如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

初学讲义之高中数学二十：简单几何体知乎 sketch template

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81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

一个三棱锥的各个面均为正三角形以每个面的中心为顶点构成一个新三棱锥若新三棱锥体积为2求原三棱锥体百度知道 sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

一个三棱锥，如果它的底面是直角三角形，那么它的三个侧面（） A．必定都不是直角三角形 B．至多有一个直角三角形 C．至多有两个直角三 百度教育 sketch template

如图，在四棱锥中，底面是菱形，，面，是棱上一动点高途 sketch template

已知四棱锥P ABCD它的底面是边长为a的菱形且∠ABC＝120°PC⊥平面ABCD又PC＝aE为PA的中点． 1求证平面 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

5．已知三棱锥S ABC的底面是正三角形点A在侧面SBC上的射影H是 SBC的垂心SA=a则此三棱锥体积最大值是 A． B C D sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

详解三角面片：实现现实场景的数字化 CSDN博客 sketch template

14． 三棱锥P ABC的四个顶点点在同一球面上若PA⊥底面ABC底面ABC是直角三角形PA=2 AC=BC=1则此球的表面积为 sketch template

81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

2．如图正三棱锥P ABC顶点P在底面上的射影在ΔABC内部M是侧面PAB上的点且M到点P的距离等于M到底面的距离则点M的轨迹是 sketch template

四棱锥图片直观图三棱锥和四棱锥图片四棱锥图片素描图片大山谷图库 sketch template

2．正棱锥的直观图的画法斜二测法画出底面的直观图然后确定顶点——青夏教育精英家教�—— sketch template

如图已知四棱锥的底面是边长为4的正方形在底面上的射影落在正方形内的长为到的距离分别为和 是的中点． Ⅰ求证平面底面 Ⅱ设 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

四棱锥 360百� sketch template

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

20．（12分）如图，四棱锥P ABCD的底面为正方形，PD⊥底面ABCD．设平面PAD与平面PBC的交线为l．（1）证明：l⊥平面PDC sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

已知正四棱锥的底面边长是，侧棱长是，则该正四棱锥的表面积为（） A B C D 百度教育 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ D．直线所成的角为45°——青夏教育精英家教�—— sketch template

已知六棱锥P ABCDEF其中底面ABCDEF是正六边形点P在底面的投影是正六边形的中心底面边长为2cm侧棱长为3cm求六棱锥P sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

六棱柱有12个顶点18条棱8个面．题目和参考答案——青夏教育精英家教�—— sketch template

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