如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

4．如图已知三棱锥的底面是直角三角形直角边长分别为3和4 过直角顶点的侧棱长为4且垂直于底面该三棱锥的正视图是 ——青夏教育精英 sketch template

正三棱锥的高是多� 百度经验 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

一个三棱锥，如果它的底面是直角三角形，那么它的三个侧面（） A．必定都不是直角三角形 B．至多有一个直角三角形 C．至多有两个直角三 百度教育 sketch template

初学讲义之高中数学二十：简单几何体知乎 sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

下面有四个�题1各个侧面都是等腰三角形的棱锥是正棱锥2三条侧棱都相等的棱锥是正棱锥3底面是正三角形的棱锥是正三棱锥4 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

2．如图正三棱锥P ABC顶点P在底面上的射影在ΔABC内部M是侧面PAB上的点且M到点P的距离等于M到底面的距离则点M的轨迹是 sketch template

5．已知三棱锥S ABC的底面是正三角形点A在侧面SBC上的射影H是 SBC的垂心SA=a则此三棱锥体积最大值是 A． B C D sketch template

81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

如图三棱锥P ABC的三条棱PCCACB两两互相垂直并且∠PAC=30PB=BC=3 �求二面角B PA C的大小 �设点C在 sketch template

如图三棱锥P ABC的底面ABC是以AC为斜边的直角三角形且顶点P在底面的射影是 ABC外心设PB=AB=1BC=2．1求证面 sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

7．一个四棱锥的底面为正方形其三视图如图所示则这个四棱锥的体积是 A． B． C． D．——青夏教育精英家教�—— sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图已知在四棱锥P ABCD中底面ABCD是边长为4的正方形 PAD是正三角形EFG分别是PDPCBC的中点．1求证直线 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

已知四棱锥P ABCD的底面是边长为6的正方形侧棱PA⊥底面ABCD且PA=8则该四棱锥的体积是 A．288B．96C．48D sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

如图四棱锥P ABCD中底面ABCD是边长为2的正方形PB⊥BCPD⊥CD且PA=2E为PD中点．1求二面角B EC A的正弦 sketch template

6．如图在底面为直角梯形的四棱锥 ABCDBC=6 Ⅰ求证 Ⅱ求二面角的平面角的余弦值解Ⅰ如图建立坐标系则 sketch template

如图已知四棱锥S ABCD的侧面SCD⊥底面ABCDBC∥ADBC⊥SC且SC=SD=CD=BC=2AD =2P为SB的中点求 sketch template

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ D．直线所成的角为45°——青夏教育精英家教�—— sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

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