19．如图所示四棱锥p Abcd的底面为直角梯形⊥平面e为ab中点 1求证平面⊥平面 2求直线与平面所成角的正弦值 Sketch Coloring Page

19．如图所示四棱锥p Abcd的底面为直角梯形⊥平面e为ab中点 1求证平面⊥平面 2求直线与平面所成角的正弦值 Template

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tomski19．如图所示四棱锥p abcd的底面为直角梯形⊥平面e为ab中点 1求证平面⊥平面 coloring

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

如图在四棱锥P—ABCD中PA⊥底面ABCDAB⊥ADAC⊥CD∠ABC=60°PA=AB=BCE是PC的中点1证明AE sketch template

如图所示，四棱锥的底面是正方形，每条侧棱的长都是底 高途 sketch template

如图所示，四棱锥的底面是正方形，每条侧棱的长都是底 高途 sketch template

$如图所示四棱锥P ABCD中PA⊥平面ABCDPB与底面所成的角为$frac{π}{4}$底面ABCD为直角梯形∠ABC=∠BAD sketch template$

如图所示四棱锥P ABCD的底面ABCD是边长为a的正方形侧棱PA=a PB=PD=a则它的5个面中互相垂直的面有对——青夏教育 sketch template

百度教育 sketch template

如图在四棱锥P ABCD中侧面底面ABCD底面ABCD是菱形侧面PAD是等边三角形且PB与面PAD所成角为1求四棱锥P sketch template

19．如图在四棱锥P ABCD中底面ABCD是矩形MN分别为PABC的中点 PD⊥平面ABCD且PD=AD=CD=1 1 sketch template

19． 如图四棱锥P ABCD的底面ABCD是边长为2的菱形点M 是棱PC的中点N是棱PB的中点平面ABCDACBD交于点O sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

19．如图所示四棱锥P ABCD的底面为直角梯形⊥平面E为AB中点 1求证平面⊥平面 2求直线与平面所成角的正弦值 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

百度教育 sketch template

19．如图在四棱锥P ABCD中底面ABCD是矩形MN分别为PABC的中点 PD⊥平面ABCD且PD=AD=CD=1 1 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图所示的四棱锥中，平面，，．高途 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

如图所示，四棱锥的底面为矩阵，其中一条棱垂直于底面，那么该四棱锥的俯视图最有可能是：【2025广东0 星光公考公务�考试公考 2025 sketch template

19．如图所示四棱锥P ABCD的底面为直角梯形⊥平面E为AB中点 1求证平面⊥平面 2求直线与平面所成角的正弦值 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示在四棱锥P ABCD中底面ABCD为菱形且∠DAB=60°PA=PDM为CD的中点BD⊥PM．1求证平面PAD⊥平面 sketch template

如图四棱锥P ABCD中PD⊥平面ABCD底面ABCD是正方形PD=AB=2E为PC中点．1求证DE⊥平面PCB2求点C sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示，底面边长为的正四棱锥被平行于其底面的平面 高途 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图在长方体ABCD A1B1C1D1中已知AB=4AD=3AA1=2E是线段AB上的点且EB=1则二面角C DE C1的正切值 sketch template

百度教育 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

高中数学人教版必修2配套练习：232平面与平面垂直的判定含答案 Word文档在线阅读与下载无忧文档 sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

百度教育 sketch template

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