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7．鹰类的下列性状分别由位于两对常染色体上的两对等位基因控制其中有一对基因具有显性纯合致死效应显性纯合子在胚胎期死亡已知绿色无纹鹰与 Template






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tomski7．鹰类的下列性状分别由位于两对常染色体上的两对等位基因控制其中有一对基因具有显性纯合致死效应显性纯合子在胚胎期死亡已知绿色无纹鹰与 coloring
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7．鹰类的下列性状分别由位于两对常染色体上的两对等位基因控制其中有一对基因具有显性纯合致死效应显性纯合子在胚胎期死亡已知绿色无纹鹰与 sketch template
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人类每条染色体上都有很多基因下图表示1号染色体上的几种基因对性状的控制及基因在染色体上的分布位置若不考染色体交叉互换据此不能得出的结论 sketch template
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雕鸮的下列性状分别由位于两对常染色体上的两对等位基因控制分别用Aa和Bb表示其中有一对基因具有纯合致死效应巳知绿色条蚊雕鸮与黄色无纹 sketch template
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某种鸟类体色条纹的有无是两对独立遗传的相对性状下表是三组相关杂交试验情况请分析后回答问题 1根据 组杂交试验的结果可判定这两对 sketch template
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右图是一个人类白化病遗传的家族系谱6号和7号为同卵双生即由同一个受精卵育两个个体8号和9号为异卵双生即由两个受精卵分别育而成的两个 sketch template
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人类有耳垂由显性基因A控制无耳垂由隐性基因a控制根据所示的遗传图解分析回答问题1父亲的基因组成是 ．2就控制耳垂性状的 sketch template
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右图是一个人类白化病遗传的家族系谱6号和7号为同卵双生即由同一个受精卵育两个个体8号和9号为异卵双生即由两个受精卵分别育而成的两个 sketch template
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果蝇的裂翅与非裂翅为一对相对性状相关基因用Aa表示位于3号常染色体直毛与分叉毛为一对相对性状．为培育果蝇新品系研究人进行如图杂交 sketch template
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题目下图表示一对色雄雌豚鼠交配产下的后代的遗传图据图回答下列问题 1在遗传学上豚鼠的色和棕色是一对2豚鼠的毛色性状是 sketch template
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题目I果蝇是遗传学研究常用的生物材料请回答下列有关果蝇遗传试验的问题已知果蝇黄身和身为一对相对性状控制该性状的基因位于常染色体上 sketch template
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2018·全国卷Ⅲ某小组利用某二倍体自花传粉植物进行两组杂交实验杂交涉及的四对相对性状分别是红果红与黄果黄、子房二室二与多 sketch template
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5．下图是几种常见的动物有的还是人类的好朋友请你仔细观察图中动物回答下列问题 1A类与B类结构相同之处是身体都是由 构成的 2 sketch template
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小鼠的长尾与短尾是一对相对性状色与褐色为另一对相对性状其中一对等位基因位于常染色体上另一对等位基因位于X染色体上多只基因型相同的褐色 sketch template
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下列叙述中肯定为显性性状的是 A子代所表现出来的性状 B具有相对性状的纯合子杂交F1所表现出来的性状 C杂合子自交后代出现新的性状 sketch template
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题目如图为整理后的某对夫妇体细胞染色体排序图请回答下列问题1从染色体组成来看表示男性染色体的是 图2染色体的主要组成物质是 sketch template
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下列性状中属于相对性状的是 A．玉米的高茎和水稻的矮茎B．兔的长毛和黄毛C．人的色觉正常和色盲D．豌豆的高茎和开白花——青夏教育精英家教—— sketch template
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题目果蝇的灰身与身为一对相对性状直毛与分叉毛为一对相对性状．现有两只亲代果蝇杂交F1的表现型与比例如图所示．请回答下列问题 1 sketch template
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下图中甲乙表示水稻两个品种Aa和Bb表示分别位于两对同源染色体上的两对等位基因 表示培育水稻新品种的过程则下列说法错误是 A sketch template
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一种鹰的羽毛黄色和绿色条纹和非条纹的差异均由基因决定两对基因分别用A表示已知决定颜色的显性基因纯合子不能存活下图显示了鹰羽毛的杂交遗传 sketch template
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用纯合子果蝇作为亲本研究两对相对性状的遗传实验结果如表所示下列说法不正确的是PF1♀灰身红眼×♂身白眼♀灰身红眼♂灰身红眼♀身 sketch template
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果蝇的灰身和身刚毛和截毛为两对相对性状分别受基因Aa和Dd控制研小组用一对表现型都是灰身刚毛的雌雄果蝇进行杂交试验现其结果与 sketch template
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题目孟德尔用高茎豌豆和矮茎豌豆进行杂交所得种子长成的子一代植株都是高茎的下列叙述正确的是 A 豌豆的高茎和矮茎是一对相对性状B sketch template
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某种野生植物有紫花和白花两种表现型已知紫花形成的生物化学途径如图中A和aB和b是分别位于两对染色体上的等位基因A对aB对b为显性．基因 sketch template
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人的双眼皮和单眼皮是一对相对性状分别由显性基因D和隐性基因d控制．已知一对夫妇均是双眼皮他们的女儿是单眼皮则父亲和女儿的基因组成分别是 sketch template
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题目已知某种植物籽粒的红色和白色为一对相对性状这一对相对性状受多对等位基因控制某研究小组将若干个籽粒红色与白色的纯合亲本杂交结果如图 sketch template
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某家系中有甲乙两种单基因遗传病如图一其中甲性状由Aa乙性状由Bb基因控制甲病在人群中患病纯合体约占110000图二为人类性 sketch template
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教材中孟德尔研究的黄绿和圆皱两对相对性状的杂交遗传实验叙述错误的是 A．每一对相对性状的遗传都遵循基因的分离定律 B．每一对相对性状在子二代 sketch template
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题目如图是人类的性别决定图解据图回答问题1人类的性别是由染色体决定的在人体细胞的23对染色体中22对与性别决定无关叫做 sketch template
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人类皮肤正常是由显性基因A控制白化病是由隐性基因a控制根据图4的遗传图解分析下列问题1人类肤色的正常和白化在遗传学上称为相对 sketch template
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在生物的遗传过程中由于某些原因总会出现与孟德尔遗传规律不一致的现象．请回答下列相关问题1某种鸟类体色条纹的有无是两对独立遗传的相对 sketch template
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苜蓿种子的子叶黄色与褐色为一对相对性状分别由基因 Yy 控制圆粒与肾粒为一对相对性状分别由基因 Rr 控制．某研小组进行遗传实验时 sketch template
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如图为人类某种遗传病的家族系谱图6号和7号为同卵双生即由同一个受精卵育而成的两个个体8号和9号为异卵双生即两个受精卵分别育成的个体 sketch template
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为研究豌豆的高茎与矮茎花的顶生与腋生两对性状的遗传进行了两组纯种豌豆杂交实验如图所示据图分析下列说法正确的是 A．两对性状分别 sketch template