如图已知d是 abc中的边bc上的一点∠bad=∠c∠abc的平分线交边ac于e交ad于f那么下列结论中错误的是 A Bac Sketch Coloring Page

如图已知d是 abc中的边bc上的一点∠bad=∠c∠abc的平分线交边ac于e交ad于f那么下列结论中错误的是 A Bac Template

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anonymous

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sketch #4091 Irie

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anonymous

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sketch #2613

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sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

anonymous

anonymous
sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

sketch #251

Tom Kelly
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sketch #3425 &#;Tonari no Kaibutsu-kun&#; by Betty Marie Melzer

anonymous

anonymous
sketch #3425 &#;Tonari no Kaibutsu-kun&#; by Betty Marie Melzer

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anonymous

anonymous
sketch #4532

sketch #921 comics ufo

anonymous

anonymous
sketch #921 comics ufo

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sketchmaster
sketch #2446 Joker by sketchmaster

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sketch #342 Forest scene

sketch #3707 The Thinker

anonymous

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sketch #3707 The Thinker

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sketch #5437 Mikasa from Attack on Titan by Manimarmuthu Muthu

anonymous

anonymous
sketch #5437 Mikasa from Attack on Titan by Manimarmuthu Muthu

sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

anonymous

anonymous
sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

tomski如图已知d是 abc中的边bc上的一点∠bad=∠c∠abc的平分线交边ac于e交ad于f那么下列结论中错误的是 a coloring

如图已知D是 ABC中的边BC上的一点∠BAD=∠C∠ABC的平分线交边AC于E交AD于F那么下列结论中错误的是 A BAC sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

如图已知在 ABC中AD是BC边上的中线E是AD上一点且BE=AC延长BE交AC于点F。求证AF=EF。百度教育 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图，在 ABC中，AB=BC，tanB=5/12，D为BC上一点，且满足 BD/CD=8/5，过点D作DE⊥AD交AC延长线于点 sketch template

已知如图在 ABC中D是AB边上的一点且BD=2ADCD=10 Sin∠BCD=则BC边上的高AE 的长为 A．45 B．6 sketch template

已知D是 ABC的边BC上的一点点B和C到AD的距离相等那么线段AD是 ABC的 A．BC的垂直平分线B．角平分线C．中线D．高线 sketch template

如图，在 ABC中，点D是BC上一点，E是AD上一点，EB=EC，∠ABE=∠ACE。求证：AD⊥BC sketch template

已知如图等边 ABC中点D为BC边的中点点F是AB边上一点点E在线段DF的延长线上∠BAE＝∠BDF点M在线段DF上∠ABE sketch template

如图在 ABC中点D是AB边上的一点1请用尺规作图法在 ABC内求作∠ADE使∠ADE=∠BDE交AC于E不要求写作法 sketch template

如图，已知以 ABC的边AB、AC分别�外作等腰Rt ABD与等腰Rt ACE，其中∠BAD=∠CAE=90°，连接BE、CD，BE和CD相交 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图在等边 ABC 中DEF分别为ABBCCA上一点且AD=BE=CF若每三个三角形两两全等为一组则图中全等的三角形组数为 sketch template

如图1，D、E、F分别是 ABC各边上的点，四边形ADEF是平行四边形，有三个选项：�D是AB的中点，�E是BC的中点，�F是AC的中点． sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

百度教育 sketch template

百度教育 sketch template

如图， ABC中，D点在BC上，将D点分别以AB、AC为对称轴，画出对称点E、F，并连接AE、AF，根据图中标示的角度，∠EAF的度数为 sketch template

如图在 ABC中BC=4以点A为圆心2为半径的⊙A与BC相切于点D交AB于E交AC于F点P是⊙A上一点且∠EPF=40°则图 sketch template

如图钝角三角形ABC的面积为15最长边AB=10BD平分∠ABC点MN分别是BDBC上的动点则CM MN的最小值为．题目和 sketch template

如图已知AB=AD∠ABC=∠ADC．试判断AC与BD的位置关系并说明理由．题目和参考答案——青夏教育精英家教�—— sketch template

如图在等边 ABC中D是AC的中点延长BC到点E使CE=CDAB=10cm．1求BE的长2 BDE是什么三角形为什么 sketch template

如图ABC中AB=6AC=8BC=10DE分别是ACAB的中点则以DE为直径的圆与BC的位置关系是 A 相交 B 相切 sketch template

如图在 ABC中BC=4以点A为圆心2为半径的⊙A与BC相切于点D交AB于E交AC于F点P是⊙A上一点且∠EPF=40°则图 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

百度教育 sketch template

如图点D在 ABC的AB边上AD=BD=CD=1延长BC至EBC=CE连接AE则AE= ．题目和参考答案——青夏教育精英家教�—— sketch template

如图D是等边 ABC的边AC上的一点E是等边 ABC外一点若BD=CE∠1=∠2则对 ADE的形状最准确的是 A．等腰三角形B sketch template

如图在 ABC中AC=6cmAB=9cmD是边BC上一点AD平分∠BAC在AB上截取AE=AC连结DE已知DE=2cmBD sketch template

如图已知在 ABC中AB=ACD是BC边上任意一点DF⊥AC于点FE在AB边上ED⊥BC于D∠AED=155°则∠EDF等于 sketch template

如图等边 ABC中点D在AB上点E在BC上AD=BE．AE和CD相交于点P求证∠CPE=60°．题目和参考答案——青夏教育精英家教�—— sketch template

如图等边 ABC中DE分别为ABBC边的延长线上的点且BD=CEDC的延长线交AE于点FAG⊥CD于点G．1求证 ACE≌ sketch template

如图3在 ABC中D是AC边延长线上的一点∠A＝36° ∠B＝62°则∠BCD的度数为 ——青夏教育精英家教�—— sketch template

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