16．如图已知d e分别是 Abc的边bc和边ac的中点连接dead若s=24cm求 Dec的面积——青夏教育精英家教�—— Sketch Coloring Page

16．如图已知d e分别是 Abc的边bc和边ac的中点连接dead若s=24cm求 Dec的面积——青夏教育精英家教�—— Template

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tomski16．如图已知d e分别是 abc的边bc和边ac的中点连接dead若s=24cm求 coloring

16．如图已知D E分别是 ABC的边BC和边AC的中点连接DEAD若S=24cm求 DEC的面积——青夏教育精英家教�—— sketch template

如图已知 ABC中AB=ACM是BC的中点DE分别是ABAC边上的点且BD=CE1求证MD=ME．2若D为AB的 sketch template

如图已知DE分别是 ABC的ABAC边上的点且 ABC∽ ADEADDB=13DE=2求BC的长．题目和参考答案——青夏 sketch template

6．如图已知DE分别是 ABC的ABAC边上一点DE//BC且那么ADAB等于 A．1 B．18 C．19——青夏 sketch template

如图，图中所有的三角形都是直角三角形，四边形都是正方形．已知正方形A，B，C，D的边长分别是12，16，9，12，求最大正方形E的面积．百度教育 sketch template

6．如图已知ΔABC和ΔABD都是⊙O的内接三角形AC和BD相交于点E则与ΔADE相似的三角形是 A．ΔBCE B．ΔABC C sketch template

如图已知D是 ABC的BC边的中点DE⊥ACDF⊥AB垂足分别为EF且DF=DE则 ABC是等腰三角形吗请说明理由．——青夏 sketch template

26．如图已知 ABC中DE分别是ACAB上的点BD与CE相交于点O给出下列三个条件 �∠EBO=∠DCO �∠BEO=∠CDO sketch template

6．如图已知DE分别是 ABC的ABAC边上一点DE//BC且那么ADAB等于 A．1 B．18 C．19——青夏 sketch template

题目如图已知正方形DEFG的顶点DE在 ABC的边BC上顶点GF分别在边ABAC上．如果BC=4 ABC的面积是6那么这个正 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

4．如图1已知DE是 ABC中边上的两点AB＝AC请你再加一个条件使 ABE≌ ACD．——青夏教育精英家教�—— sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图，已知⊙0是 ABC的外接圆，半径长为5，点D、E分别是边AB和边AC是中点，AB=AC，BC=6．求∠OED的正切值．百度教育 sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

百度教育 sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

如图，已知D，E分别是 ABC的边AC，BC上的点，平面α经过D，E两点． 1作直线AB与平面α的交点P； 2求证：D，E，P三点共线 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

如图以 ABC的边AB为直径作⊙O交BC于D过D作⊙O的切线交AC于E要使得DE⊥AC则 ABC的边必须满足的条件是 ．题目和参考 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图D是 ABC的边BC上任意一点EF分别是线段ADCE的中点且 ABC的面积为40cm2则 BEF的面积是 Cm2．A．5B sketch template

如图，在 ABC中，AD、BE分别是边BC、AC上的中线，AD与BE交于点O，点F、G分别是BO、AO的中点，联结DE、EG、GF、FD．（1 sketch template

如图在 ABC中∠BAC=∠B=60°AB=AC点DE分别是边BCAB所在直线上的动点且BD=AEAD与BC交于点F．1当 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图已知C是AB的中点D是AC的中点E是BC的中点 1若AB=18cm求DE的长2若CE=5cm求DB的长——青夏 sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

如图在半径为2的扇形AOB中∠AOB=90°点C是弧AB上的一个动点OD⊥BCOE⊥AC垂足分别为DE．1当BC=1时求线段 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

百度教育 sketch template

$如图三棱柱ABC A1B1C1中平面ABB1A1⊥平面ABC ABC为等边三角形AB=$frac{1}{2}$AA1=1∠A1AB sketch template$

如图⊙O为 ABC的内切圆切点分别为MNP．AB=8BC=9CA=10点DE分别为ABAC上的点且DE为⊙O的切线求 sketch template

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