如图�，线段ab、cd相交于点o，连接ad、cb，如图�，在图�的条件下，∠dab和∠bcd的平分线ap和cp相交于点p，并且与cd、ab分别 Sketch Coloring Page

如图�，线段ab、cd相交于点o，连接ad、cb，如图�，在图�的条件下，∠dab和∠bcd的平分线ap和cp相交于点p，并且与cd、ab分别 Template

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tomski如图�，线段ab、cd相交于点o，连接ad、cb，如图�，在图�的条件下，∠dab和∠bcd的平分线ap和cp相交于点p，并且与cd、ab分别 coloring

如图四边形ABCD内接于⊙OAB是⊙O的直径AC和BD相交于点E且1求证BC=CD2分别延长ABDC交于点P过点A作 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图直线AB与CD相交于点O∠BOD∠AOD=23则∠BOC的度数是108°108°．题目和参考答案——青夏教育精英家教�—— sketch template

如图�，线段AB、CD相交于点O，连接AD、CB，如图�，在图�的条件下，∠DAB和∠BCD的平分线AP和CP相交于点P，并且与CD、AB分别 sketch template

如图所示直线ABCD相交于点OOE平分∠BOD∠AOD ∠AOC=20°求∠AOE的度数．题目和参考答案——青夏教育精英家教�—— sketch template

已知如图ABCD相交于点O且AB=CDAD=CB．试说明OB=OD．题目和参考答案——青夏教育精英家教�—— sketch template

已知如图1线段ABCD相交于点O连接ADCB�们把形如图1的图形称之为“8字形．如图2在图1的条件下∠DAB和∠BCD的平分线 sketch template

如图线段ABCD相交于点OAC∥DBAC∥DBAO=BOEF分别为OCOD的中点连结AFBE求证AF∥BE．题目和 sketch template

如图已知线段ABCD相交于点OADCB的延长线交于点EOA=OCEA=EC请说明∠A=∠C 题目和参考答案——青夏教育精英家教�—— sketch template

如图直线ABCD相交于点OOE平分∠BOD∠AOC=72°OF⊥CD垂足为O求1求∠BOE的度数．2求∠EOF的度数 sketch template

如图在梯形ABCD中AD∥BCAB=AC∠BAC=90°BC=BDAC与BD相交于O．求证CD=CO．题目和参考答案——青夏 sketch template

如图直线AB与CD相交于点OOE⊥ABOF⊥CDOP是∠BOC的平分线．1如果∠AOD=40°�那么根据可得∠BOC sketch template

如图直线ABCDEF相交于点O是∠AOC的邻补角是 ∠DOA的对顶角是若∠AOC＝500则 ∠BOD＝0∠COB＝ 0——青夏 sketch template

如图两条直线ABCD相交于O若∠1=35°则∠2=A35B45C135D145——青夏教育精英家教�—— sketch template

如图所示ABCD交于点EAD=AECE=BCFGH分别是DEBEAC的中点．求证∠HFG=∠FGH．题目和参考答案——青 sketch template

如图线段ADBC相交于点O连接ABCD．下列条件�AB=CDAO=CO�∠A=∠CAO=CO�AO=COBO=DO�∠B sketch template

如图两直线ABCD相交于点OOE平分∠BOD如果∠AOC∠AOD=7111求∠COE2若OF⊥OE∠AOC=70°求 sketch template

如图直线ABCD相交于点OOE平分∠AODOF⊥OC1图中∠AOF的余角是∠BOC∠AOD把符合条件的角都填出来2 sketch template

6．如图直线ABCD相交于点O∠1＝∠2．则∠1的对顶角是 ∠4的邻补角是．∠2的补角是．提示注意补角和邻补角的区别前者只 sketch template

如图直线ABCD相交于点OOA平分∠COE∠COE=70°则∠BOD的度数是 A．20°B．30°C．35°D．40°——青夏 sketch template

如图1所示已知AB//CDAD和BC相交于点O若则 图1 图2 图3——青夏教育精英家教�—— sketch template

如图点C是线段AB上任意一点分别以ACBC为边在直线AB的同侧作等边三角形ACD和等边三角形BCEAE与CD相交于点MBD与CE相交 sketch template

已知如图直线AB和CD相交于OOE平分∠BOC 且∠AOC=68°则∠BOE=——青夏教育精英家教�—— sketch template

如图直线ABCD相交于点OOE⊥ABO为垂足如果∠EOD = 38°则∠AOC ∠COB =——青夏教育精英家教�—— sketch template

如图直线ABCD相交于点O∠AOC=90°MN是一条过点O的直线∠1=54°OE平分∠CON求∠2的度数．题目和参考答案——青 sketch template

如图，AB是⊙O的直径，点C是⊙O上一点，AD和过点C的切线互相垂直，垂足为D，直线DC与AB的延长线相交于P．弦CE平分∠ACB，交直径AB sketch template

如图已知直线ABCDEF相交于点OAB⊥CD∠DOE=127°则∠COE= A127B37C53D63——青夏教育 sketch template

如图线段ABDE的垂直平分线交于点C且∠ABC=∠EDC=72°∠AEB=92°则∠EBD的度数为 &ampnb 百度教育 sketch template

题目如图直线ABCDOE⊥AB过点O画直线MN⊥CD 若点F是直线MN上任意一点点O除外且∠AOC=34°求∠EOF的 sketch template

如图，在以点O为圆心的两个同心圆中，大圆的弦AB交小圆于点C、D 已知AB=4，CD=2，圆心O到直线AB的距离为1，则大圆的半径为，小圆 sketch template

百度教育 sketch template

如图已知正方形ABCD以CD为边�外作等边三角形CDEBE与AC相交于点F求证EF=CF BF 百度教育 sketch template

如图直线ABCD相交于点O．若∠AOD比∠AOC大40°则∠BOD= 若∠AOD=2∠AOC则∠BOC= 若∠AOD=∠AOC则 sketch template

如图所示直线AD和BC相交于OAB∥CD∠AOC=95°∠B=50° ∠A=A50B55C40D45——青夏教育精英 sketch template

百度教育 sketch template

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