如图在rt abc 中∠c=90°ac=bcab=8点d为ab的中点若直角mdn绕点d旋转分别交ac于点e交bc于点m则下列 Sketch Coloring Page

如图在rt abc 中∠c=90°ac=bcab=8点d为ab的中点若直角mdn绕点d旋转分别交ac于点e交bc于点m则下列 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #3226 Goth Face

anonymous

anonymous
sketch #3226 Goth Face

sketch #2029 GOD 'S PROMISE ...

Marlyn Ortiz
sketch #2029 GOD 'S PROMISE ...

sketch #1465

Laura Agapi Asnicar
sketch #1465

sketch #3208 ELETR by Raimundo Santos

anonymous

anonymous
sketch #3208 ELETR by Raimundo Santos

sketch #5059 Edward Hopper&#;s &#;Nighthawks&#; by Rosanne Zammit

anonymous

anonymous
sketch #5059 Edward Hopper&#;s &#;Nighthawks&#; by Rosanne Zammit

sketch #5297 Journey by Dmitry Sidorenko

anonymous

anonymous
sketch #5297 Journey by Dmitry Sidorenko

sketch #2278 flower

anonymous

anonymous
sketch #2278 flower

sketch #4086 2lips

anonymous

anonymous
sketch #4086 2lips

sketch #4869 Madara by Jean-Benoit Renaud

anonymous

anonymous
sketch #4869 Madara by Jean-Benoit Renaud

sketch #1257

anonymous

anonymous
sketch #1257

sketch #5286 Adventure Time by Manu Kp

anonymous

anonymous
sketch #5286 Adventure Time by Manu Kp

sketch #2771 Naruto by Милен Тревата

Милен Тревата
sketch #2771 Naruto by Милен Тревата

sketch #3059

anonymous

anonymous
sketch #3059

sketch #2810 Lennon by El Harouati Nassera

El Harouati Nassera
sketch #2810 Lennon by El Harouati Nassera

sketch #2371

anonymous

anonymous
sketch #2371

sketch #5094 Squirrel by Mehdi Público

anonymous

anonymous
sketch #5094 Squirrel by Mehdi Público

sketch #3693 Lucy from Elfen Lied by Simona Honigmelone

anonymous

anonymous
sketch #3693 Lucy from Elfen Lied by Simona Honigmelone

sketch #2206

anonymous

anonymous
sketch #2206

sketch #3779 RIP Hugo Chavez Joey Hyuuga

anonymous

anonymous
sketch #3779 RIP Hugo Chavez Joey Hyuuga

sketch #1060

anonymous

anonymous
sketch #1060

sketch #2087 zay lin

Zay Lin
sketch #2087 zay lin

sketch #4511 Yao Ming by Betty Marie Melzer

anonymous

anonymous
sketch #4511 Yao Ming by Betty Marie Melzer

sketch #4990

anonymous

anonymous
sketch #4990

sketch #2027

anonymous

anonymous
sketch #2027

sketch #1470

Laura Agapi Asnicar
sketch #1470

sketch #3554 Dr. House by Carrieann Benthem

anonymous

anonymous
sketch #3554 Dr. House by Carrieann Benthem

sketch #1110

anonymous

anonymous
sketch #1110

sketch #1453

anonymous

anonymous
sketch #1453

sketch #4273

anonymous

anonymous
sketch #4273

sketch #2910 Harley Quinn Germaine Hoens

anonymous

anonymous
sketch #2910 Harley Quinn Germaine Hoens

tomski如图在rt abc 中∠c=90°ac=bcab=8点d为ab的中点若直角mdn绕点d旋转分别交ac于点e交bc于点m则下列 coloring

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图1，在Rt ABC中，∠ACB=90°，AC=BC，点D、E分别在AC、BC边上，DC=EC，连接DE、AE、BD，点M、N、P分别是AE sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图Rt ABC中已知∠C=90°∠B=48°点D在边BC上BD=2CD把Rt ABC绕点D逆时针旋转m度后如果点B恰好落在初始 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

如图在Rt ABC中∠C=90°BD平分∠ABC交AC于点DDE垂直平分AB垂足为点E请任意写出一组相等的线段BE=EA．题目和 sketch template

如图在Rt ABC中∠C=90°AC=6BC=8点F在边AC上并且CF=2点E为边BC上的动点将 CEF沿直线EF翻折点C落 sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图在 ABC中∠C=90°AC=BCAD是角平分线DE⊥AB．垂足为E．求证BE=DE=CD．题目和参考答案——青夏教育精英家教�—— sketch template

$如图在Rt ABC中∠C=90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于$frac sketch template$

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图，在Rt ABC中，∠ACB=90°，AC=6，BC=8，AD是∠BAC的平分线．若P，Q分别是AD和AC上的动点，则PC PQ的最小值是 sketch template

如图在Rt ABC中∠ACB=Rt∠AC=2tan2A Tan2B= ∠A>∠B点P在斜边AB上移动连结PC设AP为x sketch template

如图D是Rt ABC斜边BC上一点AB=AD记∠CAD=α∠ABC=β1证明sinα Cos2β=02若AC=DC求β的 sketch template

如图在 ABC中∠C=90°AC=4BC=3以点C为圆心r为半径画圆．1当r=24时⊙C与边AB相切2当r满足3＜r sketch template

如图在Rt ABC中∠ACB=90°∠BAC=30°∠ACB的平分线与∠ABC的外角平分线交于E点连接AE则∠CEB是 A sketch template

如图在Rt ABC中∠C=90°AC=8BC=6点DE分别在边ABAC上将 ADE沿直线DE翻折点A的对应点在边AB上联结 sketch template

题目如图 1在 Rt ABC 中∠ACB＝90°AC＝BCD 是 BC 上的一点过点 D 作 DE⊥AB垂足为点 EF 为 sketch template

题目如图 ABC中∠ACB=90°AC=BC点E是AC上一点连接BE． 1如图1若AB=4 BE=5求AE的长2 sketch template

如图在直三棱锥ABC A1B1C1中AC=BC=AA1∠ACB=90°EF分别是ABBC的中点G是AA1上的点若一个三棱锥的三 sketch template

如图在Rt ABC中∠BAC=90°AB=ACBD是AC边上的中线AE⊥BD于F交BC于E．1证明∠ABD=∠DAF2 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数题目和参考答案——青夏教育精英家教�—— sketch template

题目如图在Rt ABC中∠C=90°∠A=30°AB=4动点P从点A出�沿AB以每秒2个单位长度的速度�终点B运动．过点P作 sketch template

百度教育 sketch template

如图在Rt ABC中∠ACB=90°∠BAC=30°∠ACB的平分线与∠ABC的外角平分线交于E点连接AE则∠CEB是 A sketch template

题目如图在Rt ABC中∠ACB=90°AC=BC=1将Rt ABC绕点A逆时针旋转30°后得到Rt ADE点B经过的路径为 sketch template

17． 如图在直三棱柱ABC – A1B1C1中∠BAC = 90°AB AC AAA1 2aD为BC的中点E为CC1上 sketch template

题目在直角坐标系中有如图所示的Rt ABOAB⊥x轴于点B斜边AO=10sin∠AOB= 反比例函数 的图象经过AO的中点C且 sketch template

如图在Rt ABC中∠C=90°AC=BC=6点D为AC中点点E为边AB上一动点点F为射线BC上一动点且∠FDE=90°．1 sketch template

如图在Rt ABC中∠C=90°以斜边AB为边�外作正方形ABDE且正方形对角线交于点O连接OC已知AC=5OC=62求另一 sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图 ABC中AB=AC点D在AC的延长线上点E在BC的延长线上DB=DE∠AFE ∠A=180°．求证EF=AD．题目和参考 sketch template

如图在 ABC和 DCE中AC=BCDC=EC∠ACB=∠DCE=90°将 DCE绕点C旋转连结BD和AE1求证 BCD≌ sketch template

探究1如图1在ABC与ADE中AB=ACAD=AE∠BAC=∠DAE=90°连结BDCE．请写出图1中所有全等的三角形 sketch template

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