7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Sketch Coloring Page

7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Template

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tomski7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— coloring

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

如图在 ABC中点DEF分别在边ABACBC上且DE∥BCEF∥AB若AD＝2BD则的值为 A B C D sketch template

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

如图在 ABC中点DEF分别是边BCCAAB的中点使四边形AFDE为菱形应添加的条件是AF=AE．题目和参考答案——青夏教育 sketch template

如图在正方形ABCD中点EF分别是ADBC中点连接EF将矩形CDEF绕着点C逆时针旋转一定角度得到矩形CD′E′F′点E′恰好落 sketch template

题目如图已知正方形ABCD的边长为6EF分别是ABBC边上的点且∠EDF=45°将 DAE绕点D逆时针旋转90°得到 DCM sketch template

【问题情境�（1）如图1，正方形ABCD中，E、F分别是边AB和对角线AC上的点，∠EDF=45°．易证 DBE∽ DCF（不需写出证明过程 sketch template

平面几何定理及证明（1）知乎 sketch template

百度教育 sketch template

如图 ABC中点DEF分别在边BCABCA上且DE∥CADF∥BA则�如果∠BAC=90°那么四边形AEDF是矩形�如果 sketch template

如图在 ABC中点DE分别在边ABAC上如果DE∥BC且∠DCE=∠B那么下列说法中错误的是 A． ADE∽ ABC B sketch template

如图1，D、E、F分别是 ABC各边上的点，四边形ADEF是平行四边形，有三个选项：�D是AB的中点，�E是BC的中点，�F是AC的中点． sketch template

题目如图矩形ABCD中AD=5AB=7点E为DC上一个动点把 ADE沿AE折叠当点D的对应点D′落在∠ABC的角平分线上时DE sketch template

如图，AB为⊙O的直径，C、D为⊙O上的两点，且AC平分∠BAD，过点C作直线EF⊥AD，交AD的延长线于点E． sketch template

如图1在 ABC中DEF分别为三边的中点G点在边AB上 BDG与四边形ACDG的�长相等设BC=aAC=bAB=c．1求 sketch template

在 ABC中已知∠A=60°∠C=75°AB=10点DEF分别在边ABBCCA上则 DEF�长的最小值．题目和参考答案 sketch template

如图在 ABC中点DEF分别在BCABAC上且DE∥ACDF∥AB．1如果∠BAC=90°那么四边形AEDF是 形2 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

如图在 ABC中∠A=90°AB=ACD 是BC的中点点EF分别是ABAC上的点并且BE=AF1猜想并写出AD与BC所满足 sketch template

如图已知长方体ABCD A1B1C1D1中AB=BC=2AA1=1点EF分别是A1B1B1C1的中点点O是AB与BD的交点．1 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

题目1如图1在四边形ABCD中AB=AD∠BAD=120°∠B=∠ADC=90°．EF分别是BCCD上的点．且∠EAF sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

7．如图四边形ABCD中P为AC对角线上一点PE∥BC交 AB于点EPF∥AB交AD于点F若S=20cm2 则图中阴影部分 的 sketch template

如图�，已知 ABC的内切圆⊙O与AB、BC、AC分别相切于点D、E、F，且EF=DE（1）判断 ABC的形状，并证明你的结论；（2 sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

如图 ABC∽ A′BC′ADA′D′分别是这两个三角形的高EFE′F′分别是这两个三角形的中位线ADA′D′与EFE′F′相等吗 sketch template

百度教育 sketch template

如图在 ABC中∠A=90°AB=ACD 是BC的中点点EF分别是ABAC上的点并且BE=AF1猜想并写出AD与BC所满足 sketch template

如图在 ABC中∠C=90°AC=BC点D为AB的中点点EF分别为ACBC边上的动点且CE=BF当点EF分别在边ACBC sketch template

在三棱锥P ABC中PA⊥平面ABC∠BAC=90°DEF分别是棱ABBCCP的中点AB=AC=1PA=2则直线PA与平面 sketch template

如图在等边 ABC 中DEF分别为ABBCCA上一点且AD=BE=CF若每三个三角形两两全等为一组则图中全等的三角形组数为 sketch template

已知在 ABC中内切圆I和边BCCAAB分别相切于点DEF．1若∠A=60°求∠FDE的度数2若∠A=130°求∠ sketch template

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