16．若棱长为1的正八面体的六个顶点均在某个球的球面上则这个球的体积为 ——青夏教育精英家教�—— Sketch Coloring Page

16．若棱长为1的正八面体的六个顶点均在某个球的球面上则这个球的体积为 ——青夏教育精英家教�—— Template

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tomski16．若棱长为1的正八面体的六个顶点均在某个球的球面上则这个球的体积为 ——青夏教育精英家教�—— coloring

16．若棱长为1的正八面体的六个顶点均在某个球的球面上则这个球的体积为 ——青夏教育精英家教�—— sketch template

把球面划分成全等的球面多边形，有多�个（族）不同的方法？知乎 sketch template

正多面体 360百� sketch template

有一个棱长为1的正方体，按任意方�正投影，其投影面积的最大值是 A．1 百度教育 sketch template

将棱长为1的正方体的六个面的中点相连接可以得到一个八面体，则这个八面体的体积为：星光公考公务�考试公考 2025国家公务�考试 sketch template

已知正三棱锥P－ABC的底面边长为6，其内切球的半径为1，则此三棱锥的高为． sketch template

对于一个多面体来说欧拉公式是指 A顶点数 棱数 面数=2 B顶点数 面数 棱数=2 C棱数 顶点数=2 D不同于 sketch template

百度教育 sketch template

已知正八面体的棱长为a． 1求相邻两面中心的距离； 2求两个相对面之间的距离．百度教育 sketch template

如图平行六面体ABCD A1B1C1D1中底面ABCD是边长为1的正方形AA1=2设AB=aAD=bAA1=c1试用abc sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

18．已知棱长为1的正方体AC1EF分别是B1C1C1D的中点． 1求证EFDB共面 2求点A1到平面的BDEF的距离 sketch template

如图已知正方体棱长为2点是正方形的中心点分别是棱的中点．设点分别是点在平面内的正投影． Ⅰ求以为顶点以四边形在平面内的正投影为 sketch template

如图已知正方体ABCD A1B1C1D1的棱长为1EF分别在棱ABBC上G在对角线BD1上且AE＝BF＝D1G∶GB＝1∶2 sketch template

已知菱形的边长为2，将沿折起，使得点至点的位置，得到四面体当二面角的大小为120°时，四面体的体积为；当四面体的体积为1时，以为球心，的长 sketch template

初学讲义之高中数学二十：简单几何体 知乎 sketch template

本题满分12分如图在正四棱台中上底面边长为1下底面边长为3侧棱长为21求此正四棱台的侧面积2求此正四棱台的体积 百度教育 sketch template

百度教育 sketch template

5．棱柱 1掌握棱柱的定义分类理解直棱柱正棱柱的性质 2掌握长方体的对角线的性质 3平行六面体→直平行六面体→长方体→正 sketch template

如图已知平行六面体ABCD A1B1C1D1的底面为正方形O1O分别为上下底面的中心且A1在底面ABCD上的射影是O．1求证面 sketch template

7．如图正四面体的棱长均为且平面于A点BCD均在平面外且在平面同一侧则点B到平面的距离是 A． B． C． D．——青夏教育精英 sketch template

21．如图正方体ABCD A1B1C1D1的棱长为1 M是棱AB的中点． Ⅰ求CD与平面AC D1所成的角 Ⅱ求证平面B1C sketch template

正六棱柱底面是正六边形侧棱垂直底面ABCDEF A1B1C1D1E1F1的各棱长均为1求1正六棱柱的表面积2一动点从A沿 sketch template

正方体ABCD A1B1C1D1的棱长为1E是CD中点F是BB1中点则四面体AD1EF的体积是．——青夏教育精英家教�—— sketch template

一个棱长为1的正方体截去一个正棱锥形状的角剩余几何体的体积最小可能是 A． B． C． D．不能确定——青夏教育精英家教�—— sketch template

已知平行六面体ABCD A1B1C1D1中底面ABCD是边长为1的正方形．AA1=2∠A1AB=∠A1AD=120°．1求线段AC1的 sketch template

在棱长为a的正四面体中，相对两条棱间的距离为 百度教育 sketch template

棱长均为1的正四面体的表面积是 A．3B．23C．33D．43 题目和参考答案——青夏教育精英家教�—— sketch template

百度教育 sketch template

棱长 360百� sketch template

如图所示在一个木制的棱长为3的正方体表面涂上颜色将它的棱三等分然后从每个等分点把正方体锯开得到27棱长为1的小正方体将这些小正方体 sketch template

如图在直三棱锥ABC A1B1C1中AC=BC=AA1∠ACB=90°EF分别是ABBC的中点G是AA1上的点若一个三棱锥的三 sketch template

设四面体的各条棱长都为1若该四面体的各个顶点都在同一个球面上求该球的表面积．题目和参考答案——青夏教育精英家教�—— sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

求棱长为a的正四面体的外接球与内切球的半径．题目和参考答案——青夏教育精英家教�—— sketch template

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