如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

正三棱锥的高是多� 百度经验 sketch template

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

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三棱锥图形各种截面图 千图� sketch template

一个三棱锥，如果它的底面是直角三角形，那么它的三个侧面（） A．必定都不是直角三角形 B．至多有一个直角三角形 C．至多有两个直角三 百度教育 sketch template

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81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

三棱锥的三视图画法千图� sketch template

三棱锥专题 Word文档在线阅读与下载免费文档 sketch template

如图，三棱锥的底面是边长为的等边三角形，侧棱 ，设点分别为的中点 sketch template

如图，在四棱锥中，底面是菱形，，面，是棱上一动点高途 sketch template

已知四棱锥P ABCD它的底面是边长为a的菱形且∠ABC＝120°PC⊥平面ABCD又PC＝aE为PA的中点． 1求证平面 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

一个三棱锥的三视图如图所示则该三棱锥的体积是 A4 B C D8——青夏教育精英家教�—— sketch template

14． 三棱锥P ABC的四个顶点点在同一球面上若PA⊥底面ABC底面ABC是直角三角形PA=2 AC=BC=1则此球的表面积为 sketch template

2．如图正三棱锥P ABC顶点P在底面上的射影在ΔABC内部M是侧面PAB上的点且M到点P的距离等于M到底面的距离则点M的轨迹是 sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

如图，D为圆锥的顶点，O是圆锥底面的圆心，AE为底面直径，AE=AD． ABC是底面的内接正三角形，P为DO上一点，PO=√6/6DO sketch template

如图，在四棱锥P ABCD中，侧面PAD⊥ 底面ABCD，侧棱PA=PD=√2，底面ABCD为直角梯形，其中BC//AD，AB⊥ AD，AD sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

如图已知在四棱锥P ABCD中底面ABCD是边长为4的正方形 PAD是正三角形EFG分别是PDPCBC的中点．1求证直线 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

已知四棱锥P ABCD的底面ABCD是边长为2的正方形PD⊥底面ABCDEF分别为棱BCAD的中点．Ⅰ求证DE∥平面PFBⅡ sketch template

如图已知四棱锥的底面是边长为4的正方形在底面上的射影落在正方形内的长为到的距离分别为和 是的中点． Ⅰ求证平面底面 Ⅱ设 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

20．（12分）如图，四棱锥P ABCD的底面为正方形，PD⊥底面ABCD．设平面PAD与平面PBC的交线为l．（1）证明：l⊥平面PDC sketch template

如图已知四棱锥P ABCD的底面为直角梯形AB∥CD∠DAB=90°PA⊥底面ABCD且PA=AD=DC=12AB=1M是PB的 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

【高中数学�高考冲刺点到平面距离三种求法知乎 sketch template

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