已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Sketch Coloring Page

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Template

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tomski已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 coloring

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

四棱锥三视图图片五棱锥三视图图片一个正四棱锥的三视图第2页大山谷图库 sketch template

四棱锥图片直观图三棱锥和四棱锥图片四棱锥图片素描图片大山谷图库 sketch template

四棱锥三视图图片千图� sketch template

四棱锥俯视图正四棱锥的俯视图正视图侧视图俯视图 大山谷图库 sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

如图1由正四棱锥P ABCD和正四棱柱ABCD A1B1C1D1所组成的几何体的三视图如图2．1求证PC⊥平面A1BD2求点P到 sketch template

一个四棱锥的底面为正方形其直观图与三视图如图所示则二面角P DC A的正弦值为 ABCD——青夏教育精英家教�—— sketch template

如图所示，四棱锥的底面为矩阵，其中一条棱垂直于底面，那么该四棱锥的俯视图最有可能是：【2025广东0 星光公考公务�考试公考 2025 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图四棱锥P ABCD它的正视图如图1是等腰三角形侧视图如图2是等腰直角三角形俯视图如图3是正方形ABCD各长度如图 sketch template

20．（12分）如图，四棱锥P ABCD的底面为正方形，PD⊥底面ABCD．设平面PAD与平面PBC的交线为l．（1）证明：l⊥平面PDC sketch template

四棱锥的侧视图四棱锥的三视图正视图侧视图俯视图第7页大山谷图库 sketch template

7．一个四棱锥的底面为正方形其三视图如图所示则这个四棱锥的体积是 A． B． C． D．——青夏教育精英家教�—— sketch template

12．如图所示在四棱锥P ABCD中底面ABCD是矩形PA＝AB＝2BC＝a又侧棱PA⊥底面ABCD 1当a为何值时BD⊥ sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示此图仅为示意，现有各棱长均相等的一个正三棱锥和一个正四棱锥 488523 趣�几何数学天地 33IQ sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

一个四棱锥的三视图如图所示其中主视图是腰长为1的等腰直角三角形则这个几何体的体积是 A．12B．1C．32D．2——青夏教育精英家教�—— sketch template

如图所示四棱锥P ABCD中底面ABCD是正方形PA⊥底面ABCDPA=AB=2点F是PB的中点点E在棱BC上移动．1当E为 sketch template

如图已知直角梯形ABCD中AB⊥BCAB=AD=aBC=3aE是BC边上一动点以DE为棱把 CDE折起使其成为直二面角C DE sketch template

一个四棱锥的三视图如图所示其中主视图是腰长为1的等腰直角三角形则这个几何体的体积是 A．12B．1C．32D．2——青夏教育精英家教�—— sketch template

已知正四棱锥底面正方形的边长为4cm高与斜面的夹角为30°如图所示求正四棱锥的侧面积和表面积单位cm2．题目和参考答案——青夏 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图所示侧面是全等的等腰三角形的棱锥是 A正棱锥 B侧棱长相等的棱锥C斜高长相等的棱锥 D以上均不对题目和参考答案——青夏教育精英 sketch template

一个三棱锥的三视图如图所示则该三棱锥的体积是 A4 B C D8——青夏教育精英家教�—— sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

练题本立体几何9 副本 Word文档在线阅读与下载免费文档 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

已知四棱柱如图所示，底面为平行四边形，其中点在平面高途 sketch template

已知三棱柱ABC A1B1C1的直观图和三视图如图所示E是棱CC1上一点．1若CE=2EC1求三棱锥E ACB1的体积．2若E是 sketch template

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