21．如图a所示abcd是位于竖直平面内的正方形闭合�属线框在�属线框的下方有一匀强磁场区域 mn和m′n′是匀强磁场区域的水平边界并 Sketch Coloring Page

21．如图a所示abcd是位于竖直平面内的正方形闭合�属线框在�属线框的下方有一匀强磁场区域 mn和m′n′是匀强磁场区域的水平边界并 Template

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tomski21．如图a所示abcd是位于竖直平面内的正方形闭合�属线框在�属线框的下方有一匀强磁场区域 mn和m′n′是匀强磁场区域的水平边界并 coloring

21．如图a所示abcd是位于竖直平面内的正方形闭合�属线框在�属线框的下方有一匀强磁场区域 MN和M′N′是匀强磁场区域的水平边界并 sketch template

21．如图a所示abcd是位于竖直平面内的正方形闭合�属线框在�属线框的下方有一匀强磁场区域 MN和M′N′是匀强磁场区域的水平边界并 sketch template

如图所示矩形单匝导线框abcd竖直放置其下方有一磁感应强度为B的匀强磁场区域该区域的上边界水平并与线框的ad边平行磁场方�与线框平面 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图1所示矩形导线框ABCD固定在匀强磁场中磁感线垂直于线框所在平面�里规定垂直于线框所在平面�里为磁场的正方�线框中沿着ABCDA sketch template

21．如图甲所示正方形�属线框abcd边长L=25m质量m=05kg各边电阻均为1Ω其水平放置在光�绝缘的水平面上它的ab边与 sketch template

如图所示正方体ABCD A1B1C1D1中E是C1C的中点则BE与平面B1BD所成角的余弦值为题目和参考答案——青夏教育精英家教�—— sketch template

如图所示闭合�属线圈abcd位于水平方�匀强磁场的上方h处由静止开始下落再进入磁场在运动过程中线圈平面始终和磁场方�垂直不计空气 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图1所示abcd是位于竖直平面内的正方形闭合�属线框其质量为m电阻为R．在�属线框的下方有一匀强磁场区域PQ和PQ是该匀强磁场 sketch template

如图所示是等腰直角三棱柱其中底面ABCD为正方形边长为L它们按图示位置放置处于竖直�下的匀强磁场中磁感应强度为B．则下列说法正确的是 sketch template

如图所示竖直面内的正方形导线框ABCDabcd的边长均为l总电阻均为R质量分别为2m和m它们分别系在一跨过两个定�轮的轻绳两端在两 sketch template

一轮复习：有关安培力的立体图转平面图 知乎 sketch template

如图所示，矩形平板ABCD的AD边固定在水平面上，平板与水平面夹角为θ，AC与AB的夹角也为θ。质量为m的物块在平行于平板的拉力作用下，沿AC sketch template

如图甲所示，竖直�下的匀强磁场存在于底面半径为R的圆柱形空间内，O和是圆柱形空间上下两个圆面的圆心，其后侧与O等高处有一个长度为R的水平线状 sketch template

如图所示正方形abcd区域内有垂直于纸面�里的匀强磁场O点是cd边的中点一个带正电的粒子若从O点沿纸面以垂直于cd边的速度射入正方形内 sketch template

如图所示正方体ABCD A1B1C1D1中E是C1C的中点则BE与平面B1BD所成角的余弦值为题目和参考答案——青夏教育精英家教�—— sketch template

如图所示abcd为一边长为l的正方形导线框导线框位于光�水平面内其右侧为一匀强磁场区域磁场的边界与线框的cd边平行磁场区域的宽度为 sketch template

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长为 ——青夏教育 sketch template

1如图甲所示请在图中用箭头标出两N极间磁感线的方�．2如乙图所示ABCD是一间不透光的房间墙AB是平面镜房中S处有一个正在�光 sketch template

如图所示在正方体ABCD A1B1C1D1中棱长为aMN分别为A1B和AC上的点A1M=AN=则MN与平面BB1C1C的位置关系是 sketch template

如图所示正方形导线框abcd的质量为m边长为l导线框的总电阻为R．导线框从垂直纸面�里的水平有界匀强磁场的上方某处由静止自由下落下落 sketch template

10．如图所示线圈abcd可以自由转动线圈ABCD固定不动两线圈平面垂直放置而且圆心重合当两线圈中通入图示方�的电流时线圈abcd的 sketch template

10．如图4所示正方形ABCD的对角线相交于点O点E是BC上任意一点EG⊥BD 于GEF⊥AC于F若AC=10则EG EF的值为 sketch template

21． 如图正方体ABCD A1B1C1D1的棱长为1 M是棱AB的中点． Ⅰ求CD与平面AC D1所成的角 Ⅱ求证平面B1C sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图所示边长L=02m的正方形线圈abcd其匝数n=10总电阻r=2Ω外电路的电阻R=8Ωab边的中点和cd边的中点的连线OO sketch template

21．如图甲所示正方形�属线框abcd边长L=25m质量m=05kg各边电阻均为1Ω其水平放置在光�绝缘的水平面上它的ab边与 sketch template

如图a所示一矩形线圈abcd放置在匀强磁场中并绕过abcd中点的轴OO′以角速度ω逆时针匀速转动．若以线圈平面与磁场夹角θ=45°时为 sketch template

12．如图所示在四棱锥P ABCD中底面ABCD是矩形PA＝AB＝2BC＝a又侧棱PA⊥底面ABCD 1当a为何值时BD⊥ sketch template

如图所示的几何体从上面看所得到的图形是 A．B．C．D．——青夏教育精英家教�—— sketch template

如图所示四棱锥P ABCD的底面ABCD为直角梯形且AD∥BCAD⊥ABE是PC的中点PA=BC=2AD=1AB=2∠PAB sketch template

19．如图所示abcd是倾角为θ的光�斜面已知ab//dcadbc均与ab垂直在斜面上的a点将甲球以速度v0沿ab方�射入的同时在 sketch template

如图所示，凸四边形ABCD中，对角线AC、BD相交于0点．若三角形AOD的面积是2，三角形COD的面积是1，三角形COB的面积是4，则四边形 sketch template

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