8．如图所示o是等边三角形abc的中心d是三角形中的任意一点如果作矢量dadbdc分别表示三个力三个力的方�如图中箭头所示则这三 Sketch Coloring Page

8．如图所示o是等边三角形abc的中心d是三角形中的任意一点如果作矢量dadbdc分别表示三个力三个力的方�如图中箭头所示则这三 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

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sketch #3431 Jimi Hendrix by Konvicted Rohit

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sketch #2787 Spongebob by ShopRasta Roots

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sketch #1536 Dark Night

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sketch #3399 zay lin

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tomski8．如图所示o是等边三角形abc的中心d是三角形中的任意一点如果作矢量dadbdc分别表示三个力三个力的方�如图中箭头所示则这三 coloring

题目如图所示边长为2的等边三角形ABC中D点在边BC上运动不与BC重合点E在边AB的延长线上点F在边AC的延长线上AD sketch template

等边三角形八等分图片千图� sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

8．如图所示O是等边三角形ABC的中心D是三角形中的任意一点如果作矢量DADBDC分别表示三个力三个力的方�如图中箭头所示则这三 sketch template

如图3 ABC是等边三角形在ACBC边上各取一点PQ使AP=CQ AQ BP交于点O则∠QOB= ．——青夏教育精英家教�—— sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

如图点O是等边 ABC内一点D是 ABC外的一点∠AOB=110°∠BOC=α BOC≌ ADC∠OCD=60°连接OD．1 sketch template

百度教育 sketch template

题目已知 ABC是等边三角形点D是直线AB上一点延长CB到点E使BE＝AD连接DEDC1若点D在线段AB上且AB＝6 sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

百度教育 sketch template

如图所示，在 ABC中，∠B=60°，AB=AC，点D、E分别在BC、AB上，且BD=AE，AD与CE交于点F．（1）求证： ABC是等边三角 sketch template

1如图1所示若P为等边 ABC内一点∠BPC=150° BPP′是等边三角形求证PC2 PB2=PA22如图2所示点P为 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为百度教育 sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

1如图1所示在等边 ABC中点D是AB边上的动点以CD为一边�上作等边 EDC连接AE求证AE∥BC中等边 ABC的形状改 sketch template

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

如图所示已知等边三角形ABC的边长为1按图中所示的规律用2011个这样的等边三角形镶嵌而成的四边形的�长是 ．题目和参考答案——青夏 sketch template

如图所示，边长为2的等边三角形中，D点在边上运动（不与B、C重合），点E在边的延长线上，点F在边的延长线上，．点D在边上从B至C的运动过程 sketch template

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

已知 ABC是等边三角形以BC为直径的半圆O与边AB相交于点DDE⊥AC垂足为点E．1判断DE与⊙O的位置关系并证明你的结论2 sketch template

如图所示点P是等边三角形ABC内的一点且PA=6PB=8PC=10若将 PAC绕点A逆时针旋转后得到 P′AB则∠APB等于 sketch template

如图O是等边 ABC内一点OA=3OB=4OC=5将线段BO绕点B逆时针旋转60°得到线段BO′．1求点O与O′的距离2 sketch template

如图所示 ABC是等边三角形D点是AC的中点延长BC到E使CE=CD 1用尺规作图的方法过D点作DM⊥BE 垂足是M不 sketch template

如图， ABC是等边三角形，它的面积为1，延长BC至D，使BD=2BC，延长CA至E，使CE=3CA，延长AB至F，使AF=4AB，求 DEF sketch template

一个正方形和一个等边三角形的位置如图所示�放点G是BC中点正方形对角线EG⊥BC则∠AFE= A．10°B．15°C．20°D．25 sketch template

如图所示四个三角形均为等边三角形将图形折叠得到的立体图形是 A三棱锥 B 圆锥 C棱锥 D 六面体——青夏教育精英家教�—— sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

如图所示O是等边三角形ABC的中心D是三角形中的任意一点如果作矢量DADBDC分别表示三个力三个力的方�如图中箭头所示则这三个力 sketch template

如图所示在等腰梯形ABCD中AB∥CDAD=BCAC与BD交于点0∠AOB=60°PQR分别是OABCOD的中点．求证 sketch template

如图点O是等边 ABC内一点连接OAOBOC将 BOC绕点C按顺时针方�旋转60°得 ADC连接OD．1求证 COD是等边 sketch template

12．如图所示 ABC中AB=AC∠BAC=4∠BABAC的垂直平分线分别交BC于点DE．认真分析下列说法 � BAE和 CAD sketch template

如图所示已知边长为3的等边 ABC点F在边BC上CF=1点E是射线BA上一动点以线段EF为边�右侧作等边 EFG直线EGFG交 sketch template

如图所示P是等边 ABC内部一点∠APB∠BPC∠CPA的大小之比是5∶6∶7求以PAPBPC的长为边的三角形的三个角的大小之比 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

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