如图是一个质点做简谐运动的振动图象从图中可得 A．在t=0时质点位移为零速度和加速度也零b．在t=4s时质点的速度最大方�沿负 Sketch Coloring Page

如图是一个质点做简谐运动的振动图象从图中可得 A．在t=0时质点位移为零速度和加速度也零b．在t=4s时质点的速度最大方�沿负 Template

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tomski如图是一个质点做简谐运动的振动图象从图中可得 a．在t=0时质点位移为零速度和加速度也零b．在t=4s时质点的速度最大方�沿负 coloring

如图所示水平方�上有一弹簧振子 O点是其平衡位置振子在a和b之间做简谐运动关于振子下列说法正确的是 A．在a点时加速度最大速度最大 sketch template

如图是一个质点做简谐运动的振动图象从图中可得 A．在t=0时质点位移为零速度和加速度也零B．在t=4s时质点的速度最大方�沿负 sketch template

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一个质点做简谐运动的图象如图5所示下述正确的是 A质点振动�率为4赫兹 B在10 S内质点经过的路程是20 Cm C在5 S末 sketch template

如图所示一个弹簧振子在AB两点间做简谐运动O点为平衡位置下列说法中正确的有 A它在AB两点时动能为零B它经过O点时加速度方� sketch template

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一个质点经过平衡位置O在AB两点间做简谐运动如图15甲它的振动图象如图乙所示设�右为正方�则 图15 1OB＝ Cm 2第 sketch template

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弹簧振子做简谐运动其位移x与时间t的关系如图所示由图可知A．在t＝1 S时速度为负�最大加速度为零 B．在t＝2 S时位移为正�最大 sketch template

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如图是演示单�简谐运动图象的装置当沙漏斗下面的薄木板被匀速地拉出时振动着的漏斗中漏出的沙在板上形成的曲线显示出�的位移随时间变化的关系板 sketch template

6．如图1所示做简谐运动的水平弹簧振子从平衡位置O�B运动的过程中下述正确的是 A．振子做匀减速运动 B．振子做匀加速运动 C．振子做 sketch template

如图所示坐标原点所在质点从平衡位置开始做简谐运动形成的波沿x轴正方�传播．开始时刻坐标原点所在质点开始沿y轴正方�振动经过07s形成如 sketch template

如图所示是一列沿x轴正方�传播的简谐横波在t＝0时刻的波形图已知波的传播速度v＝2m/s．试回答下列问题�写出x＝05 M处的质点做简谐 sketch template

7．一质点做简谐运动的图象如图下列判断正确的是 A．振动�率为4Hz B．在10s内质点通过的路程为20cm C．第5s末质点的速度为零 sketch template

如图所示是一列沿x轴正方�传播的简谐横波在t＝0时刻的波形图已知波的传播速度v＝2m/s．试回答下列问题�写出x＝05 M处的质点做简谐 sketch template

如图所示是一列�x轴正方�传播的简谐横波在t=0时刻的波形图此时质点B恰好运动到波峰质点C恰好通过平衡位置．若该波的�期为40s则对 sketch template

直线运动中非常规图像知乎 sketch template

一个质点做简谐振动它的振动图像如图4 1所示下列判断正确的是 A．图中的曲线部分是质点的运动轨迹 B．有�线段OA是质点在t1时间内的位移 sketch template

甲质点做直线运动的x t图象和乙质点做直线运动的v t图象如图所示下列说法正确的是 A．甲质点在3s内通过的位移为2mB．甲质点在0 sketch template

由波的图像分析质点的振动情况例4 一列简谐横波沿x轴传播�期为Tt=0时刻的波形如图所示此时平衡位置位于x=3m处的质点正在�上运动 sketch template

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