与CD交于点GAC与BD交于点F连接OC．求证 sketch template

如图已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点O与CD交于点GAC与BD交于点F连接OC．求证 sketch template

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

题目如图1 ACB和 DCE均为等边三角形点A DE在同一直线上连接BE填空1�∠AEB的度数为 �线段ADBE sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

题目已知如图 ABC和 CDE均为等边三角形BCD三点在同一条直线上连接线段BEAD交于点F连接CF1求证∠FBC sketch template

如图，已知 ABC和 CDE均是等边三角形，点B、C、D在同一条直线上，BE与AD交于点O，AD与CE交于点N，AC与BE交于点M，连OC sketch template

如图所示已知 ABC和 ECD都是等腰直角三角形∠ACB=∠DCE=90．D为AB边上 点若AB=10cmAD=3cm求AE的长 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图已知 ABC为等边三角形CF∥AB点P为线段AB上任意一点点P不与AB重合过点P作PE∥BC分别交ACCF于GE．1 sketch template

题目如图等腰Rt ABC中斜边AB的长为2O为AB的中点P为AC边上的动点OQ⊥OP交BC于点QM为PQ的中点当点P从点A sketch template

如图三角形ABC和三角形ECD都是等腰直角三角形，∠ACB=∠DCE=90°，D为AB边上一点。百度知道 sketch template

如图BCE三点在一条直线上 ABC和 DCE均为等边三角形BD与AC交于点MAE与CD交于点N．1求证AE=BD2连接 sketch template

如图已知 ABC为等边三角形点D由点C出�在BC的延长线上运动连结AD以AD为边作等边三角形ADE连结CE．1请写出ACCD sketch template

如图，已知 ABC是等边三角形，延长BA至E，延长BC至D，使AE=BD，求证：EC=ED．百度教育 sketch template

如图已知 ABC DCE FEG是三个全等的等腰三角形底边BCCEEG在同一直线上且AB=$sqrt{3}$BC=1则BP sketch template

如图11 7 ABC与 A/B/C/关于点O成中心对称则下列结论不成立的是 A点A与点A′是对称点 BBO=B/O CAB∥A/B sketch template

如图已知 ABC和 ADE均为等边三角形D在BC上DE与AC相交于点FAB＝9BD＝3则CF等于A．1 B．2 C．3 D．4 sketch template

在 ABC和 DEC中，AC=BC，DC=EC，∠ACB=∠ECD=90°（1）如图1，当点A、C、D在同一条直线上时，求证：AF⊥BD sketch template

如图D是等边三角形ABC的边AB上一点且ADDB=12现将 ABC折叠使点C与点D重合折痕为EF点EF分别在AC和BC上且 sketch template

如图已知等边三角形ABC中内有一点PPA=3PC=4PB=5求此等边三角形ABC的边长百度知道 sketch template

在等边 ABC中D为射线BC上一点CE是∠ACB外角的平分线∠ADE=60°EF⊥BC于F1如图1若点D在线段BC上证明∠ sketch template

如图已知 BCE三点共线分别以BCCE为边作等边 ABC和等边 CDE连接BDAE分别与ACCD 交于MNAE与BD的交点 sketch template

如图1在等边 ABC的边AC的延长线上取一点E以CE为边作等边 CDE使它与 ABC位于直线AE的同侧．1同学们对图1进行了热烈的 sketch template

如图在平面直角坐标系中把 ABC沿y轴对折后得到 A1B1C1再将 A1B1C1�下平移4个单位长度得到 A2B2C2则 AB1C2的 sketch template

如图已知以 ABC的三边为边在BC的同侧分别作等边三角形ABDBCE和ACF．1求证四边形ADEF是平行四边形2 ABC满足 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图已知ABC为等边三角形DF分别是BCAB上的点且CD=BF以AD为边作等边三角形ADEDACD≌DCBF．试问当点D在线段 sketch template

如图在等边 ABC中D是AC的中点延长BC到点E使CE=CDAB=10cm．1求BE的长2 BDE是什么三角形为什么 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

百度教育 sketch template

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